Sql 实际上,这也是我最后推导出的矩阵。我用它来计算一个月的工作日数,并根据2016-2020年进行了验证。此字符串产生正确的结果,答案和注释中其他地方提到的字符串是错误的。它基于@Bryan Geraghty的解决方案,因此此解决方案的输出与Excel的NET

Sql 实际上,这也是我最后推导出的矩阵。我用它来计算一个月的工作日数,并根据2016-2020年进行了验证。此字符串产生正确的结果,答案和注释中其他地方提到的字符串是错误的。它基于@Bryan Geraghty的解决方案,因此此解决方案的输出与Excel的NET,sql,mysql,Sql,Mysql,实际上,这也是我最后推导出的矩阵。我用它来计算一个月的工作日数,并根据2016-2020年进行了验证。此字符串产生正确的结果,答案和注释中其他地方提到的字符串是错误的。它基于@Bryan Geraghty的解决方案,因此此解决方案的输出与Excel的NETWORKDAYS不兼容。DATEDIFF(LAST_DAY(?))+1)是否始终是DAY(LAST_DAY(?)简单且功能正常。这是不正确的。datediff需要+1。还有第三部分,如果开始日期是星期三,结束日期是星期天,那么你已经添加了它们,


实际上,这也是我最后推导出的矩阵。我用它来计算一个月的工作日数,并根据2016-2020年进行了验证。此字符串产生正确的结果,答案和注释中其他地方提到的字符串是错误的。它基于@Bryan Geraghty的解决方案,因此此解决方案的输出与Excel的NETWORKDAYS不兼容。DATEDIFF(LAST_DAY(?))+1)是否始终是DAY(LAST_DAY(?)简单且功能正常。这是不正确的。datediff需要+1。还有第三部分,如果开始日期是星期三,结束日期是星期天,那么你已经添加了它们,你仍然有周末在里面。我会发布更详细的解决方案。很抱歉,我无法分析此问题。你是说你有3个不同的输入,开始日期和结束日期?我以为你在计算起点和终点之间的差异?
DECLARE @StartDate DATETIME,
        @EndDate DATETIME

SELECT  @StartDate = '22 Nov 2009',
        @EndDate = '28 Nov 2009'

;WITH CTE AS(
        SELECT  @StartDate DateVal,
                DATENAME(dw, @StartDate) DayNameVal
        UNION ALL
        SELECT  DateVal + 1,
                DATENAME(dw, DateVal + 1)
        FROM    CTE
        WHERE   DateVal < @EndDate
)
SELECT  COUNT(1)
FROM    (
            SELECT *
            FROM CTE
            WHERE DayNameVal NOT IN ('Sunday','Saturday')
        ) DayVals
CREATE TABLE Calendar
(
     calendar_date     DATETIME     NOT NULL,
     is_holiday        BIT          NOT NULL,
     is_weekend        BIT          NOT NULL,
     CONSTRAINT PK_Calendar PRIMARY KEY CLUSTERED (calendar_date)
)
SELECT
     COUNT(*)
FROM
     Calendar
WHERE
     calendar_date BETWEEN '2009-01-01' AND '2009-10-01' AND
     is_holiday = 0 AND
     is_weekend = 0
DELIMITER $$

DROP FUNCTION IF EXISTS `catalog`.`WORKDAYS` $$
CREATE FUNCTION `catalog`.`WORKDAYS` (first_date DATETIME, second_date DATETIME) RETURNS INT
LANGUAGE SQL
DETERMINISTIC

BEGIN

  DECLARE start_date DATE;
  DECLARE end_date DATE;
  DECLARE diff INT;

  IF (first_date < second_date) THEN
    SET start_date = first_date;
    SET end_date = second_date;
  ELSE
    SET start_date = second_date;
    SET end_date = first_date;
  END IF;

  SET diff = DATEDIFF(end_date, start_date);

  RETURN (CASE WHEN DAYNAME(start_date) not in ('Saturday', 'Sunday') && DAYNAME(end_date) = 'Saturday' THEN diff
               WHEN DAYNAME(start_date) not in ('Saturday', 'Sunday') && DAYNAME(end_date) = 'Sunday' THEN (diff - 2)

