Sql 如何构造子查询/CTE以替换嵌套的聚合函数？

我试图找出每个“百分比”存储桶的“金额”值百分比

示例数据：

amt | pct
5   | .5
10  | .6
15  |  1
20  | .8

预期结果：

pctAMT | PCTrange
.3     | <65
.4     | 75-84
.3     | 100+

pctAMT | PCTrange
.3 |我希望这样：

SELECT (CASE WHEN percent < 0.65 then '  <65'
             WHEN percent < 0.75 then '65-74'
             WHEN percent < 0.85 then '75-84'
             WHEN percent < 0.95 then '85-94'
             WHEN percent < 1.00 then '95-99'
             ELSE ' 100+'
        END) as PCTrange,
       SUM(amt)/ SUM(SUM(amt)) OVER () AS pctAMT
FROM table
WHERE date = '2016-04-01'
GROUP BY PCTrange
ORDER BY PCTrange;

SELECT（百分比<0.65时的大小写），然后用正在使用的数据库标记您的问题。您的错误看起来像Netezza，因此我添加了该标记。
SELECT (CASE WHEN percent < 0.65 then '  <65'
             WHEN percent < 0.75 then '65-74'
             WHEN percent < 0.85 then '75-84'
             WHEN percent < 0.95 then '85-94'
             WHEN percent < 1.00 then '95-99'
             ELSE ' 100+'
        END) as PCTrange,
       SUM(amt)/ SUM(SUM(amt)) OVER () AS pctAMT
FROM table
WHERE date = '2016-04-01'
GROUP BY PCTrange
ORDER BY PCTrange;