SQL统计计数结果

我正试图从销售中生成我想在DataStudio中显示的报告。我有电子邮件栏、订单号和总价，我正在尝试使用sql查询识别以下内容：

重复和新客户数量（计算订单数量，如果订单>1，则重复，否则为新）

来自重复客户和新客户的订单数

我所做的只是计算每封电子邮件的订单数量

SELECT email, count(email) as order_count, date FROM orders GROUP BY 
email

这是我想展示的示例报告

    Repeating Customer | New Customer  
        1              |       2


    Orders from Repeating Cust. | Orders from New Customer
          2                     |    2


    Total Price Repeating Cust. | Total Price New Custo.
          200                   |      330

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非常感谢您的帮助。

使用两个单独的查询，一个用于重复查询，另一个用于新客户查询，然后简单地加入它们以创建您的报告

重复客户

SELECT email, COUNT(email), SUM(TotalPrice) as order_count FROM orders GROUP BY email HAVING COUNT(email) > 1

SELECT email, SUM(TotalPrice) as order_count FROM orders GROUP BY email HAVING COUNT(email) = 1

新客户

SELECT email, COUNT(email), SUM(TotalPrice) as order_count FROM orders GROUP BY email HAVING COUNT(email) > 1

SELECT email, SUM(TotalPrice) as order_count FROM orders GROUP BY email HAVING COUNT(email) = 1

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如果您使用前端技术来显示这些结果，那么您也可以在前端将这些结果编译为水平方向（重复和新客户在两列而不是两行中）。如果要在纯SQL中执行此操作，只需交叉连接两个查询即可获得输出。

您可以尝试大小写和子查询：

SELECT SUM(CASE WHEN t.Cust_cnt=1 THEN 1 ELSE 0 END) AS New_Cust,
       SUM(CASE WHEN t.Cust_cnt>1 THEN 1 ELSE 0 END) AS Repeat_Cust,
       SUM(CASE WHEN t.Cust_cnt=1 THEN t.Total_Order ELSE 0 END) AS New_Cust_Order,
       SUM(CASE WHEN t.Cust_cnt>1 THEN t.Total_Order ELSE 0 END) AS Repeat_Cust_Order,
       SUM(CASE WHEN t.Cust_cnt=1 THEN t.Total_Price ELSE 0 END) AS New_Cust_Order_Total_Price,
       SUM(CASE WHEN t.Cust_cnt>1 THEN t.Total_Price ELSE 0 END) AS Repeat_Cust_OrderTotal_Price,
       t.Last_Order_Date
FROM (
SELECT COUNT(Email) AS Cust_cnt,SUM(O_Price) AS Total_Price,COUNT(O_Number) AS Total_Order, MAX(O_Date) AS Last_Order_Date, Email  FROM Orders Group by Email) AS t;

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它可能为GROUP BY子句提供错误，并且包含未聚合的列“orders.date”，该列在功能上不依赖于GROUP BY中的列clause@FrustratedDeveloper：啊，是的，把它们拿走了，因为输出不需要它们。我怎么能包括日期？你可以选择我在回答中编辑的

max

或

min

日期，但是根据你的帖子，你也可以使用

订单号

代替

电子邮件