               WHEN DAYNAME(start_date) = 'Saturday' && DAYNAME(end_date) = 'Sunday' THEN (diff - 1)
               WHEN DAYNAME(start_date) = 'Saturday' && DAYNAME(end_date) = 'Saturday' THEN (diff + 1)
               WHEN DAYNAME(start_date) = 'Sunday' && DAYNAME(end_date) in ('Saturday', 'Sunday') THEN (diff + 1)

               WHEN DAYNAME(start_date) = 'Saturday' && DAYNAME(end_date) not in ('Saturday', 'Sunday') THEN (diff -1)
               WHEN DAYNAME(start_date) = 'Sunday' && DAYNAME(end_date) not in ('Saturday', 'Sunday') THEN (diff + 1)

               WHEN DAYNAME(start_date) not in ('Saturday', 'Sunday') && DAYNAME(end_date) not in ('Saturday', 'Sunday')
                    && WEEKDAY(start_date) > WEEKDAY(end_date) THEN (diff - 2)
               ELSE diff END)
    - (FLOOR(diff / 7) * 2)
    - (CASE WHEN DAYNAME(start_date) = 'Sunday' THEN 1 ELSE 0 END)
    - (CASE WHEN DAYNAME(end_date) = 'Saturday' THEN 1 ELSE 0 END);

END $$

DELIMITER ;
SELECT

   @tmp_s   := ept.`date_start`,
   @tmp_e   := IF(ept.`date_end` IS NULL, NOW(),ept.`date_end`),
   @start   := IF(DAYOFWEEK(@tmp_s)=1,@tmp_s + INTERVAL 1 DAY,(IF(DAYOFWEEK(@tmp_s)=7,@tmp_s + INTERVAL 2 DAY,@tmp_s)),
   @end     := IF(DAYOFWEEK(@tmp_e)=1,@tmp_e - INTERVAL 2 DAY,(IF(DAYOFWEEK(@tmp_e)=7,@tmp_e - INTERVAL 1 DAY,@tmp_e)),
   @bizdays := CASE
                  WHEN DATEDIFF(@end,@start)>7 THEN CEIL((DATEDIFF(@end,@start)/7)*5)
                  WHEN DAYOFWEEK(@end)< DAYOFWEEK(@start) THEN DATEDIFF(@end,@start)-2
                  ELSE DATEDIFF(@end,@start)
               END,
   DATE(@start),
   DATE(@end),
   IF(@bizdays>=10,10,@bizdays)

