按SQL语句分组-获取超过5个城市的国家/地区

我正试图吸引超过5个城市的国家

表：

城市

城市id、城市、国家id、上次更新

国家

国家id、国家、上次更新

我想我很快就能明白这一点，但我还没完全明白。有什么建议吗

SELECT DISTINCT country
FROM country C, city O
WHERE O.country_id = C.country_id AND O.country_id
 IN (SELECT country_id FROM city group by country_id having count(country_id) > 5);

你可以这样试试

select countryid, count(distinct city_id) from country c join city ct c.country_id=ct.country_id
group by countryid 
having count(distinct city_id) > 5

---

下面的查询适用于您的要求

   SELECT C.country
     FROM country C
    INNER JOIN
          city O
       ON  O.country_id = C.country_id 
   GROUP BY C.country
   HAVING count(distinct O.city)>5;

---

你应该读这篇文章。使用计数（城市）以防其为空+但是我给了我1张。是的，OP没有具体说明。您甚至可能需要使用

count（distinct city）

以防出现重复点。。。不管怎样，这对他们来说可能更好（不同的是）

select countryid, count(distinct city_id) from country c join city ct c.country_id=ct.country_id
group by countryid 
having count(distinct city_id) > 5

SELECT DISTINCT 
       country
FROM   country C
WHERE EXISTS (SELECT COUNT(DISTINCT city_id)
              FROM city CITY
              WHERE CITY.country_id = C.country_id
              GROUP BY CITY.country_id 
              HAVING COUNT(DISTINCT city_id) > 5);

   SELECT C.country
     FROM country C
    INNER JOIN
          city O
       ON  O.country_id = C.country_id 
   GROUP BY C.country
   HAVING count(distinct O.city)>5;