Sql 错误要求的列数少于返回的列数
错误:Sql 错误要求的列数少于返回的列数,sql,postgresql,plpgsql,Sql,Postgresql,Plpgsql,错误: CREATE OR REPLACE FUNCTION get_user_info ( u_email VARCHAR, u_password VARCHAR, p_name VARCHAR ) RETURNS TABLE( user_id int, given_name varchar(55), family_name varchar(55), password
CREATE OR REPLACE FUNCTION get_user_info ( u_email VARCHAR, u_password VARCHAR, p_name VARCHAR )
RETURNS TABLE(
user_id int,
given_name varchar(55),
family_name varchar(55),
password varchar(255),
email varchar(255),
date_of_birth date
)
AS $$
BEGIN
-- If a player display player_name and team_id
IF p_name != '' THEN
RETURN QUERY
SELECT player.user_id, player.given_name, player.family_name, player.password, player.email, player.date_of_birth,
player.player_name AS player_name, player.team_id AS team_id FROM player
WHERE player.email = u_email and player.password = u_password;
-- If not a player then display usual table
ELSE
RETURN QUERY
SELECT * FROM "user"
WHERE "user".email = u_email and "user".password = u_password;
END IF;
END $$
LANGUAGE plpgsql;
-- Get user info with arguments - email, password and player_name. If not a player pass '' as player_name
SELECT get_user_info('tomtom@hotmail.com', 'tommy12', 'tomkilla'); -- Player
只是想知道为什么我会犯这个错误?我发誓我以前让它工作过,但是现在它不工作了,如果我做一个旁观者,查询就工作了,你的函数只希望返回6列
ERROR: structure of query does not match function result type
DETAIL: Number of returned columns (8) does not match expected column count (6).
CONTEXT: PL/pgSQL function get_user_info(character varying,character varying,character varying) line 5 at RETURN QUERY
SQL state: 42804
但是select语句返回了8列
(
user_id int,
given_name varchar(55),
family_name varchar(55),
password varchar(255),
email varchar(255),
date_of_birth date
)
您可以在return语句中添加这两列,如下所示
player.user_id, player.given_name, player.family_name, player.password, player.email, player.date_of_birth,player.player_name AS player_name, player.team_id AS team_id
(
用户id int,
命名为varchar(55),
姓瓦查尔(55岁),
密码varchar(255),
电子邮件varchar(255),
出生日期,
玩家姓名,
团队id
)
在else语句中,您将从users表返回所有列,您可以指定需要返回的列,否则您可能也会遇到问题。那么,我将如何两次指定这些列呢?因为我只想在球员而不是观众的情况下展示其他两列。它们从“用户”表继承。不,您不能这样做。对于返回的动态列数,您可以从函数中返回
SETOF RECORD
,但必须在select中指定列。那么为什么“player.player\u name作为player\u name,player.team\u id作为team\u id”不起作用呢?我认为这会在psuedo列中添加内容?要实现这一点,您必须返回记录集
而不是表
。如果您想删除您的问题,请“关闭”它,但不要删除实际文本
(
user_id int,
given_name varchar(55),
family_name varchar(55),
password varchar(255),
email varchar(255),
date_of_birth date,
player_name <type>,
team_id <type>
)