Sql 如何在HANA中创建案例

Sql 如何在HANA中创建案例,sql,case,hana,Sql,Case,Hana,我在postgres中有以下查询,其中给出了仪表范围和在该范围内行驶的车辆数量 SELECT (CASE WHEN meter >= 0 AND meter< 10000 THEN '0-10' WHEN meter >= 10000 AND meter < 20000 THEN '10-20' WHEN meter >= 20000 AND meter <30000 THEN '20-30'

我在postgres中有以下查询,其中给出了仪表范围和在该范围内行驶的车辆数量

SELECT (CASE WHEN meter >= 0 AND meter< 10000 THEN '0-10' 
             WHEN meter >= 10000 AND meter < 20000  THEN '10-20' 
             WHEN meter >= 20000 AND meter <30000 THEN '20-30' 
             WHEN meter >= 30000 AND meter < 40000 THEN '30-40' 
             WHEN meter >= 40000 AND meter < 50000 THEN '40-50' 
             WHEN meter >= 50000 AND meter < 60000  THEN '50-60' 
             WHEN meter >= 60000 AND meter <70000 THEN '60-70' 
             WHEN meter >= 70000 AND meter < 80000 THEN '70-80' 
             WHEN meter >= 80000 AND meter < 100000 THEN '80-90' 
             WHEN meter >=100000 THEN 'above 100'  
       END) as range,count(*) as vehicle_count 
        from ( 



      SELECT extract (day from time) as day, place,vehicle_id,sum(meter_two_points) as meter 
FROM public.datatable where time >= '2015-09-05 00:00:00' and time <= '2015-09-05 23:00:00' and place=10 
  group by day,vehicle_id,place 
  order by day,vehicle_id  



)  as A group by range  order by range limit 10
现在我想对HANA中的同一个表执行相同的查询

 SELECT (CASE   WHEN meter >= 0 AND meter< 10000 THEN '0-10' 
                WHEN meter >= 10000 AND meter < 20000  THEN '10-20' 
                WHEN meter >= 20000 AND meter <30000 THEN '20-30' 
                WHEN meter >= 30000 AND meter < 40000 THEN '30-40' 
                WHEN meter >= 40000 AND meter < 50000 THEN '40-50' 
                WHEN meter >= 50000 AND meter < 60000  THEN '50-60' 
                WHEN meter >= 60000 AND meter <70000 THEN '60-70' 
                WHEN meter >= 70000 AND meter < 80000 THEN '70-80' 
                WHEN meter >= 80000 AND meter < 100000 THEN '80-90' 
                WHEN meter >=100000 THEN 'above 100'  
           END) as range,count(*) as vehicle_count 
            from ( 


            But it throws with the error `invalid column name range`
          SELECT to_integer(to_varchar(time,'DD')) as day, place,vehicle_id,sum(meter_two_points) as meter 
    FROM public.datatable where time >= '2015-09-05 00:00:00' and time <= '2015-09-05 23:00:00' and place=10 
      group by day,vehicle_id,place 
      order by day,vehicle_id  



    )  as A group by range  order by range limit 10

您可以更改为:

SELECT range, 
    COUNT(*) AS vehicle_count 
FROM (
    SELECT (CASE   WHEN meter >= 0 AND meter< 10000 THEN '0-10' 
                WHEN meter >= 10000 AND meter < 20000  THEN '10-20' 
                WHEN meter >= 20000 AND meter <30000 THEN '20-30' 
                WHEN meter >= 30000 AND meter < 40000 THEN '30-40' 
                WHEN meter >= 40000 AND meter < 50000 THEN '40-50' 
                WHEN meter >= 50000 AND meter < 60000  THEN '50-60' 
                WHEN meter >= 60000 AND meter <70000 THEN '60-70' 
                WHEN meter >= 70000 AND meter < 80000 THEN '70-80' 
                WHEN meter >= 80000 AND meter < 100000 THEN '80-90' 
                WHEN meter >=100000 THEN 'above 100'  
           END) AS range
    FROM ( 
        SELECT to_integer(to_varchar(time,'DDMMYYYY')) AS day, 
            --You should considering using other way to truncate date from time, 
            --not convert too much,
            --at least you could use only to_varchar is enough
            place, 
            vehicle_id,
            SUM(meter_two_points) AS meter 
        FROM public.datatable 
        WHERE time >= '2015-09-05 00:00:00' 
            AND time <= '2015-09-05 23:00:00' 
            AND place=10 
        GROUP BY to_integer(to_varchar(time,'DDMMYYYY')), 
            vehicle_id, 
            place 
    )  
) AS a
GROUP BY range  
ORDER BY range 
LIMIT 10;       --why limit 10 here while you only have 10 ranges?

作为一个例子,我一直想知道PostgreSQL是否可以在第一次查询中选择“按范围分组”列后按分组。

您可以更改为:

SELECT range, 
    COUNT(*) AS vehicle_count 
FROM (
    SELECT (CASE   WHEN meter >= 0 AND meter< 10000 THEN '0-10' 
                WHEN meter >= 10000 AND meter < 20000  THEN '10-20' 
                WHEN meter >= 20000 AND meter <30000 THEN '20-30' 
                WHEN meter >= 30000 AND meter < 40000 THEN '30-40' 
                WHEN meter >= 40000 AND meter < 50000 THEN '40-50' 
                WHEN meter >= 50000 AND meter < 60000  THEN '50-60' 
                WHEN meter >= 60000 AND meter <70000 THEN '60-70' 
                WHEN meter >= 70000 AND meter < 80000 THEN '70-80' 
                WHEN meter >= 80000 AND meter < 100000 THEN '80-90' 
                WHEN meter >=100000 THEN 'above 100'  
           END) AS range
    FROM ( 
        SELECT to_integer(to_varchar(time,'DDMMYYYY')) AS day, 
            --You should considering using other way to truncate date from time, 
            --not convert too much,
            --at least you could use only to_varchar is enough
            place, 
            vehicle_id,
            SUM(meter_two_points) AS meter 
        FROM public.datatable 
        WHERE time >= '2015-09-05 00:00:00' 
            AND time <= '2015-09-05 23:00:00' 
            AND place=10 
        GROUP BY to_integer(to_varchar(time,'DDMMYYYY')), 
            vehicle_id, 
            place 
    )  
) AS a
GROUP BY range  
ORDER BY range 
LIMIT 10;       --why limit 10 here while you only have 10 ranges?

另外,我一直想知道PostgreSQL是否可以在第一次查询中选择GROUP BY后使用GROUP BY GROUP with range列进行分组。

postgre也应该抛出该错误。一般来说,SQL中的操作顺序是不能这样分组的。至少在postgre中需要一个嵌套子queryno,postgre也应该抛出这个错误。一般来说,SQL中的操作顺序是不能这样分组的。至少你需要一个嵌套子queryno在postgres中它工作得很好是的,它是关于SQL操作顺序的,PostgreSQL可以在选择后分组,但HANA不能这样做。chearsUp是关于SQL操作顺序的,PostgreSQL可以在选择后分组,但HANA不能这样做。干杯