Sql MS access 2016中外部应用的等效命令

为了获得新的信息，我尝试与表关联，但似乎在MS access中没有外部应用程序。这是我的密码：

    SELECT *
FROM [pred-predi_calculo-presi]
  OUTER APPLY
    ( SELECT TOP 1 [snptc_histo].POSICIONBUS
      FROM [snptc_histo]
      WHERE [snptc_histo].PATENTEBUS = [pred-predi_calculo-presi].PATENTE
        AND [snptc_histo].horaConsulta < [pred-predi_calculo-presi].'pasadaReal'
      ORDER BY [snptc_histo].horaConsulta DESC
    ) AS p
  OUTER APPLY
    ( SELECT TOP 1 [snptc_histo].POSICIONBUS
      FROM [snptc_histo]
      WHERE [snptc_histo].PATENTEBUS = [pred-predi_calculo-presi].PATENTE
        AND [snptc_histo].horaConsulta >= [pred-predi_calculo-presi].'pasadaReal'
      ORDER BY [snptc_histo].horaConsulta ASC
    ) AS n ;

snptc_历史：

PATENTEBUS  POSICIONBUS horaConsulta
WA-9114     0           17:15:52
CJRW-83     3,64        17:15:52
ZN-3967     0,26        17:15:50
BJFV-89     11,06       17:15:51
BJFS-92     32,866      17:15:51
FLXJ-30     19,74       17:15:51
BJFR-52     9,55        17:15:50
CJRW-52     24,67       17:15:50
BJFR-94     14,75       17:15:49
CJRT-63     16,02       17:15:49

---

在Access中，这不是最简单的操作，但请尝试以下操作

Query1-中间查询，查找每个PatentBus值小于pasadaReal的最大horaConsulta值：

SELECT s.PATENTEBUS, MAX(horaConsulta) AS MaxHoraConsulta
FROM [snptc_histo] AS s 
INNER JOIN [pred-predi_calculo-presi] AS p ON s.PATENTEBUS = p.PATENTE
WHERE s.horaConsulta < p.pasadaReal
GROUP BY s.PATENTEBUS

SELECT s.PATENTEBUS, s.POSICIONBUS
FROM [snptc_histo] AS s 
INNER JOIN Query1 AS q ON s.PATENTEBUS = q.PATENTEBUS AND s.horaConsulta = q.MaxHoraConsulta

现在创建类似的查询，以查找每个PatentBus值大于或等于pasadaReal的min Horaconsorta值及其关联的PosiConbus值：

SELECT s.PATENTEBUS, MAX(horaConsulta) AS MaxHoraConsulta
FROM [snptc_histo] AS s 
INNER JOIN [pred-predi_calculo-presi] AS p ON s.PATENTEBUS = p.PATENTE
WHERE s.horaConsulta < p.pasadaReal
GROUP BY s.PATENTEBUS

SELECT s.PATENTEBUS, s.POSICIONBUS
FROM [snptc_histo] AS s 
INNER JOIN Query1 AS q ON s.PATENTEBUS = q.PATENTEBUS AND s.horaConsulta = q.MaxHoraConsulta

问题3

SELECT s.PATENTEBUS, MIN(horaConsulta) AS MinHoraConsulta
FROM [snptc_histo] AS s 
INNER JOIN [pred-predi_calculo-presi] AS p ON s.PATENTEBUS = p.PATENTE
WHERE s.horaConsulta >= p.pasadaReal
GROUP BY s.PATENTEBUS

问题4

SELECT s.PATENTEBUS, s.POSICIONBUS
FROM [snptc_histo] AS s 
INNER JOIN Query3 AS q ON s.PATENTEBUS = q.PATENTEBUS AND s.horaConsulta = q.MinHoraConsulta

现在，您的最终查询变成：

SELECT p.*, q2.POSICIONBUS, q4.POSICIONBUS
FROM ([pred-predi_calculo-presi] AS p
LEFT JOIN Query2 AS q2 ON p.PATENTE = q2.PATENTEBUS)
LEFT JOIN Query4 AS q4 ON p.PATENTE = q4.PATENTEBUS

---

Query1不起作用；看起来像“WHERE s.horaConsulta[pred-predi_calculo-presi]。'pasadaReal'？我假设这应该写成

[pred-predi_calculo-presi].[pasadaReal]

，换句话说，我假设

pasadaReal

是

[pred-predi_calculo-presi]

表中的一列。这是错误的吗？是的，但正如我所说的，WHERE作用于SELECT，所以它看到它正在写入的行中的[snptc_histo]列，而不是其他表中的列，因为它不知道要查看哪一行WHERE也可以作用于JOIN。我根据您的原始帖子重新创建了最小的表结构，该查询按预期工作。你能发布你的表结构和样本数据吗？我添加了样本数据