Sql oracle中的每周分组

我需要从OracleSQL按周分组，下表包含数量，并分为几个类别。我需要得到每个类别的每周数量总和

来源表：数量\单位明细

date (mm/dd/yyyy)   quantity    category
10/1/2018             4            A
10/2/2018             4            B
10/3/2018             5            C
10/4/2018             7            A
10/5/2018             2            A
10/6/2018             2            B
10/7/2018             1            C
10/8/2018             0            C
10/9/2018             8            C
10/10/2018            2            B
10/11/2018            4            D
10/12/2018            6            B
10/13/2018            8            D
10/14/2018            9            C
10/15/2018            11           A

结果表应如下所示：

week start date (dd/mm/yyyy)    category    sum of quantity
01/10/2018 to 07/10/2018            A            13
01/10/2018 to 07/10/2018            B             6
01/10/2018 to 07/10/2018            C             6
01/10/2018 to 07/10/2018            D             0
08/10/2018 to 14/10/2018            A             0
08/10/2018 to 14/10/2018            B             8
08/10/2018 to 14/10/2018            C            17
08/10/2018 to 14/10/2018            D            12
15/10/2018 to 21/10/2018            A            11
15/10/2018 to 21/10/2018            B             0
15/10/2018 to 21/10/2018            C             0
15/10/2018 to 21/10/2018            D             0

您可以使用：

select to_char(trunc(min(min_Date),'iw'),'dd/mm/yyyy')||' to '
     ||to_char(trunc(min(min_Date),'iw')+6,'dd/mm/yyyy') as week,
    as week,
       category, sum(sum_of_quantity) as sum_of_quantity
  from
(
  select to_char(myDate,'iw') as week, min(myDate) as min_Date, max(myDate) max_Date, 
         category, sum(quantity) as sum_of_quantity
    from quantity_details
   group by to_char(myDate,'iw'), category
) 
group by week, category
order by week, category;

WEEK                     CATEGORY  SUM_OF_QUANTITY
------------------------ --------  ---------------
01/10/2018 to 07/10/2018    A            13
01/10/2018 to 07/10/2018    B             6
01/10/2018 to 07/10/2018    C             6
08/10/2018 to 14/10/2018    B             8
08/10/2018 to 14/10/2018    C            17
08/10/2018 to 14/10/2018    D            12
15/10/2018 to 21/10/2018    A            11

如果您希望将所有类别及其数量包括为

zero

，即使它们不匹配，我们也应该更加努力地使用

左连接的贡献作为：

select to_char(trunc(q1.min_Date,'iw'),'dd/mm/yyyy')||' to '
     ||to_char(trunc(q1.min_Date,'iw')+6,'dd/mm/yyyy') as week,
       q1.category,
       nvl(q2.quantity,0) as sum_of_quantity
  from
( 
  select to_char(d1.myDate,'iw') as week, min(d1.myDate) as min_Date,
         max(d1.myDate) max_Date, d2.category
    from quantity_details d1 
   cross join ( select category from quantity_details group by category ) d2
   group by to_char(d1.myDate,'iw'), d2.category
) q1
 left join
(
  select to_char(myDate,'iw') as week, min(myDate) as min_Date, max(myDate) max_Date, 
         category, sum(quantity) as quantity
    from quantity_details
   group by to_char(myDate,'iw'), category
) q2 on ( q1.category = q2.category and q1.week = q2.week )
 order by q1.week, q1.category;

WEEK                     CATEGORY  SUM_OF_QUANTITY
------------------------ --------  ---------------
01/10/2018 to 07/10/2018    A            13
01/10/2018 to 07/10/2018    B             6
01/10/2018 to 07/10/2018    C             6
01/10/2018 to 07/10/2018    D             0
08/10/2018 to 14/10/2018    A             0
08/10/2018 to 14/10/2018    B             8
08/10/2018 to 14/10/2018    C            17
08/10/2018 to 14/10/2018    D            12
15/10/2018 to 21/10/2018    A            11
15/10/2018 to 21/10/2018    B             0
15/10/2018 to 21/10/2018    C             0
15/10/2018 to 21/10/2018    D             0

既然您似乎需要结果集中的“零”，也许这些想法会有帮助：{1}找到所有可能的（唯一的）周x类别组合（下面查询中的子查询C）{2}找到每周的总和（下面查询中的子查询S。{3}左键加入2，这样您就可以得到没有总和的周的空值。{4}选择所需的列，并使用CASE替换空值。（使用Oracle 11和12测试，请参阅）

结果

week from/to              CATEGORY  sum of quantity
01/10/2018 to 07/10/2018  A         13
01/10/2018 to 07/10/2018  B         6
01/10/2018 to 07/10/2018  C         6
01/10/2018 to 07/10/2018  D         0
08/10/2018 to 14/10/2018  A         0
08/10/2018 to 14/10/2018  B         8
08/10/2018 to 14/10/2018  C         17
08/10/2018 to 14/10/2018  D         12
15/10/2018 to 21/10/2018  A         11
15/10/2018 to 21/10/2018  B         0
15/10/2018 to 21/10/2018  C         0
15/10/2018 to 21/10/2018  D         0

week from/to              CATEGORY  sum of quantity
01/10/2018 to 07/10/2018  A         13
01/10/2018 to 07/10/2018  B         6
01/10/2018 to 07/10/2018  C         6
01/10/2018 to 07/10/2018  D         0
08/10/2018 to 14/10/2018  A         0
08/10/2018 to 14/10/2018  B         8
08/10/2018 to 14/10/2018  C         17
08/10/2018 to 14/10/2018  D         12
15/10/2018 to 21/10/2018  A         11
15/10/2018 to 21/10/2018  B         0
15/10/2018 to 21/10/2018  C         0
15/10/2018 to 21/10/2018  D         0