Sum 在两列之间拆分的行上求和
我的数据是这样的,我不知道如何获得“想要”列。我尝试过保留、滞后和求和函数的各种组合,但不幸没有成功Sum 在两列之间拆分的行上求和,sum,sas,datastep,Sum,Sas,Datastep,我的数据是这样的,我不知道如何获得“想要”列。我尝试过保留、滞后和求和函数的各种组合,但不幸没有成功 month quantity1 quantity2 want 1 a x x+sum(b to l) 2 b y sum(x to y)+sum(c to l) 3 c z sum(x to z)+sum(d to l) 4
month quantity1 quantity2 want
1 a x x+sum(b to l)
2 b y sum(x to y)+sum(c to l)
3 c z sum(x to z)+sum(d to l)
4 d
5 e
6 f
7 g
8 h
9 i
10 j
11 k
12 l
感谢您在这件事上提供的任何帮助您可以通过一个步骤完成这项工作,但以下两个步骤将产生所需的结果。第一步是计算相关
quantity1
值之和,第二步是将它们添加到相关quantity2
值之和:
data temp;
input month qty1 qty2;
datalines;
1 1 100
2 1 100
3 1 100
4 1 .
5 1 .
6 1 .
7 1 .
8 1 .
9 1 .
10 1 .
11 1 .
12 1 .
;
run;
proc sql;
create table qty1_sums as select distinct
a.*, sum(b.qty1) as qty1_sums
from temp as a
left join temp as b
on a.month < b.month
group by a.month;
create table want as select distinct
a.*,
case when not missing(a.qty2) then sum(a.qty1_sums, sum(b.qty2)) end as want
from qty1_sums as a
left join temp as b
on a.month >= b.month
group by a.month;
quit;
数据温度;
输入月份qty1 qty2;
数据线;
1 1 100
2 1 100
3 1 100
4 1 .
5 1 .
6 1 .
7 1 .
8 1 .
9 1 .
10 1 .
11 1 .
12 1 .
;
跑
proc-sql;
创建表qty1_SUMMES作为select distinct
a、 *,和(b.qty1)作为qty1\u和
从临时工
左连接临时组件b
月日<月日
按a.月分组;
创建所需的表作为“选择不同”
a、 *,
如果未丢失(a.qty2),则sum(a.qty1_sums,sum(b.qty2))根据需要结束
从qty1_和作为
左连接临时组件b
a月>=b月
按a.月分组;
退出
您可以在一个步骤中完成此操作,但以下步骤将在两个步骤中产生所需的结果。第一步是计算相关quantity1
值之和,第二步是将它们添加到相关quantity2
值之和:
data temp;
input month qty1 qty2;
datalines;
1 1 100
2 1 100
3 1 100
4 1 .
5 1 .
6 1 .
7 1 .
8 1 .
9 1 .
10 1 .
11 1 .
12 1 .
;
run;
proc sql;
create table qty1_sums as select distinct
a.*, sum(b.qty1) as qty1_sums
from temp as a
left join temp as b
on a.month < b.month
group by a.month;
create table want as select distinct
a.*,
case when not missing(a.qty2) then sum(a.qty1_sums, sum(b.qty2)) end as want
from qty1_sums as a
left join temp as b
on a.month >= b.month
group by a.month;
quit;
数据温度;
输入月份qty1 qty2;
数据线;
1 1 100
2 1 100
3 1 100
4 1 .
5 1 .
6 1 .
7 1 .
8 1 .
9 1 .
10 1 .
11 1 .
12 1 .
;
跑
proc-sql;
创建表qty1_SUMMES作为select distinct
a、 *,和(b.qty1)作为qty1\u和
从临时工
左连接临时组件b
月日<月日
按a.月分组;
创建所需的表作为“选择不同”
a、 *,
如果未丢失(a.qty2),则sum(a.qty1_sums,sum(b.qty2))根据需要结束
从qty1_和作为
左连接临时组件b
a月>=b月
按a.月分组;
退出
听起来像是“滚动12个月的总和”。如果是这样,使用不同的数据结构(不是2个变量,而是24行1个变量)就容易多了;然后您就有了所有的ETS工具,或者SQL或SAS数据步骤中的一个简单过程
如果您不能/不会重新构造数据,那么您可以通过将数据加载到临时数组(或哈希表,但对于新手来说数组更简单)中来实现。这样你就可以提前了解整件事。例如:
data have;
do month = 1 to 12;
q_2014 = rand('Uniform')*10+500+month*5;
q_2015 = rand('Uniform')*10+550+month*5;
output;
end;
run;
data want;
array q2014[12] _temporary_; *temporary array to hold data;
array q2015[12] _temporary_;
if _n_=1 then do; *load data into temporary arrays;
do _n = 1 to n_data;
set have point=_n nobs=n_data;
q2014[_n] = q_2014;
q2015[_n] = q_2015;
end;
end;
set have;
do _i = 1 to _n_; *grab the this_year data;
q_rolling12 = sum(q_rolling12,q2015[_i]);
end;
do _j = _n_+1 to n_data;
q_rolling12 = sum(q_rolling12,q2014[_j]);*grab the last_year data;
end;
run;
听起来像是“滚动12个月的总和”。如果是这样,使用不同的数据结构(不是2个变量,而是24行1个变量)就容易多了;然后您就有了所有的ETS工具,或者SQL或SAS数据步骤中的一个简单过程 如果您不能/不会重新构造数据,那么您可以通过将数据加载到临时数组(或哈希表,但对于新手来说数组更简单)中来实现。这样你就可以提前了解整件事。例如:
data have;
do month = 1 to 12;
q_2014 = rand('Uniform')*10+500+month*5;
q_2015 = rand('Uniform')*10+550+month*5;
output;
end;
run;
data want;
array q2014[12] _temporary_; *temporary array to hold data;
array q2015[12] _temporary_;
if _n_=1 then do; *load data into temporary arrays;
do _n = 1 to n_data;
set have point=_n nobs=n_data;
q2014[_n] = q_2014;
q2015[_n] = q_2015;
end;
end;
set have;
do _i = 1 to _n_; *grab the this_year data;
q_rolling12 = sum(q_rolling12,q2015[_i]);
end;
do _j = _n_+1 to n_data;
q_rolling12 = sum(q_rolling12,q2014[_j]);*grab the last_year data;
end;
run;
对quantity1求和,然后将值存储到宏变量中是很方便的。使用“多余”数据示例:
proc sql;
select sum(qty1) into:sum_qty1 from temp;
quit;
data want;
set temp;
value1+qty1;
value2+qty2;
want=value2+&sum_qty1-value1;
if missing(qty2) then want=.;
drop value:;
run;
对quantity1求和,然后将值存储到宏变量中是很方便的。使用“多余”数据示例:
proc sql;
select sum(qty1) into:sum_qty1 from temp;
quit;
data want;
set temp;
value1+qty1;
value2+qty2;
want=value2+&sum_qty1-value1;
if missing(qty2) then want=.;
drop value:;
run;