Sql 如何合并不同表中的范围

给出以下两个表格：

T1
------------------
From | To  | Value
------------------
10   | 20  | XXX
20   | 30  | YYY
30   | 40  | ZZZ


T2
------------------
From | To  | Value
------------------
10   | 15  | AAA
15   | 19  | BBB
19   | 39  | CCC
39   | 40  | DDD

在SQLServer2008上使用T-SQL获得以下结果的最佳方法是什么

“从/到”范围是连续的，没有间隙，下一个“从”始终与上一个“到”具有相同的值

---

下面的查询查找最小范围，然后再次从表中提取值：

SELECT ranges.from, ranges.to, T1.Value, T2.Value
FROM (SELECT all_from.from, min(all_to.to) as to
    FROM (SELECT T1.FROM
        FROM T1
        UNION 
        SELECT T2.FROM 
        FROM T2) all_from
    JOIN (SELECT T1.TO
        FROM T1
        UNION
        SELECT T2.FROM
        FROM T2) all_to ON all_from.from < all_to.to
    GROUP BY all_from.from) ranges
JOIN T1 ON ranges.from >= T1.from AND ranges.to <= T1.to
JOIN T2 ON ranges.from >= T2.from AND ranges.to <= T2.to
ORDER BY ranges.from

---

首先，我声明的数据与您发布的数据相似。如果我所做的任何假设是错误的，请纠正我。最好是在问题中发表你自己的声明，这样我们都在使用相同的数据

DECLARE @T1 TABLE (
  [From] INT,
  [To] INT,
  [Value] CHAR(3)
);

INSERT INTO @T1 (
  [From],
  [To],
  [Value]
)
VALUES
  (10, 20, 'XXX'),
  (20, 30, 'YYY'),
  (30, 40, 'ZZZ');

DECLARE @T2 TABLE (
  [From] INT,
  [To] INT,
  [Value] CHAR(3)
);

INSERT INTO @T2 (
  [From],
  [To],
  [Value]
)
VALUES
  (10, 15, 'AAA'),
  (15, 19, 'BBB'),
  (19, 39, 'CCC'),
  (39, 40, 'DDD');

以下是我的select查询，用于生成您的预期结果：

SELECT
  CASE
    WHEN [@T1].[From] > [@T2].[From]
    THEN [@T1].[From]
    ELSE [@T2].[From]
  END AS [From],
  CASE
    WHEN [@T1].[To] < [@T2].[To]
    THEN [@T1].[To]
    ELSE [@T2].[To]
  END AS [To],
  [@T1].[Value],
  [@T2].[Value]
FROM @T1
INNER JOIN @T2 ON
  (
    [@T1].[From] <= [@T2].[From] AND
    [@T1].[To] > [@T2].[From]
  ) OR
  (
    [@T2].[From] <= [@T1].[From] AND
    [@T2].[To] > [@T1].[From]
  );

---

谢谢你的回答，但我最后使用了CTE，我认为wgich更干净

DECLARE @T1 TABLE ([From] INT, [To] INT, [Value] CHAR(3));
DECLARE @T2 TABLE ([From] INT, [To] INT, [Value] CHAR(3));

INSERT INTO @T1 (  [From],  [To],  [Value]) VALUES  (10, 20, 'XXX'),  (20, 30, 'YYY'),  (30, 40, 'ZZZ');
INSERT INTO @T2 (  [From],  [To],  [Value]) VALUES  (10, 15, 'AAA'),  (15, 19, 'BBB'),  (19, 39, 'CCC'),  (39, 40, 'DDD');

;with merged1 as 
(
    select 
        t1.[From] as from1,
        t1.[to] as to1,
        t1.Value as Value1,
        t2.[From] as from2,
        t2.[to] as to2,
        t2.Value as Value2
    from @t1 t1
    inner join @T2 t2 
        on t1.[From] <  t2.[To]
        and t1.[To] >= t2.[From]

)
,merged2 as 
(
    select 
          case when from2>=from1 then from2 else from1 end as [From]
         ,case when to2<=to1 then to2 else to1 end as [To]
         ,value1
         ,value2
    from merged1
)
select * from merged2

---

窃取@isme的数据设置，我写了以下内容：

;With EPs as (
    select [From] as EP from @T1
    union
    select [To] from @T1
    union
    select [From] from @T2
    union
    select [To] from @T2
), OrderedEndpoints as (
    select EP,ROW_NUMBER() OVER (ORDER BY EP) as rn from EPs
)
select
    oe1.EP,
    oe2.EP,
    t1.Value,
    t2.Value
from
    OrderedEndpoints oe1
        inner join
    OrderedEndpoints oe2
        on
            oe1.rn = oe2.rn - 1
        inner join
    @T1 t1
        on
            oe1.EP < t1.[To] and
            oe2.EP > t1.[From]
        inner join
    @T2 t2
        on
            oe1.EP < t2.[To] and
            oe2.EP > t2.[From]

也就是说，您创建一个包含时段EPs的所有可能端点的集合，然后对这些端点进行排序，并为每个端点分配一个行号OrderedEPs

---

然后，最终的查询将每对相邻的行组合在一起，并连接回原始表，以查找每一行中哪些行与所选范围重叠。

我无法编译此查询。您是如何设置测试数据的？使用我的数据设置，这仍然无法为我编译。在您的查询副本中，我将所有出现的T1替换为[@T1]，将所有出现的T2替换为[@T2]，并在执行时收到此语法错误：Msg 156，级别15，状态1，第34行关键字“from”附近的语法不正确。我删除了关于结果集不同的注释，因为它们是相同的。

;With EPs as (
    select [From] as EP from @T1
    union
    select [To] from @T1
    union
    select [From] from @T2
    union
    select [To] from @T2
), OrderedEndpoints as (
    select EP,ROW_NUMBER() OVER (ORDER BY EP) as rn from EPs
)
select
    oe1.EP,
    oe2.EP,
    t1.Value,
    t2.Value
from
    OrderedEndpoints oe1
        inner join
    OrderedEndpoints oe2
        on
            oe1.rn = oe2.rn - 1
        inner join
    @T1 t1
        on
            oe1.EP < t1.[To] and
            oe2.EP > t1.[From]
        inner join
    @T2 t2
        on
            oe1.EP < t2.[To] and
            oe2.EP > t2.[From]