Sql 组合两个选择查询

我有两个选择查询

select name1,age1 from table1

输出：

+--------+------+
| name1  | age1 |
+--------+------+
| ravi   |   25 |
| rakhav |   12 |
| joil   |   10 |
+--------+------+

select color,no from table2

输出

+--------+----+
| color  | no |
+--------+----+
| red    |  3 |
| yellow |  4 |
+--------+----+

我想要像这样的输出

+--------+------+--------+----+
| name1  | age1 | color  | no |
+--------+------+--------+----+
| ravi   |   25 | red    |  3 |
| rakhav |   12 | yellow |  4 |
| joil   |   10 |        |    |
+--------+------+--------+----+

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尝试

从表1 t1、表2 t2中选择t1.*、t2.

尝试以下操作：

select * from
(select name1, age1, row_number() over(order by age1 desc) as rn from table1) as t1
left join
(select color, no, row_number() over(order by no) as rn from table2) as t2
on t1.rn = t2.rn

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它的获取类似于交叉连接是的，但是您想如何组合来自两个表的记录呢？如果没有orderby，您的两个select语句将以随机顺序返回行。表2的哪些行与表1的哪些行对应？如果您只是试图通过一个查询获得两条完全不相关的信息，请不要这样做。使用两个查询。否则，请解释它们是如何相关的。是的，完全不相关的片段。。。