Sql 在提取数据库中重复行的查询结果中仅选择较新的记录

Sql 在提取数据库中重复行的查询结果中仅选择较新的记录,sql,postgresql,subquery,where-clause,greatest-n-per-group,Sql,Postgresql,Subquery,Where Clause,Greatest N Per Group,我有一个db,在这里我可以有多个行,具有相同的字段“aid”(这是一种相同项的历史变更日志)。 通过以下查询,我提取了按降序日期排序的具有相同辅助功能的行: select aid,data_ril,specie,id from scu.censimento t1 where (select count(*) from scu.censimento t2 where t1.aid = t2.aid) > 1 order by aid, data_ril desc 这应该是与父层相关的子表(

我有一个db,在这里我可以有多个行,具有相同的字段“aid”(这是一种相同项的历史变更日志)。 通过以下查询,我提取了按降序日期排序的具有相同辅助功能的行:

select aid,data_ril,specie,id from scu.censimento t1
where (select count(*) from scu.censimento t2
where t1.aid = t2.aid) > 1
order by aid, data_ril desc
这应该是与父层相关的子表(由只显示最新aid记录的postgres物化视图生成),我得到的结果如下:

    +------+------------+--------+------+
    | aid  | data_ril   | specie | id   |
    +------+------------+--------+------+
    | 349  | 2020-06-18 | 35     | 349  |
    +------+------------+--------+------+
    | 349  | 2020-06-17 | 35     | 2004 |
    +------+------------+--------+------+
    | 700  | 2020-08-07 | 58     | 700  |
    +------+------------+--------+------+
    | 700  | 2020-07-06 | 58     | 2006 |
    +------+------------+--------+------+
    | 700  | 2020-05-02 | 15     | 1956 |
    +------+------------+--------+------+
    | 1316 | 2020-09-02 | 1      | 1316 |
    +------+------------+--------+------+
    | 1316 | 2020-08-27 | 1      | 2005 |
    +------+------------+--------+------+
    | 1317 | 2020-09-02 | 2      | 1317 |
    +------+------------+--------+------+
    | 1317 | 2020-08-27 | 2      | 1996 |
    +------+------------+--------+------+
    | 1481 | 2020-12-03 | 21     | 2112 |
    +------+------------+--------+------+
    | 1481 | 2020-09-08 | 49     | 1481 |
    +------+------------+--------+------+
    | 1492 | 2020-09-28 | 6      | 1492 |
    +------+------------+--------+------+
    | 1492 | 2020-09-08 | 6      | 1999 |
    +------+------------+--------+------+
    | 1688 | 2020-11-03 | 72     | 1688 |
    +------+------------+--------+------+
    | 1688 | 2020-10-08 | 72     | 2000 |
    +------+------------+--------+------+
我想知道修改上述查询的SQL语法,以便显示除日期最新的行以外的所有重复行,这样我就可以得到如下表:

+------+------------+--------+------+
| aid  | data_ril   | specie | id   |
+------+------------+--------+------+
| 349  | 2020-06-17 | 35     | 2004 |
+------+------------+--------+------+
| 700  | 2020-07-06 | 58     | 2006 |
+------+------------+--------+------+
| 700  | 2020-05-02 | 15     | 1956 |
+------+------------+--------+------+
| 1316 | 2020-08-27 | 1      | 2005 |
+------+------------+--------+------+
| 1317 | 2020-08-27 | 2      | 1996 |
+------+------------+--------+------+
| 1481 | 2020-09-08 | 49     | 1481 |
+------+------------+--------+------+
| 1492 | 2020-09-08 | 6      | 1999 |
+------+------------+--------+------+
| 1688 | 2020-10-08 | 72     | 2000 |
+------+------------+--------+------+

提前感谢。

您可以使用窗口功能完成此操作。其思想是通过降序排列具有相同的
aid
的记录,然后过滤出每组的最高记录

select aid, data_ril, specie, id
from (
    select t.*, 
        row_number() over(partition by aid order by data_ril desc) rn
    from mytable t 
) t
where rn > 1
order by aid, data_ril