从MAX（SUM（））SQL GROUP BY获取ID

我试图从下图中得到的结果中获取PlayerID

我用来显示的查询是：

SELECT PlayerIDFK, sum(TwoPointMade) as TwoPointMade, sum(ThreePointMade) as ThreePointMAde 
FROM PlayerPerformance GROUP BY PlayerIDFK;

我还有另一个查询，在本例中返回两列总和的最大值47，这是正确的答案，但我还想得到PlayerIDFK

SELECT MAX(SUM(TwoPointMade) + SUM(ThreePointMade)) AS "Points"
FROM PlayerPerformance GROUP BY PlayerIDFK;

当我尝试使用查询获取播放器ID时，我没有得到一个组函数。这是我尝试使用的查询：

SELECT PlayerIDFK, MAX(SUM(TwoPointMade) + SUM(ThreePointMade)) AS "Points"
FROM PlayerPerformance GROUP BY PlayerIDFK;

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使用

orderby

和

rownum

（或

仅获取12c+中的前1行

：

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请仅使用与您使用的技术相匹配的标签。是，还是？这不是

分组依据的作业<代码>分组依据

不从表中返回行。它生成新行。第5行错误：ORA-00935:组函数嵌套太深请尝试按顺序删除sum（）包装。

SELECT *
FROM (SELECT PlayerIDFK, sum(TwoPointMade) as TwoPointMade, sum(ThreePointMade) as ThreePointMAde 
      FROM PlayerPerformance
      GROUP BY PlayerIDFK
      ORDER BY ( sum(TwoPointMade) + sum(ThreePointMade) ) desc
     ) pp
WHERE rownum = 1;