Sql 如何从年龄号码中获取出生日期

使用：

使用：

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两个

DATEADD

s就足够了：

SET @YEARS=CONVERT(BIGINT,SUBSTRING( @INPUT,1,3))

SET @MONTHS=CONVERT(BIGINT,SUBSTRING( @INPUT,CHARINDEX ('M', @INPUT,1)-2,2))

SET @DAYS=CONVERT(BIGINT,SUBSTRING( @INPUT,CHARINDEX ('D', @INPUT,1)-2,2))

SET @DATE_OF_BIRTH=DATEADD(year, -@Years,
DATEADD(month, -@Months,DATEADD(day, -@Days, getDate())))
SELECT Convert(nvarchar(12),@DATE_OF_BIRTH,105)

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两个

DATEADD

s就足够了：

SET @YEARS=CONVERT(BIGINT,SUBSTRING( @INPUT,1,3))

SET @MONTHS=CONVERT(BIGINT,SUBSTRING( @INPUT,CHARINDEX ('M', @INPUT,1)-2,2))

SET @DAYS=CONVERT(BIGINT,SUBSTRING( @INPUT,CHARINDEX ('D', @INPUT,1)-2,2))

SET @DATE_OF_BIRTH=DATEADD(year, -@Years,
DATEADD(month, -@Months,DATEADD(day, -@Days, getDate())))
SELECT Convert(nvarchar(12),@DATE_OF_BIRTH,105)

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我想要上面输入参数的确切日期。请帮助我，为什么你把它标记为MySQL？我想要上面输入参数的确切日期。请帮助我，为什么你把它标记为MySQL？

SET @YEARS=CONVERT(BIGINT,SUBSTRING( @INPUT,1,3))

SET @MONTHS=CONVERT(BIGINT,SUBSTRING( @INPUT,CHARINDEX ('M', @INPUT,1)-2,2))

SET @DAYS=CONVERT(BIGINT,SUBSTRING( @INPUT,CHARINDEX ('D', @INPUT,1)-2,2))

SET @DATE_OF_BIRTH=DATEADD(year, -@Years,
DATEADD(month, -@Months,DATEADD(day, -@Days, getDate())))
SELECT Convert(nvarchar(12),@DATE_OF_BIRTH,105)

DECLARE @DATE_OF_BIRTH date 
    = DATEADD(year, -@Years, DATEADD(month, -@Months, GETDATE()))-@days