sqlalchemy与过滤器的关系
我试图仅获取已批准的响应(暂存>1),但由于某些原因,primaryjoin中的Reply.staged>1不起作用 我对sqlAlchemy非常陌生,所以我不确定家长与远程_端的关系是什么sqlalchemy与过滤器的关系,sqlalchemy,relationships,Sqlalchemy,Relationships,我试图仅获取已批准的响应(暂存>1),但由于某些原因,primaryjoin中的Reply.staged>1不起作用 我对sqlAlchemy非常陌生,所以我不确定家长与远程_端的关系是什么 class Story(Base): __tablename__ = ’Story' id = Column(‘ID', Integer, primary_key=True) anonymous = Column(TINYINT) detail = Column('detail',St
class Story(Base):
__tablename__ = ’Story'
id = Column(‘ID', Integer, primary_key=True)
anonymous = Column(TINYINT)
detail = Column('detail',String, js_name='detail')
summary = Column('summary',String, js_name='questionSummary')
user_id = Column('uid', Integer, ForeignKey('rlUser.uid'), js_name='userId')
user = relationship("User")
inspire_id = Column('inspireID', Integer, js_name='inspireId')
staged = Column(TINYINT)
class Reply(Base):
__tablename__ = 'Reply'
id = Column('replyID', Integer, primary_key=True)
parent_id = Column('parentID', Integer, ForeignKey('rlReply.replyID'),js_name='parentId')
user_id = Column('userID', Integer, js_name='userId')
detail = Column(String, js_name='detail')
reply_date = Column('replyDate', TIMESTAMP, js_name='replyDate')
expertise_type = Column('expertiseType', Integer, js_name='expertiseType')
status = Column(Integer)
staged = Column(Integer)
story = relationship(“Story",primaryjoin='and_(Reply.story_id == Story.id, Reply.parent_id==0, Reply.staged>1)', backref=backref("replies", uselist=True ))
parent = relationship('Reply',primaryjoin='and_(Reply.parent_id==Reply.id, Reply.staged>1)', backref='responses', remote_side='Reply.id', viewonly=True, uselist=True)
def __init__(self):
self.staged = constants.POST_QUEUE_STATUS['STAGED']
@property
def reply_count(self):
return len(self.responses)
story.replies的where子句:
其中Reply
rushlineID
=%s和Reply
parentID
=%s和Reply
.staged>%s
parms sqlalchemy.engine.base.engine(110L,0,1)
然而,这是完美的:
故事的where子句。答复[0]。答复:
其中Reply
parentID
=%s和%s>%s
参数是sqlalchemy.engine.base.engine(68L,2,1)
我需要的是Reply
parentID
=%s和Reply
.staged>%s和%s>%s的位置
sqlalchemy.engine.base.engine(68L,1,2,1)我必须承认,这是一个神奇的咒语,我经历了很多尝试和错误。以下是相关位:
parent_id = RlColumn('parentID', Integer,
ForeignKey('rlReply.replyID'),
js_name='parentId')
parent = RlRelationship('Reply',
primaryjoin='and_(Reply.parent_id==remote(Reply.id),Reply.flagged_status <2)',
remote_side=id, uselist=True,
foreign_keys=parent_id, backref='replies')
parent\u id=RlColumn('parentID',Integer,
ForeignKey('rlReply.replyID'),
js_name='parentId')
parent=RlRelationship('Reply',
primaryjoin='和\(Reply.parent\u id==remote(Reply.id),Reply.flagged\状态