SQL不同行数和计数

我有一张这样的桌子：

Id  CookieId
--------------------------------
4   13ab1dc1bac-ef74565ea9ff5ba8
4   13b474728b3-6cf7bf445e311c59
4   13b474728b3-6cf7bf445e311c59
4   13a1b545ebf-20c86b23c91ad2c5
4   13a1b545ebf-20c86b23c91ad2c5

SELECT ID, COUNT(DISTINCT CookieId) AS `COUNT`
FROM Table1
GROUP BY ID

结果应仅为不同的行：

Id  CookieId
--------------------------------
4   13ab1dc1bac-ef74565ea9ff5ba8
4   13b474728b3-6cf7bf445e311c59
4   13a1b545ebf-20c86b23c91ad2c5

如果我能得到更多的行数也会很好

Id      count(CookieId)
-----------------------
4       3

---

如何实现这两个结果？

要在结果中获得唯一记录，请使用以下方法：

SELECT DISTINCT ID, CookieId
FROM Table1

结果:

| ID |                     COOKIEID |
-------------------------------------
|  4 | 13ab1dc1bac-ef74565ea9ff5ba8 |
|  4 | 13b474728b3-6cf7bf445e311c59 |
|  4 | 13a1b545ebf-20c86b23c91ad2c5 |

| ID | COUNT |
--------------
|  4 |     3 |

要获取唯一

CookieId的计数

请使用

DISTINCT

内部

count

函数，如下所示：

Id  CookieId
--------------------------------
4   13ab1dc1bac-ef74565ea9ff5ba8
4   13b474728b3-6cf7bf445e311c59
4   13b474728b3-6cf7bf445e311c59
4   13a1b545ebf-20c86b23c91ad2c5
4   13a1b545ebf-20c86b23c91ad2c5

SELECT ID, COUNT(DISTINCT CookieId) AS `COUNT`
FROM Table1
GROUP BY ID

结果:

| ID |                     COOKIEID |
-------------------------------------
|  4 | 13ab1dc1bac-ef74565ea9ff5ba8 |
|  4 | 13b474728b3-6cf7bf445e311c59 |
|  4 | 13a1b545ebf-20c86b23c91ad2c5 |

| ID | COUNT |
--------------
|  4 |     3 |

---

要获取结果中的唯一记录，请使用以下命令：

SELECT DISTINCT ID, CookieId
FROM Table1

结果:

| ID |                     COOKIEID |
-------------------------------------
|  4 | 13ab1dc1bac-ef74565ea9ff5ba8 |
|  4 | 13b474728b3-6cf7bf445e311c59 |
|  4 | 13a1b545ebf-20c86b23c91ad2c5 |

| ID | COUNT |
--------------
|  4 |     3 |

要获取唯一

CookieId的计数

请使用

DISTINCT

内部

count

函数，如下所示：

Id  CookieId
--------------------------------
4   13ab1dc1bac-ef74565ea9ff5ba8
4   13b474728b3-6cf7bf445e311c59
4   13b474728b3-6cf7bf445e311c59
4   13a1b545ebf-20c86b23c91ad2c5
4   13a1b545ebf-20c86b23c91ad2c5

SELECT ID, COUNT(DISTINCT CookieId) AS `COUNT`
FROM Table1
GROUP BY ID

结果:

| ID |                     COOKIEID |
-------------------------------------
|  4 | 13ab1dc1bac-ef74565ea9ff5ba8 |
|  4 | 13b474728b3-6cf7bf445e311c59 |
|  4 | 13a1b545ebf-20c86b23c91ad2c5 |

| ID | COUNT |
--------------
|  4 |     3 |

您可以尝试此查询

select Id,count(CookieId) from table_name group by CookieId;

您可以尝试此查询

select Id,count(CookieId) from table_name group by CookieId;

---

首先选择使用的不同值

SELECT DISTINCT CookieId, Id 
FROM YourTable;
GO

SELECT Id, COUNT(DISTINCT CookieId)
FROM YourTable;
GROUP BY Id;
GO

这只是因为在两列中有重复项才起作用。要获取这些值的计数，请使用

SELECT DISTINCT CookieId, Id 
FROM YourTable;
GO

SELECT Id, COUNT(DISTINCT CookieId)
FROM YourTable;
GROUP BY Id;
GO

---

我希望这有帮助。

首先选择使用的不同值

SELECT DISTINCT CookieId, Id 
FROM YourTable;
GO

SELECT Id, COUNT(DISTINCT CookieId)
FROM YourTable;
GROUP BY Id;
GO

    SELECT  DISTINCT(`CookieId`),Id, COUNT(CookieId) FROM
 `tablename` GROUP BY `CookieId`

这只是因为在两列中有重复项才起作用。要获取这些值的计数，请使用

SELECT DISTINCT CookieId, Id 
FROM YourTable;
GO

SELECT Id, COUNT(DISTINCT CookieId)
FROM YourTable;
GROUP BY Id;
GO

我希望这有帮助

    SELECT  DISTINCT(`CookieId`),Id, COUNT(CookieId) FROM
 `tablename` GROUP BY `CookieId`