Stored procedures PLSQL过程需要花费大量时间来执行
我有一个OraclePLSQL过程，它有一个父游标和两个子游标，在主体中参照父游标值创建 当我运行SQL语句direclt时，它会立即返回结果。然而，当我将它们放入PLSQL过程中时，它会无休止地运行Stored procedures PLSQL过程需要花费大量时间来执行,stored-procedures,plsql,oracle11g,oracle10g,oracle-sqldeveloper,Stored Procedures,Plsql,Oracle11g,Oracle10g,Oracle Sqldeveloper,我有一个OraclePLSQL过程，它有一个父游标和两个子游标，在主体中参照父游标值创建 当我运行SQL语句direclt时，它会立即返回结果。然而，当我将它们放入PLSQL过程中时，它会无休止地运行 CREATE OR REPLACE PROCEDURE SENDTASKREMINDER AS l_html VARCHAR2(32767); r_html VARCHAR2(32767); l_exst NUMBER; ow
CREATE OR REPLACE PROCEDURE SENDTASKREMINDER
AS
l_html VARCHAR2(32767);
r_html VARCHAR2(32767);
l_exst NUMBER;
ownerId NUMBER;
CURSOR OwnerCursor IS SELECT DISTINCT TASK_OWNER_ID FROM TASKS
WHERE to_char(TASK_START_DATE, 'DD-MON-YY') >= to_char(SYSDATE, 'DD-MON-YY') AND to_char(TASK_DUE_DATE, 'DD-MON-YY') <= to_char(SYSDATE, 'DD-MON-YY')
UNION
SELECT DISTINCT TASK_OWNER_ID FROM TASKS
WHERE to_char(TASK_START_DATE, 'DD-MON-YY') > to_char(SYSDATE, 'DD-MON-YY');
BEGIN
l_html := '<html>
<head>
<title>Task Reminder</title>
</head>
<body>';
r_html := l_html;
/* Get Pending Tasks */
OPEN OwnerCursor;
LOOP
FETCH OwnerCursor INTO ownerId;
r_html := l_html;
SELECT COUNT(*) INTO l_exst FROM TASKS
WHERE TASK_OWNER_ID = ownerId AND to_char(TASK_START_DATE, 'DD-MON-YY') >= to_char(SYSDATE, 'DD-MON-YY') AND to_char(TASK_DUE_DATE, 'DD-MON-YY') <= to_char(SYSDATE, 'DD-MON-YY');
IF l_exst > 0
THEN
r_html := r_html || '<h1>Your current pending tasks</h1><table><tr><th>Task Name</th><th>Description</th><th>Due Date</th></tr>';
FOR PendingCursor IN (SELECT PK_TASK_ID, TASK_NAME, TASK_DESCRIPTION, TASK_START_DATE, TASK_DUE_DATE FROM TASKS
WHERE TASK_OWNER_ID = ownerId AND to_char(TASK_START_DATE, 'DD-MON-YY') >= to_char(SYSDATE, 'DD-MON-YY') AND to_char(TASK_DUE_DATE, 'DD-MON-YY') <= to_char(SYSDATE, 'DD-MON-YY'))
LOOP
r_html := r_html || '<tr><td>' || PendingCursor.TASK_NAME || '</td><td>' || PendingCursor.TASK_DESCRIPTION || '</td><td>' || PendingCursor.TASK_DUE_DATE ||'</td></tr>';
END LOOP;
r_html := r_html || '</table>';
END IF;
SELECT COUNT(*) INTO l_exst FROM TASKS
WHERE TASK_OWNER_ID = ownerId AND to_char(TASK_START_DATE, 'DD-MON-YY') > to_char(SYSDATE, 'DD-MON-YY') ;
IF l_exst > 0
THEN
r_html := r_html || '<h1>Your future tasks</h1><table><tr><th>Task Name</th><th>Description</th><th>Due Date</th></tr>';
FOR FutureCursor IN (SELECT PK_TASK_ID, TASK_NAME, TASK_DESCRIPTION, TASK_START_DATE, TASK_DUE_DATE FROM TASKS
WHERE TASK_OWNER_ID = ownerId AND to_char(TASK_START_DATE, 'DD-MON-YY') > to_char(SYSDATE, 'DD-MON-YY') )
LOOP
r_html := r_html || '<tr><td>' || FutureCursor.TASK_NAME || '</td><td>' || FutureCursor.TASK_DESCRIPTION || '</td><td>' || FutureCursor.TASK_DUE_DATE ||'</td></tr>';
END LOOP;
