Sql Oracle：在单个查询中求和此和此

我的订单表上有上周的订单和送货司机的ID。看起来有点像这样：

ORDERDATE,    ORDERNO,    DRIVER
23/01/2013,    901398503,    1
23/01/2013,    901332159,    1
23/01/2013,    901334158,    2
24/01/2013,    901338455,    1
25/01/2013,    902907513,    1
25/01/2013,    902338553,    2
25/01/2013,    903936533,    2
27/01/2013,    903944523,    1
27/01/2013,    903981522,    2
27/01/2013,    911334951,    1
28/01/2013,    911338851,    1
28/01/2013,    911339259,    1
28/01/2013,    912332555,    2
28/01/2013,    912336650,    2
29/01/2013,    912337655,    1
29/01/2013,    913969582,    1
29/01/2013,    913973583,    1
29/01/2013,    913982552,    1
29/01/2013,    916379158,    1

select 
 TRUNC(NEXT_DAY(sysdate,'SUNDAY')-7 +i) ORDERDATE,
 0 as ORDERCOUNT   
from
 (select rownum i from all_objects where rownum < 8)

我想选择ORDERDATE、ORDERCOUNT、DRIVER\u 1\u COUNT、DRIVER\u 2\u COUNT

所以，日期|总订单|驾驶员1的总订单|驾驶员2的总订单

另外，如果ORDERDATE、ORDERCOUNT、DRIVER_1_计数或DRIVER_2_计数为0或null，则需要零

在oracle中，我可以为上周的每一天选择日期，并为每一天选择一个零订单计数占位符，如下所示：

ORDERDATE,    ORDERNO,    DRIVER
23/01/2013,    901398503,    1
23/01/2013,    901332159,    1
23/01/2013,    901334158,    2
24/01/2013,    901338455,    1
25/01/2013,    902907513,    1
25/01/2013,    902338553,    2
25/01/2013,    903936533,    2
27/01/2013,    903944523,    1
27/01/2013,    903981522,    2
27/01/2013,    911334951,    1
28/01/2013,    911338851,    1
28/01/2013,    911339259,    1
28/01/2013,    912332555,    2
28/01/2013,    912336650,    2
29/01/2013,    912337655,    1
29/01/2013,    913969582,    1
29/01/2013,    913973583,    1
29/01/2013,    913982552,    1
29/01/2013,    916379158,    1

select 
 TRUNC(NEXT_DAY(sysdate,'SUNDAY')-7 +i) ORDERDATE,
 0 as ORDERCOUNT   
from
 (select rownum i from all_objects where rownum < 8)

我需要这个输出：

ORDERDATE,ORDERCOUNT,DRIVER_1_COUNT,DRIVER_2_COUNT
23/01/2013,3,2,1
24/01/2013,1,1,0
25/01/2013,3,1,2
26/01/2013,0,0,0
27/01/2013,3,2,1
28/01/2013,4,2,2
29/01/2013,5,5,0

我可以通过另一个查询获得ORDERDATE和ORDERCOUNTsimple和union，以避免遗漏天数，但我也无法计算每个驱动程序的总和

提前谢谢你的帮助

---

Ed

首先，您需要总结和交叉表结果：

SELECT ORDERDATE, SUM(ORDERCOUNT) ORDERCOUNT, 
SUM(DECODE(DRIVER,1,ORDERCOUNT,0)) DRIVER_1_COUNT, 
SUM(DECODE(DRIVER,2,ORDERCOUNT,0)) DRIVER_2_COUNT
FROM (
    SELECT ORDERDATE, DRIVER, COUNT(*) ORDERCOUNT
    FROM YourTable
    GROUP BY ORDERDATE, DRIVER
) S
GROUP BY  ORDERDATE

在Oracle中可能有更聪明的方法来做到这一点

然后，您需要使用外部将其与您的日期连接起来来填充空格：

注意：上述查询在此查询中别名为“T”：

SELECT D.ORDERDATE, 
NVL(T.ORDERCOUNT,0) ORDERCOUNT, 
NVL(T.DRIVER_1_COUNT,0) DRIVER_1_COUNT, 
NVL(T.DRIVER_1_COUNT,0) DRIVER_2_COUNT
FROM 
(
SELECT ORDERDATE, SUM(ORDERCOUNT) ORDERCOUNT, 
SUM(DECODE(DRIVER,1,ORDERCOUNT,0)) DRIVER_1_COUNT, 
SUM(DECODE(DRIVER,2,ORDERCOUNT,0)) DRIVER_2_COUNT
FROM 
    (
    SELECT ORDERDATE, DRIVER, COUNT(*) ORDERCOUNT
    FROM YourTable
    GROUP BY ORDERDATE, DRIVER
    ) S
GROUP BY  ORDERDATE
) T
RIGHT OUTER JOIN
(
SELECT
TRUNC(NEXT_DAY(sysdate,'SUNDAY')-7 +i) ORDERDATE
FROM (select rownum i from all_objects where rownum < 8)
) D
ON D.ORDERDATE = T.ORDERDATE

---

您必须从子查询中进行选择。这样的办法应该行得通

select orderdate, ordercount, sum(driver1) driver1count, sum(driver2) driver2count
from (
select orderdate
, case when driver = 1 then 1 else 0 end driver1
, case when driver = 2 then 1 else 0 end driver2
, count(*) ordercount

from yourtable

where whatever

group by orderdate
, case when driver = 1 then 1 else 0 end driver1
, case when driver = 2 then 1 else 0 end driver2

) you_need_an_alias_here

group by orderdate, ordercount

order by orderdate

---

在Oracle 11g中，您可以执行以下操作：-

SELECT *
FROM orders
PIVOT (
  COUNT( ORDERNO )
  FOR DRIVER IN (1,2,3)
)

有关进一步的解释，请参见

查看sumcase when。。。