Sql 从select语句中的SUM返回前5名

我需要返回以下语句，但我只想返回每个销售价值的前5名….而不是所有记录

Select ID, Code, sum(Sale) as Sale from TableName
Where Code = 11
Group By ID, code

我不要这个

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也许你需要一些类似的东西：

;WITH sales (
SELECT
 id, 
 code,
 sale,
 ROW_NUMBER() OVER (PARTITION BY id, code ORDER BY sales DESC) n
FROM
 TableName
WHERE
 Code = 11
)
SELECT
 id, code, sum(sale) sale
FROM
 sales
WHERE
 n <= 5
GROUP BY
 id,
 code

通过帮助查找最后5次销售的行号和分区。那么你只和前5名相加

---

此查询返回每个id、代码组的前5名销售额之和。

如果只想返回每个组的前5名结果，可以执行以下操作：

select id, code, SUM (sale) 
from
(
    select id, code, sale, 
        ROW_NUMBER() over(partition by id, code order by sale desc) rn 
    from tablename
) v
where rn<=5
group by id, code 

with cte as 
(ID, Code, Sale,ROW_NUMBER() over(partition by  ID,
Code order by (select 0)) rownum
from TableName)
Select ID, Code, sum(Sale) as Sale from cte
Where Code = 11
and rownum<=5
Group By ID, code

with cte as 
(ID, Code, Sale,ROW_NUMBER() over(partition by  ID,
Code order by Sale desc) rownum
from TableName)
Select ID, Code, sum(Sale) as Sale from cte
Where Code = 11
and rownum<=5
Group By ID, code

如果您希望以最高工资返回每个组的前5名结果，您可以这样做：

with cte as 
(ID, Code, Sale,ROW_NUMBER() over(partition by  ID,
Code order by (select 0)) rownum
from TableName)
Select ID, Code, sum(Sale) as Sale from cte
Where Code = 11
and rownum<=5
Group By ID, code

with cte as 
(ID, Code, Sale,ROW_NUMBER() over(partition by  ID,
Code order by Sale desc) rownum
from TableName)
Select ID, Code, sum(Sale) as Sale from cte
Where Code = 11
and rownum<=5
Group By ID, code

---

前5名的总销售额，或者每个组前5名销售额的总和？我只想返回每个组前5名的结果。这标记为SQL Server，ORDER BY/LIMIT技术仅适用于MySQL。

with cte as 
(ID, Code, Sale,ROW_NUMBER() over(partition by  ID,
Code order by (select 0)) rownum
from TableName)
Select ID, Code, sum(Sale) as Sale from cte
Where Code = 11
and rownum<=5
Group By ID, code

with cte as 
(ID, Code, Sale,ROW_NUMBER() over(partition by  ID,
Code order by Sale desc) rownum
from TableName)
Select ID, Code, sum(Sale) as Sale from cte
Where Code = 11
and rownum<=5
Group By ID, code