r_html := r_html || '</table>';
END IF;
r_html := r_html || '</body></html>';
send_mail(p_to => 'XXX.XXX@xxx.com',
p_from => 'fromemail@xxx.com',
p_subject => 'Your Pending and Future tasks for OwnerId' || ownerId,
p_text_msg => 'text msg is not yet created',
p_html_msg => r_html,
p_smtp_host => 'localhost');
END LOOP;
CLOSE OwnerCursor;
END;
/
FETCH Ownercursor into ownerId;
EXIT WHEN Ownercursor%NOTFOUND;
FETCH Ownercursor into ownerId;
EXIT WHEN Ownercursor%NOTFOUND;
FETCH Ownercursor into ownerId;
EXIT WHEN Ownercursor%NOTFOUND;
FETCH Ownercursor into ownerId;
EXIT WHEN Ownercursor%NOTFOUND;
我没有看到任何无休止的循环。您是否在独立过程中测试了发送邮件的呼叫？它可能挂在那里 where子句中还有一个逻辑缺陷。您使用的TO_CHAR函数错误。这：
到charTASK开始日期，'DD-MON-YY'>=到charSYSDATE，'DD-MON-YY'和到charTASK到期日期，'DD-MON-YY'=系统日期和任务到期日期我没有看到任何无休止的循环。您是否在独立过程中测试了发送邮件的呼叫？它可能挂在那里 where子句中还有一个逻辑缺陷。您使用的TO_CHAR函数错误。这：
到charTASK开始日期，'DD-MON-YY'>=到charSYSDATE，'DD-MON-YY'和到charTASK到期日期，'DD-MON-YY'=系统日期和任务到期日期我没有看到任何无休止的循环。您是否在独立过程中测试了发送邮件的呼叫？它可能挂在那里 where子句中还有一个逻辑缺陷。您使用的TO_CHAR函数错误。这：
到charTASK开始日期，'DD-MON-YY'>=到charSYSDATE，'DD-MON-YY'和到charTASK到期日期，'DD-MON-YY'=系统日期和任务到期日期我没有看到任何无休止的循环。您是否在独立过程中测试了发送邮件的呼叫？它可能挂在那里 where子句中还有一个逻辑缺陷。您使用的TO_CHAR函数错误。这：
到charTASK开始日期，'DD-MON-YY'>=到charSYSDATE，'DD-MON-YY'和到charTASK到期日期，'DD-MON-YY'=系统日期和任务到期日期Wow。从哪里开始。Diederikh和Scott讨论了几个突出的问题，但仔细看代码，有很多是没有意义的 首先，当前任务的开始日期是过去还是现在，到期日期是将来还是现在？将来的任务是否在将来有开始日期？如果是这样的话，你的比较就全错了。根据您的逻辑，当前任务的开始日期为将来或现在，到期日期为过去或现在 第二，有五个！需要查询并访问数据库的位置。没有理由不能用初始光标读入您需要的所有内容。然后根据需要进行分析和处理 还有很多其他地方我会提出建议。我不想列出所有的代码，所以我只想包括代码。你可以接受我的小建议，也可以不接受，但一定要验证你的约会逻辑，不要频繁地访问数据库。在执行一次磁盘访问所需的时间内，可以执行数千行代码。它仍然没有我希望的生产代码那么完美，但已经足够让您开始了。而且，虽然我不能访问您的表，但它应该可以工作
create or replace PROCEDURE SENDTASKREMINDER AS
l_html VARCHAR2(100);
r_html VARCHAR2(32767);
C_header varchar2( 40 ) := '<h1>Your current pending tasks</h1>';
F_header varchar2( 32 ) := '<h1>Your future tasks</h1>';
EndHeader varchar2( 80 ) := '<table><tr><th>Task Name</th><th>Description</th><th>Due Date</th></tr>';
EndFooter varchar2( 32 ) := '</table></body></html>';
PrevOwnerId int := -1; -- Must not be a valid OwnerID
C_count int := 0;
F_count int := 0;
l_today date := Trunc( SysDate );
CURSOR OwnerCursor IS
SELECT TASK_OWNER_ID, PK_TASK_ID, TASK_NAME, TASK_DESCRIPTION, TASK_START_DATE, TASK_DUE_DATE
FROM TASKS
WHERE (TASK_START_DATE <= l_today and TASK_DUE_DATE >= l_today)
or TASK_START_DATE > l_today
order by TASK_OWNER_ID, TASK_START_DATE; -- So first the Current then Future tasks
BEGIN
l_html := '<html><head><title>Task Reminder</title></head><body>';
/* Get all Tasks */
for OwnerRec in OwnerCursor LOOP
if OwnerRec.TASK_OWNER_ID != PrevOwnerId then
-- This is the first record for this owner. Unless it's also the first record of the loop,
-- close the html and send the email.
