Sql 带有ruby sinatra多对多的数据映射器：槽=>；资源

我正在尝试创建一个新的用户组多对多关系。 我正在使用这些dataMapper对象

module Core_authentication

  class User
    include DataMapper::Resource

    property :id, Serial
    property :username, String
    property :password, BCryptHash
    property :email, String
    property :created_at, DateTime
    property :updated_at, DateTime

    #Creating join tables to link to group and person information
    has n, :Person, :through => Resource
    has n, :Group, :through => Resource
  end  

  class Group
    include DataMapper::Resource

    property :id, Serial
    property :name, String

    #Another jointable link group to link to functions and classification levels
    has n, :Function, :through => Resource
    has n, :Classificationlevel, :through => Resource
  end  

  class Person
    include DataMapper::Resource

    property :id, Serial
    property :firstname, String
    property :lastname, String
    property :adress, String
    property :postcode, String
    property :telefoon, String
    property :created_at, DateTime
    property :updated_at, DateTime

  end  

  class Function
    include DataMapper::Resource

    property :id, Serial
    property :name, String

  end  

  class Classificationlevel
    include DataMapper::Resource

    property :id, Serial
    property :levelcode, String
    property :name, String

  end

end

这些代码用于创建和填充表格

user = Core_authentication::User.create
user.username = params['username']
user.password = params['password']
user.email = params['email']
#user.save

group = Core_authentication::Group.first_or_create(:name => params['group'])
group.name = params['group']
group.save

user.Group << group

user=Core\u身份验证：：user.create
user.username=params['username']
user.password=params['password']
user.email=params['email']
#user.save
group=Core\u身份验证：：group.first\u或\u create（：name=>params['group']）
group.name=params['group']
组。保存
经过多次尝试，user.Group修复了该问题
它是通过使用
hasn，：model，through=>Resource
并将其放置在两个模型类中来修复的

这将创建一个包含两个资源ID的联接表，这里是一个小示例

module Core_authentication

  class User
    include DataMapper::Resource

    property :id, Serial
    property :username, String, :required => true, :unique => true  
    property :password, BCryptHash, :required => true 
    property :email, String, :format => :email_address, :required => true
    property :created_at, DateTime
    property :updated_at, DateTime

    #Creating join tables to link to group and person information
    has n, :persons, :through => Resource

  end 

  class Person
    include DataMapper::Resource

    property :id, Serial
    property :firstname, String
    property :lastname, String, :required => true
    property :adress, String
    property :postcode, String, :length => 6, :required => true
    property :telefoon, String
    property :created_at, DateTime
    property :updated_at, DateTime

    has n, :users, :through => Resource

  end  

然后只需创建两个对象，然后通过

user.persons << person

user.persons在多次尝试后修复了该问题
它是通过使用
hasn，：model，through=>Resource
并将其放置在两个模型类中来修复的

这将创建一个包含两个资源ID的联接表，这里是一个小示例

module Core_authentication

  class User
    include DataMapper::Resource

    property :id, Serial
    property :username, String, :required => true, :unique => true  
    property :password, BCryptHash, :required => true 
    property :email, String, :format => :email_address, :required => true
    property :created_at, DateTime
    property :updated_at, DateTime

    #Creating join tables to link to group and person information
    has n, :persons, :through => Resource

  end 

  class Person
    include DataMapper::Resource

    property :id, Serial
    property :firstname, String
    property :lastname, String, :required => true
    property :adress, String
    property :postcode, String, :length => 6, :required => true
    property :telefoon, String
    property :created_at, DateTime
    property :updated_at, DateTime

    has n, :users, :through => Resource

  end  

然后只需创建两个对象，然后通过

user.persons << person

user.persons的
参数不应该是复数吗？例如，
有n，：person*s*，：through=>resource*s*
。另外，
所属的装饰在哪里？难道
有n个
参数不应该是复数吗？例如，
有n，：person*s*，：through=>resource*s*
。另外，
所属的装饰在哪里？