FROM `employee_points` ept
WHERE ept.`date_start` > '2011-01-01'
SELECT (DATEDIFF(LAST_DAY(?),?) + 1) - 
    ((WEEK(LAST_DAY(?)) - WEEK(?)) * 2) -
    (case when weekday(?) = 6 then 1 else 0 end) - 
    (case when weekday(LAST_DAY(?)) = 5 then 1 else 0 end)
5 * (DATEDIFF(@E, @S) DIV 7) + MID('0123444401233334012222340111123400012345001234550', 7 * WEEKDAY(@S) + WEEKDAY(@E) + 1, 1)
 | M T W T F S S
-|--------------
M| 0 1 2 3 4 4 4
T| 4 0 1 2 3 3 3
W| 3 4 0 1 2 2 2
T| 2 3 4 0 1 1 1
F| 1 2 3 4 0 0 0
S| 1 2 3 4 5 0 0
S| 1 2 3 4 5 5 0
 | M T W T F S S
-|--------------
M| 0 1 2 3 4 4 4
T| 4 0 1 2 3 3 3
W| 3 4 0 1 2 2 2
T| 2 3 4 0 1 1 1
F| 1 2 3 4 0 0 0
S| 0 1 2 3 4 0 0
S| 0 1 2 3 4 4 0
5 * (DATEDIFF(@E, @S) DIV 7) + MID('0123444401233334012222340111123400001234000123440', 7 * WEEKDAY(@S) + WEEKDAY(@E) + 1, 1)
 | M T W T F S S
-|--------------
M| 0 1 2 3 4 5 5
T| 5 0 1 2 3 4 4
W| 4 5 0 1 2 3 3
T| 3 4 5 0 1 2 2
F| 2 3 4 5 0 1 1
S| 0 1 2 3 4 0 0
S| 0 1 2 3 4 5 0
0123455501234445012333450122234501101234000123450
5 * (DATEDIFF(@E, @S) DIV 7) + MID('0123455501234445012333450122234501101234000123450', 7 * WEEKDAY(@S) + WEEKDAY(@E) + 1, 1)
Sunday, 2012-08-26 -> Monday, 2012-08-27 = 0
Sunday, 2012-08-26 -> Sunday, 2012-09-02 = 5
Monday, 2012-08-27 -> Tuesday, 2012-08-28 = 1
Monday, 2012-08-27 -> Monday, 2012-09-10 = 10
Monday, 2012-08-27 -> Monday, 2012-09-17 = 15
Monday, 2012-08-27 -> Tuesday, 2012-09-18 = 16
Monday, 2012-08-27 -> Monday, 2012-09-24 = 20
Monday, 2012-08-27 -> Monday, 2012-10-01 = 25
Tuesday, 2012-08-28 -> Wednesday, 2012-08-29 = 1
Wednesday, 2012-08-29 -> Thursday, 2012-08-30 = 1
Thursday, 2012-08-30 -> Friday, 2012-08-31 = 1
Friday, 2012-08-31 -> Saturday, 2012-09-01 = 1
Saturday, 2012-09-01 -> Sunday, 2012-09-02 = 0
Sunday, 2012-09-02 -> Monday, 2012-09-03 = 0
Monday, 2012-09-03 -> Tuesday, 2012-09-04 = 1
Tuesday, 2012-09-04 -> Wednesday, 2012-09-05 = 1
Wednesday, 2012-09-05 -> Thursday, 2012-09-06 = 1
Thursday, 2012-09-06 -> Friday, 2012-09-07 = 1
Friday, 2012-09-07 -> Saturday, 2012-09-08 = 1
Saturday, 2012-09-08 -> Sunday, 2012-09-09 = 0
Monday, 2012-09-24 -> Sunday, 2012-10-07 = 10
Saturday, 2012-08-25 -> Saturday, 2012-08-25 = 0
Saturday, 2012-08-25 -> Sunday, 2012-08-26 = 0
Saturday, 2012-08-25 -> Monday, 2012-08-27 = 0
Saturday, 2012-08-25 -> Tuesday, 2012-08-28 = 1
Saturday, 2012-08-25 -> Wednesday, 2012-08-29 = 2
Saturday, 2012-08-25 -> Thursday, 2012-08-30 = 3
Saturday, 2012-08-25 -> Friday, 2012-08-31 = 4
Saturday, 2012-08-25 -> Sunday, 2012-09-02 = 0
Monday, 2012-08-27 -> Monday, 2012-08-27 = 0
Monday, 2012-08-27 -> Tuesday, 2012-08-28 = 1
Monday, 2012-08-27 -> Wednesday, 2012-08-29 = 2
Monday, 2012-08-27 -> Thursday, 2012-08-30 = 3
Monday, 2012-08-27 -> Friday, 2012-08-31 = 4
Monday, 2012-08-27 -> Saturday, 2012-09-01 = 5
Monday, 2012-08-27 -> Sunday, 2012-09-02 = 5
DELIMITER //
DROP FUNCTION IF EXISTS WORKDAYS_LEFT//

CREATE FUNCTION WORKDAYS_LEFT(target_date DATE, location char(2))
RETURNS INT
LANGUAGE SQL
DETERMINISTIC
BEGIN
  DECLARE start_date DATE;
  DECLARE end_date DATE;
  DECLARE check_date DATE;
  DECLARE diff INT;
  DECLARE extra_weekend_days INT;
  DECLARE weeks_diff INT;