if C_count > 0 or F_count > 0 then
r_html := r_html || EndFooter;
end if;
send_mail(p_to => 'XXX.XXX@xxx.com',
p_from => 'fromemail@xxx.com',
p_subject => 'Your Pending and Future tasks for OwnerId' || ownerId,
p_text_msg => 'text msg is not yet created',
p_html_msg => r_html,
p_smtp_host => 'localhost');
r_html := l_html;
PrevOwnerId := OwnerRec.TASK_OWNER_ID;
C_count := 0;
F_count := 0;
end if;
if OwnerRec.TASK_START_DATE <= l_today then
if C_count = 0 then
-- This is the first Current entry, write the header
r_html := r_html || C_header || EndHeader;
end if;
C_count := c_count + 1;
else
if F_count = 0 then
-- This is the first Future entry. See if there were any Current entries
if C_count > 0 then
-- There was, so terminate the Current table
r_html := r_html || '</table>';
C_count := 0;
end if;
-- Write the header
r_html := r_html || F_header || EndHeader;
end if;
F_count := F_count + 1;
end if;
-- Whether Current or Future, write the task particulars
r_html := r_html || '<tr><td>' || OwnerRec.TASK_NAME || '</td><td>' || OwnerRec.TASK_DESCRIPTION || '</td><td>' || OwnerRec.TASK_DUE_DATE ||'</td></tr>';
END LOOP;
-- The last owner has not completed processing. But maybe there were no tasks at all...
if C_count > 0 or F_count > 0 then
r_html := r_html || EndFooter;
send_mail(p_to => 'XXX.XXX@xxx.com',
p_from => 'fromemail@xxx.com',
p_subject => 'Your Pending and Future tasks for OwnerId' || ownerId,
p_text_msg => 'text msg is not yet created',
p_html_msg => r_html,
p_smtp_host => 'localhost');
dbms_output.put_line( r_html );
end if;
END;
哇。从哪里开始。Diederikh和Scott讨论了几个突出的问题，但仔细看代码，有很多是没有意义的 首先，当前任务的开始日期是过去还是现在，到期日期是将来还是现在？将来的任务是否在将来有开始日期？如果是这样的话，你的比较就全错了。根据您的逻辑，当前任务的开始日期为将来或现在，到期日期为过去或现在 第二，有五个！需要查询并访问数据库的位置。没有理由不能用初始光标读入您需要的所有内容。然后根据需要进行分析和处理 还有很多其他地方我会提出建议。我不想列出所有的代码，所以我只想包括代码。你可以接受我的小建议，也可以不接受，但一定要验证你的约会逻辑，不要频繁地访问数据库。在执行一次磁盘访问所需的时间内，可以执行数千行代码。它仍然没有我希望的生产代码那么完美，但已经足够让您开始了。而且，虽然我不能访问您的表，但它应该可以工作
create or replace PROCEDURE SENDTASKREMINDER AS
l_html VARCHAR2(100);
r_html VARCHAR2(32767);
C_header varchar2( 40 ) := '<h1>Your current pending tasks</h1>';
F_header varchar2( 32 ) := '<h1>Your future tasks</h1>';
EndHeader varchar2( 80 ) := '<table><tr><th>Task Name</th><th>Description</th><th>Due Date</th></tr>';
EndFooter varchar2( 32 ) := '</table></body></html>';
PrevOwnerId int := -1; -- Must not be a valid OwnerID
C_count int := 0;
F_count int := 0;
l_today date := Trunc( SysDate );
CURSOR OwnerCursor IS
SELECT TASK_OWNER_ID, PK_TASK_ID, TASK_NAME, TASK_DESCRIPTION, TASK_START_DATE, TASK_DUE_DATE
FROM TASKS
WHERE (TASK_START_DATE <= l_today and TASK_DUE_DATE >= l_today)
or TASK_START_DATE > l_today
order by TASK_OWNER_ID, TASK_START_DATE; -- So first the Current then Future tasks
BEGIN
l_html := '<html><head><title>Task Reminder</title></head><body>';
/* Get all Tasks */
for OwnerRec in OwnerCursor LOOP
if OwnerRec.TASK_OWNER_ID != PrevOwnerId then
-- This is the first record for this owner. Unless it's also the first record of the loop,
-- close the html and send the email.
