Sql 从时段中删除假日间隔

以下查询计算在收到请求和响应请求之间经过的工作时间。工作时间为周一至周五的9点至5点

select tmp.Request_Id, 
sum (tmp.hhmmss) as WorkHoursElapsed
from

    (select Request_Id,
    period(cast(c.calendar_date as timestamp(6)) + INTERVAL '0000 09:00:00.00000' DAY TO SECOND,cast(calendar_date as timestamp(6)) + INTERVAL '0000 17:00:00.000000' DAY TO SECOND) as p, 
    p P_INTERSECT b.ref as i, 
    (end(i) - begin(i)) Hour(4) to MINUTE as hhmmss 
    from calendar c 
    Cross join

        (select Request_Id, period(LocalTime_Received_RTA ,LocalTime_Responded_RTA) as ref 
        from Responded_Requests 
         WHERE LocalTime_Received_RTA<LocalTime_Responded_RTA 
        group by 1,2
        ) as b 

    where p overlaps b.ref
    and c.day_of_week between 2 and 6  

    ) as tmp

group by 1

我有另一张表，有开始和结束的时间间隔

开始时间：2014年1月1日12:00:00上午结束时间：2014年1月1日11:59:00下午

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如何联接假日表以排除假日间隔？

您需要将其转换为Teradata SQL systax，在T-SQL中，您只需添加另一个联接和排除值，如下所示

SELECT m.*
    FROM mytable AS m
    JOIN othertable AS o
        ON m.date NOT BETWEEN o.StartDate AND o.EndDate

或

SELECT m.*
    FROM mytable AS m
    JOIN othertable AS o
        ON m.date < o.StartDate
           AND m.date > o.EndDate