Sqlalchemy Alembic不生成复合主键

Sqlalchemy Alembic不生成复合主键,sqlalchemy,alembic,Sqlalchemy,Alembic,我有一个SQLAlchemy模型,比如- class UserFavPlace(db.Model): # This model stores the feedback from the user whether he has # faved a place or not __tablename__ = u'user_fav_places' id = db.Column(db.Integer, primary_key = True) public_plac

我有一个SQLAlchemy模型,比如-

class UserFavPlace(db.Model):
    # This model stores the feedback from the user whether he has
    # faved a place or not
    __tablename__ = u'user_fav_places'

    id = db.Column(db.Integer, primary_key = True)
    public_place_id = db.Column(db.Integer, db.ForeignKey(u'public_places.id'))
    user_id = db.Column(db.Integer, db.ForeignKey(u'users.user_id'))
    fav = db.Column(db.Boolean)
    updated_time = db.Column(db.DateTime)

    place = relationship(u'PublicPlace', backref = u'user_fav_places')
    user = relationship(u'User', backref = u'user_fav_places')
然后我把这个模型改成如下-

class UserFavPlace(db.Model):
    # This model stores the feedback from the user whether he has
    # faved a place or not
    __tablename__ = u'user_fav_places'

    public_place_id = db.Column(db.Integer, db.ForeignKey(u'public_places.id'),
            primary_key = True)
    user_id = db.Column(db.Integer, db.ForeignKey(u'users.user_id'),
            primary_key = True)
    fav = db.Column(db.Boolean)
    updated_time = db.Column(db.DateTime)

    place = relationship(u'PublicPlace', backref = u'user_fav_places')
    user = relationship(u'User', backref = u'user_fav_places')
但是,Alembic没有生成正确的升级和降级语句。似乎它没有添加新引入的主键约束

def upgrade():
    ### commands auto generated by Alembic - please adjust! ###
    op.drop_column('user_fav_places', 'id')
    ### end Alembic commands ###


def downgrade():
    ### commands auto generated by Alembic - please adjust! ###
    op.add_column('user_fav_places', sa.Column('id', mysql.INTEGER(display_width=11), nullable=False))
    ### end Alembic commands ###

我不知道如何添加这个

我发现自动生成在检测主键/外键更改方面非常糟糕。这没关系,通常你还是想定制它们

我还没有创建复合主键,但看起来这应该可以根据文档进行操作:

但是,您可能会遇到另一个问题,我在这里写到:

在alembic的较新版本中可能已经修复了这一问题,但它可能不允许您在现有表上创建主键(有关原因,请参阅上面的答案)。如果发生这种情况,您可以自己设计SQL并使用op.execute运行它


希望有帮助

更正了对Alembic文档的引用:顺便说一下,如果数据库中已有数据,请确保没有重复。如果有,请前往
op.create_primary_key(
        "pk_user_fav_places", "user_fav_places",
        ["public_place_id", "user_id"]
    )