Sql Where语句在order by语句之后

我想通过平均值>在8处摸索之后问一下，类似这样的问题

SELECT avg(students_subject.nota) as avg, students.name
FROM students_subject
left JOIN studentsON students.id=students_subject.id_alumno
GROUP BY students_subject.id_student 
where avg > 8;

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对于引用聚合函数的条件，请使用

having

子句：

SELECT avg(students_subject.nota) as avg, students.name
FROM students_subject
left JOIN students ON students.id=students_subject.id_alumno
GROUP BY students_subject.id_student 
having avg(students_subject.nota)> 8;

---

对于引用聚合函数的条件，请使用

having

子句：

SELECT avg(students_subject.nota) as avg, students.name
FROM students_subject
left JOIN students ON students.id=students_subject.id_alumno
GROUP BY students_subject.id_student 
having avg(students_subject.nota)> 8;

---

与分组比较时使用have其中不能与聚合函数一起使用。您的查询将如下所示：

SELECT avg(students_subject.nota) as avg, students.name
FROM students_subject
left JOIN studentsON students.id=students_subject.id_alumno
GROUP BY students_subject.id_student 
HAVING avg > 8;

---

与分组比较时使用have其中不能与聚合函数一起使用。您的查询将如下所示：

SELECT avg(students_subject.nota) as avg, students.name
FROM students_subject
left JOIN studentsON students.id=students_subject.id_alumno
GROUP BY students_subject.id_student 
HAVING avg > 8;

参考站点

语法

SELECT column_name(s)
FROM table_name
WHERE condition
GROUP BY column_name(s)
HAVING condition
ORDER BY column_name(s);

范例

SELECT COUNT(CustomerID), Country
FROM Customers
GROUP BY Country
HAVING COUNT(CustomerID) > 5;

参考站点

语法

SELECT column_name(s)
FROM table_name
WHERE condition
GROUP BY column_name(s)
HAVING condition
ORDER BY column_name(s);

范例

SELECT COUNT(CustomerID), Country
FROM Customers
GROUP BY Country
HAVING COUNT(CustomerID) > 5;