使用Alamofire在Swift 4 ios中将Json对象作为参数值发布

我尝试了很多方法，但每次都失败了。 我想将json对象作为键值发布 关键是“数据” 关键值是

{"totalcost":"8500","delivery_type":"take_away","order_name":"","order_mobilenumber":"","order_city":"Chose Your Place","order_address":"","take":"  2 Hour ","":[{"parent_id":"145","subitem_id":"179","quentity":"1"}],"customer_id":"6"}

我的代码是

let parameters: [String: Any] = [
        "data":
            ["customer_id":"6",
            "totalcost":"8500",
            "delivery_type":"take_away",
            "order_name":"",
            "order_mobilenumber":"",
            "order_city":"Chose Your Place",
            "order_address":"",
            "take_away_time":" Next 2 Hour ",
            "":[
                [
                  "parent_id":"145",
                  "subitem_id":"179",
                  "quentity":"1"
                ]
            ]
        ]

    ]

Alamofire.request("http:/app_con",method:.post,parameters:parameters,encoding:JSONEncoding.default).responseJSON{response in
        let jsonResult = response.result.value
        print(jsonResult)

    }

我的反应越来越差

{
message = "Please Try After Some Time";
status = error;

{
message = "successfully submitted";
status = successful;

}

但通过邮递员，我得到了以下回应

{
message = "Please Try After Some Time";
status = error;

{
message = "successfully submitted";
status = successful;

})

我尝试了很多方法，但都没有成功。请给我你有价值的建议

---

谢谢

**这是通过使用迅捷JSON解决的。我搜索了很多网站，但没有得到预期的答案。 我张贴答案，因为它将是有用的人

解决办法是

I tried to post key value in dictionary format instead of json format,That's why i did not get expected output. swiftjson is very to write json object.**

let emptyJson : JSON = JSON(["customer_id":"26",
                                 "totalcost":"8500",
                                 "delivery_type":"take_away",
                                 "order_name":"",
                                 "order_mobilenumber":"",
                                 "order_city":"Chose Your Place",
                                 "order_address":"",
                                 "take_away_time":" Next 2 Hour ",
                                 "":[
                                    [
                                        "parent_id":"145",
                                        "subitem_id":"179",
                                        "quentity":"1"
                                    ]
                                    ]
                               ])
let parameters: [String: Any] = [
        "data": emptyJson
    ]
Alamofire.request("http://_con",method:.post,parameters:parameters).responseJSON{response in
        let jsonResult = response.result.value
        print(jsonResult)

    }

---

在Alamofire请求中不需要使用json编码。我们只是发布json对象。

您遇到了什么错误？我在postman中发布了相同的参数，它会给出“状态：“成功”的响应，但通过上述代码，获取状态错误请在您的问题中添加您的错误。没有错误，它没有给出成功的回应