if C_count > 0 or F_count > 0 then
r_html := r_html || EndFooter;
end if;
send_mail(p_to => 'XXX.XXX@xxx.com',
p_from => 'fromemail@xxx.com',
p_subject => 'Your Pending and Future tasks for OwnerId' || ownerId,
p_text_msg => 'text msg is not yet created',
p_html_msg => r_html,
p_smtp_host => 'localhost');
r_html := l_html;
PrevOwnerId := OwnerRec.TASK_OWNER_ID;
C_count := 0;
F_count := 0;
end if;
if OwnerRec.TASK_START_DATE <= l_today then
if C_count = 0 then
-- This is the first Current entry, write the header
r_html := r_html || C_header || EndHeader;
end if;
C_count := c_count + 1;
else
if F_count = 0 then
-- This is the first Future entry. See if there were any Current entries
if C_count > 0 then
-- There was, so terminate the Current table
r_html := r_html || '</table>';
C_count := 0;
end if;
-- Write the header
r_html := r_html || F_header || EndHeader;
end if;
F_count := F_count + 1;
end if;
-- Whether Current or Future, write the task particulars
r_html := r_html || '<tr><td>' || OwnerRec.TASK_NAME || '</td><td>' || OwnerRec.TASK_DESCRIPTION || '</td><td>' || OwnerRec.TASK_DUE_DATE ||'</td></tr>';
END LOOP;
-- The last owner has not completed processing. But maybe there were no tasks at all...
if C_count > 0 or F_count > 0 then
r_html := r_html || EndFooter;
send_mail(p_to => 'XXX.XXX@xxx.com',
p_from => 'fromemail@xxx.com',
p_subject => 'Your Pending and Future tasks for OwnerId' || ownerId,
p_text_msg => 'text msg is not yet created',
p_html_msg => r_html,
p_smtp_host => 'localhost');
dbms_output.put_line( r_html );
end if;
END;
哇。从哪里开始。Diederikh和Scott讨论了几个突出的问题，但仔细看代码，有很多是没有意义的 首先，当前任务是否为w 开始日期在过去或现在，到期日期在未来或现在？将来的任务是否在将来有开始日期？如果是这样的话，你的比较就全错了。根据您的逻辑，当前任务的开始日期为将来或现在，到期日期为过去或现在 第二，有五个！需要查询并访问数据库的位置。没有理由不能用初始光标读入您需要的所有内容。然后根据需要进行分析和处理 还有很多其他地方我会提出建议。我不想列出所有的代码，所以我只想包括代码。你可以接受我的小建议，也可以不接受，但一定要验证你的约会逻辑，不要频繁地访问数据库。在执行一次磁盘访问所需的时间内，可以执行数千行代码。它仍然没有我希望的生产代码那么完美，但已经足够让您开始了。而且，虽然我不能访问您的表，但它应该可以工作
create or replace PROCEDURE SENDTASKREMINDER AS
l_html VARCHAR2(100);
r_html VARCHAR2(32767);
C_header varchar2( 40 ) := '<h1>Your current pending tasks</h1>';
F_header varchar2( 32 ) := '<h1>Your future tasks</h1>';
EndHeader varchar2( 80 ) := '<table><tr><th>Task Name</th><th>Description</th><th>Due Date</th></tr>';
EndFooter varchar2( 32 ) := '</table></body></html>';
PrevOwnerId int := -1; -- Must not be a valid OwnerID
C_count int := 0;
F_count int := 0;
l_today date := Trunc( SysDate );
CURSOR OwnerCursor IS
SELECT TASK_OWNER_ID, PK_TASK_ID, TASK_NAME, TASK_DESCRIPTION, TASK_START_DATE, TASK_DUE_DATE
FROM TASKS
WHERE (TASK_START_DATE <= l_today and TASK_DUE_DATE >= l_today)
or TASK_START_DATE > l_today
order by TASK_OWNER_ID, TASK_START_DATE; -- So first the Current then Future tasks
BEGIN
l_html := '<html><head><title>Task Reminder</title></head><body>';
/* Get all Tasks */
for OwnerRec in OwnerCursor LOOP
if OwnerRec.TASK_OWNER_ID != PrevOwnerId then
-- This is the first record for this owner. Unless it's also the first record of the loop,
-- close the html and send the email.
