Sql 选择具有相同属性1和不同属性2的行

我有一张桌子

+----+------+---------+
| ID | CODE | COUNTRY |
+----+------+---------+
|  1 |   05 | France  |
|  2 |   05 | France  |
|  3 |   06 | Germany |
|  4 |   07 | France  |
|  5 |   07 | Italy   |
+----+------+---------+

我需要选择代码相同但国家不同的行。 因此，结果应该是：

+------+---------+
| CODE | COUNTRY |
+------+---------+
|   07 | France  |
|   07 | Italy   |
+------+---------+

我试过了

SELECT t1.code AS code, t1.country AS country
FROM countries AS t1, countries AS t2
WHERE t1.code = t2.code
AND t1.country <> t2.country;

结果是：

+------+---------+
| CODE | COUNTRY |
+------+---------+
|   07 | Italy   |
|   07 | Italy   |
|   07 | France  |
|   07 | France  |
+------+---------+

但是应该和上面一样

我使用MS Access，因此查询应该在Access上运行

只需添加distinct

您可以使用“最小”和“最大”来识别不同国家/地区的代码，然后使用该代码选择所有行：

SELECT * FROM countries WHERE Code IN (
  SELECT Code
  FROM countries
  GROUP BY Code
  HAVING MIN(Country) < MAX(Country)
)

---

考虑选择区别有时我想知道我是否和别人一样阅读同样的问题。这是如何选择代码相同但国家不同的行的？@Damien_the_unsiver这里的键是OP query，它已经对上面示例中的表起作用了，所以只需要distinct就可以删除重复的行。结果是3条记录：法国、意大利、意大利。

SELECT DISTINCT t1.code AS code, t1.country AS country
FROM countries AS t1, countries AS t2
WHERE t1.code = t2.code
AND t1.country <> t2.country;

SELECT * FROM countries WHERE Code IN (
  SELECT Code
  FROM countries
  GROUP BY Code
  HAVING MIN(Country) < MAX(Country)
)