  SET start_date = CURDATE();
  SET end_date = target_date;
  SET diff = DATEDIFF(end_date, start_date);
  SET weeks_diff = FLOOR(diff / 7);
  SET end_date = DATE_SUB(end_date, INTERVAL (weeks_diff * 7) DAY);
  SET check_date = DATE_ADD(start_date, INTERVAL 1 DAY);
  SET extra_weekend_days = 0;
  WHILE check_date <= end_date DO
    SET extra_weekend_days = extra_weekend_days +
      IF(DAYNAME(check_date) = 'Saturday', 1, 0) +
      IF(DAYNAME(check_date) = IF(location = 'IL','Friday', 'Sunday'), 1, 0);
    SET check_date = DATE_ADD(check_date, INTERVAL 1 DAY);
  END WHILE;

  RETURN diff - weeks_diff*2 - extra_weekend_days;
END//

DELIMITER ;
SELECT (DATEDIFF(date_end, date_start)) -
        ((WEEK(date_end) - WEEK(date_start)) * 2) -
        (case when weekday(date_end) = 6 then 1 else 0 end) -
        (case when weekday(date_start) = 5 then 1 else 0 end) -
        (SELECT COUNT(*) FROM holidays WHERE holiday>=date_start and holiday<=data_end)
CREATE FUNCTION `WDDIFF` (d0 DATE, d1 DATE) 
  RETURNS INT DETERMINISTIC 
  COMMENT 'Date0, Date1' 
BEGIN 
  RETURN DATEDIFF(d1, d0) - (DATEDIFF(DATE_SUB(d1, INTERVAL WEEKDAY(d1) DAY), DATE_ADD(d0, INTERVAL (7 - WEEKDAY(d0)) DAY))/7+1)*2 + IF(WEEKDAY(d0)>4, 1, 0) + 1; 
END
    RETURN (diff + 1)
    - (FLOOR(diff / 7) * 2)
    - (CASE WHEN DAYNAME(start_date) = 'Sunday' THEN 1 ELSE 0 END)
    - (CASE WHEN DAYNAME(end_date) = 'Saturday' THEN 1 ELSE 0 END)
    - (CASE WHEN diff<7 and WEEK(start_date)<>WEEK(end_date) THEN 2 ELSE 0 end);
DELIMITER $$
DROP FUNCTION IF EXISTS WORKDAYS $$
CREATE FUNCTION `WORKDAYS` (first_date DATETIME, second_date DATETIME) RETURNS INT
LANGUAGE SQL
DETERMINISTIC

BEGIN

DECLARE start_date DATE;
DECLARE end_date DATE;
DECLARE diff INT;
DECLARE NumberOfWeeks INT;
DECLARE RemainingDays INT;
DECLARE firstDayOfTheWeek INT;
DECLARE lastDayOfTheWeek INT;
DECLARE WorkingDays INT;  

IF (first_date < second_date) THEN
SET start_date = first_date;
SET end_date = second_date;
ELSE
SET start_date = second_date;
SET end_date = first_date;
END IF;

## Add one to include both days in interval
SET diff = DATEDIFF(end_date, start_date)+1;
SET NumberOfWeeks=floor(diff/7);
SET RemainingDays=MOD(diff,7);
SET firstDayOfTheWeek=DAYOFWEEK(start_date);
SET lastDayOfTheWeek=DAYOFWEEK(end_date); 


IF(firstDayOfTheWeek <= lastDayOfTheWeek) THEN 

   IF( firstDayOfTheWeek<=6 AND 6 <=lastDayOfTheWeek) THEN SET        RemainingDays=RemainingDays-1; END IF;
   IF( firstDayOfTheWeek<=7 AND 7 <=lastDayOfTheWeek) THEN SET RemainingDays=RemainingDays-1; END IF; 
   ELSE
       IF( firstDayOfTheWeek=7) THEN SET RemainingDays=RemainingDays-1;
         IF (lastDayOfTheWeek=6) THEN  SET RemainingDays=RemainingDays-1; END IF;  
       ELSE SET RemainingDays=RemainingDays-2;
       END IF;
   END IF;