if C_count > 0 or F_count > 0 then
r_html := r_html || EndFooter;
end if;
send_mail(p_to => 'XXX.XXX@xxx.com',
p_from => 'fromemail@xxx.com',
p_subject => 'Your Pending and Future tasks for OwnerId' || ownerId,
p_text_msg => 'text msg is not yet created',
p_html_msg => r_html,
p_smtp_host => 'localhost');
r_html := l_html;
PrevOwnerId := OwnerRec.TASK_OWNER_ID;
C_count := 0;
F_count := 0;
end if;
if OwnerRec.TASK_START_DATE <= l_today then
if C_count = 0 then
-- This is the first Current entry, write the header
r_html := r_html || C_header || EndHeader;
end if;
C_count := c_count + 1;
else
if F_count = 0 then
-- This is the first Future entry. See if there were any Current entries
if C_count > 0 then
-- There was, so terminate the Current table
r_html := r_html || '</table>';
C_count := 0;
end if;
-- Write the header
r_html := r_html || F_header || EndHeader;
end if;
F_count := F_count + 1;
end if;
-- Whether Current or Future, write the task particulars
r_html := r_html || '<tr><td>' || OwnerRec.TASK_NAME || '</td><td>' || OwnerRec.TASK_DESCRIPTION || '</td><td>' || OwnerRec.TASK_DUE_DATE ||'</td></tr>';
END LOOP;
-- The last owner has not completed processing. But maybe there were no tasks at all...
if C_count > 0 or F_count > 0 then
r_html := r_html || EndFooter;
send_mail(p_to => 'XXX.XXX@xxx.com',
p_from => 'fromemail@xxx.com',
p_subject => 'Your Pending and Future tasks for OwnerId' || ownerId,
p_text_msg => 'text msg is not yet created',
p_html_msg => r_html,
p_smtp_host => 'localhost');
dbms_output.put_line( r_html );
end if;
END;
哇。从哪里开始。Diederikh和Scott讨论了几个突出的问题，但仔细看代码，有很多是没有意义的 首先，当前任务的开始日期是过去还是现在，到期日期是将来还是现在？将来的任务是否在将来有开始日期？如果是这样的话，你的比较就全错了。根据您的逻辑，当前任务的开始日期为将来或现在，到期日期为过去或现在 第二，有五个！需要查询并访问数据库的位置。没有理由不能用初始光标读入您需要的所有内容。然后根据需要进行分析和处理 还有很多其他地方我会提出建议。我不想列出所有的代码，所以我只想包括代码。你可以接受我的小建议，也可以不接受，但一定要验证你的约会逻辑，不要频繁地访问数据库。在执行一次磁盘访问所需的时间内，可以执行数千行代码。它仍然没有我希望的生产代码那么完美，但已经足够让您开始了。而且，虽然我不能访问您的表，但它应该可以工作
create or replace PROCEDURE SENDTASKREMINDER AS
l_html VARCHAR2(100);
r_html VARCHAR2(32767);
C_header varchar2( 40 ) := '<h1>Your current pending tasks</h1>';
F_header varchar2( 32 ) := '<h1>Your future tasks</h1>';
EndHeader varchar2( 80 ) := '<table><tr><th>Task Name</th><th>Description</th><th>Due Date</th></tr>';
EndFooter varchar2( 32 ) := '</table></body></html>';
PrevOwnerId int := -1; -- Must not be a valid OwnerID
C_count int := 0;
F_count int := 0;
l_today date := Trunc( SysDate );
CURSOR OwnerCursor IS
SELECT TASK_OWNER_ID, PK_TASK_ID, TASK_NAME, TASK_DESCRIPTION, TASK_START_DATE, TASK_DUE_DATE
FROM TASKS
WHERE (TASK_START_DATE <= l_today and TASK_DUE_DATE >= l_today)
or TASK_START_DATE > l_today
order by TASK_OWNER_ID, TASK_START_DATE; -- So first the Current then Future tasks
BEGIN
l_html := '<html><head><title>Task Reminder</title></head><body>';
/* Get all Tasks */
for OwnerRec in OwnerCursor LOOP
if OwnerRec.TASK_OWNER_ID != PrevOwnerId then
-- This is the first record for this owner. Unless it's also the first record of the loop,
-- close the html and send the email.
