删除SugarCRM中带有条件的detailview中的按钮
我的代码:删除SugarCRM中带有条件的detailview中的按钮,sugarcrm,Sugarcrm,我的代码: $GLOBALS['listbutton'] = $this->dv->defs['templateMeta']['form']['buttons']; if ($this->bean->status == 'Converted') { unset($this->dv->defs['templateMeta']['form']['buttons'][0]); } parent::display
$GLOBALS['listbutton'] = $this->dv->defs['templateMeta']['form']['buttons'];
if ($this->bean->status == 'Converted') {
unset($this->dv->defs['templateMeta']['form']['buttons'][0]);
}
parent::display();
$GLOBALS['log']->debug("INFOdation log Display");
$this->dv->defs['templateMeta']['form']['buttons'] = $GLOBALS['listbutton'];
但是当status=='New'时,编辑按钮仍然隐藏。你能帮我吗。我只想在状态为“已转换”时隐藏编辑按钮,其他状态必须显示。您可以使用Javascript隐藏按钮 在detailviewdefs.php中包含您的脚本
'includes' =>
array (
0 =>
array (
'file' => 'custom/modules/Leads/button_hide.js',
),
),
比如:
SUGAR.util.doWhen("typeof $ != 'undefined'", function(){
if($(#status).val() == "Converted")$('#delete_button').parent().hide();
});
(如果启用了ajax,则SUGAR.util.doWhen是SugarCrm onload)
如果字段状态不在视图中,则需要在detailviewdefs.php中添加一个隐藏字段,并使用smarty代码设置值,如:
<input type="hidden" id="status" value="{$fields.status.value}">
如果删除
unset
零件,是否可以看到编辑按钮?