   SET WorkingDays=NumberOfWeeks*5;

   IF(RemainingDays>0) THEN RETURN WorkingDays+RemainingDays;

   ELSE RETURN WorkingDays; END IF;

 END $$

 DELIMITER ;
-- Routine DDL
-- Note: comments before and after the routine body will not be stored by the server
-- --------------------------------------------------------------------------------
DELIMITER $$

CREATE DEFINER=`root`@`localhost` FUNCTION `fn_GetBusinessDaysBetweenDates`(d1 DATE, d2 DATE) RETURNS int(11)
BEGIN
    DECLARE bDaysInPeriod INT;

    SET bDaysInPeriod=0;
    WHILE d1<=d2 DO
        IF DAYOFWEEK(d1) BETWEEN 2 AND 6 THEN
            SET bDaysInPeriod=bDaysInPeriod+1;
        END IF;

        SET d1=d1+INTERVAL 1 day;
    END WHILE;

    RETURN bDaysInPeriod;
END
 | M T W T F S S
-|--------------
M| 0 1 2 3 4 5 5
T| 4 0 1 2 3 4 4
W| 3 4 0 1 2 3 3
T| 2 3 4 0 1 2 2
F| 1 2 3 4 0 1 1
S| 0 1 2 3 4 0 0
S| 0 1 2 3 4 5 0
Below function will give you the Weekdays, Weekends, Date difference with proper results:

You can call the below function like,
select getWorkingday('2014-04-01','2014-05-05','day_diffs');
select getWorkingday('2014-04-01','2014-05-05','work_days');
select getWorkingday('2014-04-01','2014-05-05','weekend_days');




    DROP FUNCTION IF EXISTS PREPROCESSOR.getWorkingday;
    CREATE FUNCTION PREPROCESSOR.`getWorkingday`(d1 datetime,d2 datetime, retType varchar(20)) RETURNS varchar(255) CHARSET utf8
    BEGIN
     DECLARE dow1, dow2,daydiff,workdays, weekenddays, retdays,hourdiff INT;
        declare newstrt_dt datetime;
       SELECT dd.iDiff, dd.iDiff - dd.iWeekEndDays AS iWorkDays, dd.iWeekEndDays into daydiff, workdays, weekenddays
      FROM (
       SELECT
         dd.iDiff,
         ((dd.iWeeks * 2) + 
          IF(dd.iSatDiff >= 0 AND dd.iSatDiff < dd.iDays, 1, 0) + 
          IF (dd.iSunDiff >= 0 AND dd.iSunDiff < dd.iDays, 1, 0)) AS iWeekEndDays
           FROM (
          SELECT  dd.iDiff, FLOOR(dd.iDiff / 7) AS iWeeks, dd.iDiff % 7 iDays, 5 - dd.iStartDay AS iSatDiff,  6 - dd.iStartDay AS iSunDiff
         FROM (
          SELECT
            1 + DATEDIFF(d2, d1) AS iDiff,
            WEEKDAY(d1) AS iStartDay
          ) AS dd
        ) AS dd
      ) AS dd ;
      if(retType = 'day_diffs') then
      set retdays = daydiff; 
     elseif(retType = 'work_days') then
      set retdays = workdays; 
     elseif(retType = 'weekend_days') then  
      set retdays = weekenddays; 
     end if; 
        RETURN retdays; 
        END;