if C_count > 0 or F_count > 0 then
r_html := r_html || EndFooter;
end if;
send_mail(p_to => 'XXX.XXX@xxx.com',
p_from => 'fromemail@xxx.com',
p_subject => 'Your Pending and Future tasks for OwnerId' || ownerId,
p_text_msg => 'text msg is not yet created',
p_html_msg => r_html,
p_smtp_host => 'localhost');
r_html := l_html;
PrevOwnerId := OwnerRec.TASK_OWNER_ID;
C_count := 0;
F_count := 0;
end if;
if OwnerRec.TASK_START_DATE <= l_today then
if C_count = 0 then
-- This is the first Current entry, write the header
r_html := r_html || C_header || EndHeader;
end if;
C_count := c_count + 1;
else
if F_count = 0 then
-- This is the first Future entry. See if there were any Current entries
if C_count > 0 then
-- There was, so terminate the Current table
r_html := r_html || '</table>';
C_count := 0;
end if;
-- Write the header
r_html := r_html || F_header || EndHeader;
end if;
F_count := F_count + 1;
end if;
-- Whether Current or Future, write the task particulars
r_html := r_html || '<tr><td>' || OwnerRec.TASK_NAME || '</td><td>' || OwnerRec.TASK_DESCRIPTION || '</td><td>' || OwnerRec.TASK_DUE_DATE ||'</td></tr>';
END LOOP;
-- The last owner has not completed processing. But maybe there were no tasks at all...
if C_count > 0 or F_count > 0 then
r_html := r_html || EndFooter;
send_mail(p_to => 'XXX.XXX@xxx.com',
p_from => 'fromemail@xxx.com',
p_subject => 'Your Pending and Future tasks for OwnerId' || ownerId,
p_text_msg => 'text msg is not yet created',
p_html_msg => r_html,
p_smtp_host => 'localhost');
dbms_output.put_line( r_html );
end if;
END;
如果你很难理解简单的循环和退出，那么你也可以考虑一个for循环。对于初学者来说，它们更容易理解。非常感谢。现在很快。我现在有另一个问题。它正在发送大约1000多封内容相同的电子邮件。在我的表格中，我只有两个任务所有者，他们将收到提醒电子邮件。所以，应该只有2封电子邮件发送给我测试我的id。然而，我收到1000+重复电子邮件。你知道为什么吗？如果你很难理解简单的循环和退出，那么你也可以考虑一个for循环。对于初学者来说，它们更容易理解。非常感谢。现在很快。我现在有另一个问题。它正在发送大约1000多封内容相同的电子邮件。在我的表格中，我只有两个任务所有者，他们将收到提醒电子邮件。所以，应该只有2封电子邮件发送给我测试我的id。然而，我收到1000+重复电子邮件。你知道为什么吗？如果你很难理解简单的循环和退出，那么你也可以考虑一个for循环。对于初学者来说，它们更容易理解。非常感谢。现在很快。我现在有另一个问题。它正在发送大约1000多封内容相同的电子邮件。在我的表格中，我只有两个任务所有者，他们将收到提醒电子邮件。所以，应该只有2封电子邮件发送给我测试我的id。然而，我收到1000+重复电子邮件。你知道为什么吗？如果你很难理解简单的循环和退出，那么你也可以考虑一个for循环。对于初学者来说，它们更容易理解。非常感谢。现在很快。我现在有另一个问题。它正在发送大约1000多封内容相同的电子邮件。在我的表格中，我只有两个任务所有者，他们将收到提醒电子邮件。所以，应该只有2封电子邮件发送给我测试我的id。然而，我收到1000+重复电子邮件。知道为什么吗？