Sql 带和分组

简化我有这样的东西：

select register_date,count(*)
from USER
group by register_date;

结果是：

2016-01-20  10
2016-01-21  5
2016-01-22  8

这告诉我，在第一天，10个用户注册了超过5个，第二天注册了8个。 我需要有一个注册用户总数：

2016-01-20  10
2016-01-21  15 (10+5)
2016-01-22  23 (10+5+8)

---

有什么办法吗？提前谢谢。

使用累计金额。您可以通过聚合查询执行此操作，甚至：

select register_date, count(*),
       sum(count(*)) over (order by register_date) as running_count
from USER
group by register_date
order by register_date;

---

使用累积总和。您可以通过聚合查询执行此操作，甚至：

select register_date, count(*),
       sum(count(*)) over (order by register_date) as running_count
from USER
group by register_date
order by register_date;