Thank You.
Vinod Cyriac.
Bangalore
DROP FUNCTION IF EXISTS DateDiffBusiness;
DELIMITER &
CREATE FUNCTION DateDiffBusiness( d2 DATE, d1 DATE )
RETURNS INT
DETERMINISTIC
COMMENT 'Calculates the number of bussiness days between two dates'
BEGIN
  DECLARE dow1, dow2, days INT;
  SET dow1 = DAYOFWEEK(d1);
  SET dow2 = DAYOFWEEK(d2);
  SET days = FLOOR( DATEDIFF(d2,d1)/7 ) * 5 +
             CASE
               WHEN dow1=1 AND dow2=7 THEN 5
               WHEN dow1 IN(7,1) AND dow2 IN (7,1) THEN 0
               WHEN dow1=dow2 THEN 1
               WHEN dow1 IN(7,1) AND dow2 NOT IN (7,1) THEN dow2-1
               WHEN dow1 NOT IN(7,1) AND dow2 IN(7,1) THEN 7-dow1
               WHEN dow1<=dow2 THEN dow2-dow1+1
               WHEN dow1>dow2 THEN 5-(dow1-dow2-1)
               ELSE 0
             END;
  RETURN days-1;
END&
DELIMITER ;


DROP FUNCTION IF EXISTS DateAddBusiness;
DELIMITER &
CREATE FUNCTION DateAddBusiness(mydate DATE, numday INT) 
RETURNS DATE
DETERMINISTIC
COMMENT 'Adds bussiness days between two dates'
BEGIN
 DECLARE num_week INT DEFAULT 0;
 DECLARE num_day INT DEFAULT 0;
 DECLARE adj INT DEFAULT 0;
 DECLARE total INT DEFAULT 0;
 SET num_week = numday DIV 5;
 SET num_day = MOD(numday, 5);
 IF (WEEKDAY(mydate) + num_day >= 5) then
  SET adj = 2;
 END IF;
 SET total = num_week * 7 + adj + num_day;
 RETURN DATE_ADD(mydate, INTERVAL total DAY);
END&
DELIMITER ;
DELIMITER $$

DROP FUNCTION IF EXISTS `WORKDAYS` $$
CREATE FUNCTION `WORKDAYS` (first_date DATETIME, second_date DATETIME) RETURNS INT
LANGUAGE SQL
DETERMINISTIC

BEGIN

  DECLARE start_date DATE;
  DECLARE end_date DATE;
  DECLARE diff INT;
  DECLARE cnt INT;

  IF (first_date < second_date) THEN
    SET start_date = first_date;
    SET end_date = second_date;
  ELSE
    SET start_date = second_date;
    SET end_date = first_date;
  END IF;

   SELECT COUNT(*) INTO cnt FROM `holiday` WHERE (hday BETWEEN start_date AND end_date) and (DAYOFWEEK(hday) != 7 and DAYOFWEEK(hday) != 1);

  SET diff = DATEDIFF(end_date, start_date) ;

  RETURN (CASE WHEN DAYNAME(start_date) not in ('Saturday', 'Sunday') && DAYNAME(end_date) = 'Saturday' THEN (diff - cnt)
               WHEN DAYNAME(start_date) not in ('Saturday', 'Sunday') && DAYNAME(end_date) = 'Sunday' THEN (diff - 2 - cnt)

               WHEN DAYNAME(start_date) = 'Saturday' && DAYNAME(end_date) = 'Sunday' THEN (diff - 1 - cnt)
               WHEN DAYNAME(start_date) = 'Saturday' && DAYNAME(end_date) = 'Saturday' THEN (diff + 1 - cnt)
               WHEN DAYNAME(start_date) = 'Sunday' && DAYNAME(end_date) in ('Saturday', 'Sunday') THEN (diff + 1 - cnt)

               WHEN DAYNAME(start_date) = 'Saturday' && DAYNAME(end_date) not in ('Saturday', 'Sunday') THEN (diff -1 - cnt)
               WHEN DAYNAME(start_date) = 'Sunday' && DAYNAME(end_date) not in ('Saturday', 'Sunday') THEN (diff + 1 - cnt)

               WHEN DAYNAME(start_date) not in ('Saturday', 'Sunday') && DAYNAME(end_date) not in ('Saturday', 'Sunday')
                    && WEEKDAY(start_date) > WEEKDAY(end_date) THEN (diff - 2 - cnt)
               ELSE (diff - cnt)  END)
    - (FLOOR(diff / 7) * 2)
    - (CASE WHEN DAYNAME(start_date) = 'Sunday' THEN 1 ELSE 0 END)
    - (CASE WHEN DAYNAME(end_date) = 'Saturday' THEN 1 ELSE 0 END);

