Struct 初始化嵌套结构定义
如何初始化以下结构Struct 初始化嵌套结构定义,struct,go,initialization,Struct,Go,Initialization,如何初始化以下结构 type Sender struct { BankCode string Name string Contact struct { Name string Phone string } } 我试过: s := &Sender{ BankCode: "BC", Name: "NAME", Contact {
type Sender struct {
BankCode string
Name string
Contact struct {
Name string
Phone string
}
}
我试过:
s := &Sender{
BankCode: "BC",
Name: "NAME",
Contact {
Name: "NAME",
Phone: "PHONE",
},
}
mixture of field:value and value initializers
undefined: Contact
s := &Sender{
BankCode: "BC",
Name: "NAME",
Contact: Contact {
Name: "NAME",
Phone: "PHONE",
},
}
undefined: Contact
不起作用:
s := &Sender{
BankCode: "BC",
Name: "NAME",
Contact {
Name: "NAME",
Phone: "PHONE",
},
}
mixture of field:value and value initializers
undefined: Contact
s := &Sender{
BankCode: "BC",
Name: "NAME",
Contact: Contact {
Name: "NAME",
Phone: "PHONE",
},
}
undefined: Contact
我试过:
s := &Sender{
BankCode: "BC",
Name: "NAME",
Contact {
Name: "NAME",
Phone: "PHONE",
},
}
mixture of field:value and value initializers
undefined: Contact
s := &Sender{
BankCode: "BC",
Name: "NAME",
Contact: Contact {
Name: "NAME",
Phone: "PHONE",
},
}
undefined: Contact
不起作用:
s := &Sender{
BankCode: "BC",
Name: "NAME",
Contact {
Name: "NAME",
Phone: "PHONE",
},
}
mixture of field:value and value initializers
undefined: Contact
s := &Sender{
BankCode: "BC",
Name: "NAME",
Contact: Contact {
Name: "NAME",
Phone: "PHONE",
},
}
undefined: Contact
分别定义这两个结构,然后在“发送者”中嵌入“联系人”怎么样 如果您这样做,您的第二次初始化尝试将起作用。此外,您可以单独使用“联系人”
如果你真的想使用嵌套结构,你可以使用Ainar-G的答案,但是这个版本并不漂亮(如果结构嵌套得很深,它会变得更难看,如图所示),所以如果可以避免的话,我不会这么做。你的
联系人
是一个匿名结构类型的字段。因此,必须重复类型定义:
s := &Sender{
BankCode: "BC",
Name: "NAME",
Contact: struct {
Name string
Phone string
}{
Name: "NAME",
Phone: "PHONE",
},
}
但在大多数情况下,最好按照rob74的建议定义一个单独的类型。这是另一个选项,但我只想知道如何初始化嵌套结构。您的答案是解决嵌套结构定义的更好方法,但Ainar-G的答案对我的问题是正确的。好的,这似乎是正确的答案,但正如你所说,rob74的回答更优雅。
type NameType struct {
First string
Last string
}
type UserType struct {
NameType
Username string
}
user := UserType{NameType{"Eduardo", "Nunes"}, "esnunes"}
// or
user := UserType{
NameType: NameType{
First: "Eduardo",
Last: "Nunes",
},
Username: "esnunes",
}