END $$
DROP TABLE IF EXISTS `holiday`;
CREATE TABLE `holiday` (
  `id` bigint(32) unsigned NOT NULL AUTO_INCREMENT,
  `hday` date NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8;

INSERT INTO `holiday` (`id`, `hday`) VALUES
(1, '2012-01-01'),
(2, '2012-05-01'),
(3, '2012-05-08'),
(4, '2012-07-05'),
(5, '2012-07-06'),
(6, '2012-09-28'),
(7, '2012-10-28'),
(8, '2012-11-17'),
(9, '2012-12-24'),
(10,    '2012-12-25'),
(11,    '2012-12-26');
etc...
DELIMITER //
DROP FUNCTION IF EXISTS NETWORKDAYS//
CREATE FUNCTION NETWORKDAYS(sd DATE, ed DATE)
RETURNS INT
LANGUAGE SQL
DETERMINISTIC
BEGIN
  RETURN (5 * (DATEDIFF(ed, sd) DIV 7) + MID('0123444401233334012222340111123400001234000123440', 7 * WEEKDAY(sd) + WEEKDAY(ed) + 1, 1))+1;
END//
DELIMITER ;
SELECT NETWORKDAYS('2015-01-01 06:00:00', '2015-01-20 06:00:00');
DELIMITER $$
DROP FUNCTION IF EXISTS WORKDAYSDIFF$$
CREATE FUNCTION WORKDAYSDIFF(sd DATE, ed DATE)
RETURNS INT
LANGUAGE SQL
DETERMINISTIC
BEGIN
 RETURN IF (sd >= ed, 
    5 * (DATEDIFF(sd, ed) DIV 7) + MID('0123455501234445012333450122234501101234000123450', 7 * WEEKDAY(ed) + WEEKDAY(sd) + 1, 1),
  -(5 * (DATEDIFF(ed, sd) DIV 7) + MID('0123455501234445012333450122234501101234000123450', 7 * WEEKDAY(sd) + WEEKDAY(ed) + 1, 1)) );
END$$
DELIMITER ;
select datediff('2016-06-19','2016-06-01') - (floor(datediff('2016-06-19','2016-06-01')/6) + floor(datediff('2016-06-19','2016-06-01')/7));
CREATE DEFINER=`root`@`localhost` FUNCTION `weekdayDiff`
(
edate datetime,
sdate datetime
)
RETURNS int
DETERMINISTIC

BEGIN
if edate>sdate
then
 return 5 * (DATEDIFF(edate, sdate) DIV 7) + MID('+0+1+2+3+4+4+4+4+0+1+2+3+3+3+3+4+0+1+2+2+2+2+3+4+0+1+1+1+1+2+3+4+0+0+0+0+1+2+3+4-1-1+0+1+2+3+4+4-1', 2*(7 * WEEKDAY(sdate) + WEEKDAY(edate)) + 1, 2);
else
 return -(5 * (DATEDIFF(sdate, edate) DIV 7) + MID('+0+1+2+3+4+4+4+4+0+1+2+3+3+3+3+4+0+1+2+2+2+2+3+4+0+1+1+1+1+2+3+4+0+0+0+0+1+2+3+4-1-1+0+1+2+3+4+4-1', 2*(7 * WEEKDAY(edate) + WEEKDAY(sdate)) + 1, 2));
end if;

-- The following works unless both start and finish date are on weekends.
-- return 5 * (DATEDIFF(edate, sdate) DIV 7) + MID('0123444401233334012222340111123400001234000123440', 7 * WEEKDAY(sdate) + WEEKDAY(edate) + 1, 1);

END;
 |  M  T  W  T  F  S  S
-|---------------------
M| +0 +1 +2 +3 +4 +4 +4
T| +4 +0 +1 +2 +3 +3 +3
W| +3 +4 +0 +1 +2 +2 +2
T| +2 +3 +4 +0 +1 +1 +1
F| +1 +2 +3 +4 +0 +0 +0
S| +0 +1 +2 +3 +4 -1 -1
S| +0 +1 +2 +3 +4 +4 -1
set
@S = '2016-04-01',
@E = '2016-04-30';
 select
    case 
        when WEEKDAY(@S) < 5 then 5 - WEEKDAY(@S)
        else 0
    end #startweek
    +
    case 
        when WEEKDAY(@E) < 5 then WEEKDAY(@E) + 1
        else 5
    end #endweek
    +
    (
        DATEDIFF(@E, @S) + 1 # plus 1 day cause params is inside 1 month
        - (7 - WEEKDAY(@S)) # minus start week
        - (WEEKDAY(@E) + 1) # minus end week
    ) DIV 7 * 5 #rest part


    as work_date_count;
SELECT  5* (DATEDIFF(u.EndDate, u.StartDate) DIV 7) + MID('1234555512344445123333451222234511112345001234550', 7 * WEEKDAY(u.StartDate) + WEEKDAY(u.EndDate) + 1, 1)
DROP FUNCTION IF EXISTS datediff_workdays;
CREATE FUNCTION datediff_workdays(start_date DATE, end_date DATE) RETURNS INTEGER
BEGIN
  RETURN 5 * (DATEDIFF(end_date, start_date) DIV 7) + MID('0123455501234445012333450122234501101234000123450', 7 * WEEKDAY(start_date) + WEEKDAY(end_date) + 1, 1);
END
drop procedure if exists get_duration$$
create procedure get_duration(in data_from date, in data_to date)
begin
    if (WEEKDAY(data_from) = 5 AND WEEKDAY(data_to) = 5) 
    OR (WEEKDAY(data_from) = 6 AND WEEKDAY(data_to) = 6) then
        select (5 * (DATEDIFF(data_to, data_from) DIV 7) 
        + MID('0123444401233334012222340111123400001234000123440',
        7 * WEEKDAY(data_from) + WEEKDAY(data_to) + 1, 1)) dur;
    else 
        select (5 * (DATEDIFF(data_to, data_from) DIV 7) 
        + MID('0123444401233334012222340111123400001234000123440',
        7 * WEEKDAY(data_from) + WEEKDAY(data_to) + 1, 1))+1 dur;
    end if;
end$$
RETURN ABS(DATEDIFF(date2, date1)) + 1
     - ABS(DATEDIFF(ADDDATE(date2, INTERVAL 1 - DAYOFWEEK(date2) DAY),
                    ADDDATE(date1, INTERVAL 1 - DAYOFWEEK(date1) DAY))) / 7 * 2
     - (DAYOFWEEK(IF(date1 < date2, date1, date2)) = 1)
     - (DAYOFWEEK(IF(date1 > date2, date1, date2)) = 7)
     - (SELECT DISTINCT COUNT(PriKey) FROM holidays WHERE date BETWEEN date1 AND date2)
     + (SELECT DISTINCT COUNT(PriKey) FROM weekenddaysworked WHERE date BETWEEN date1 AND date2)
select 
    FLOOR(DATEDIFF(later_date, earlier_date) / 7) * 5 +  
    least(DATEDIFF(later_date, earlier_date) % 7, 5) + 
    if(weekday(later_date) < weekday(earlier_date), -2, 0);
SELECT 5 * (DATEDIFF(@E, @S) DIV 7) +
  CASE WHEN @E < @S THEN
    -1 * MID('0123455401234434012332340122123401101234000123450', 7 * WEEKDAY(@E) + WEEKDAY(@S) + 1, 1)
  ELSE
    MID('0123455401234434012332340122123401101234000123450', 7 * WEEKDAY(@S) + WEEKDAY(@E) + 1, 1)
  END
+------------+------------+-----------+
| @S         | @E         | wday_diff |
+------------+------------+-----------+
| 2019-11-25 | 2019-10-26 |       -20 |
| 2019-11-25 | 2019-11-28 |         3 |
+------------+------------+-----------+