Swift Alamofire SwiftyJSON异步/同步类方法
因此,我目前有以下几点:Swift Alamofire SwiftyJSON异步/同步类方法,swift,asynchronous,synchronous,alamofire,swifty-json,Swift,Asynchronous,Synchronous,Alamofire,Swifty Json,因此,我目前有以下几点: class ViewController: UIViewController { class Identity{ let baseUrl = "superSecretURL" var _username: String = "" var _password: String = "" var _apiKey: String = "" init(){ } init(username: String, apiKe
class ViewController: UIViewController {
class Identity{
let baseUrl = "superSecretURL"
var _username: String = ""
var _password: String = ""
var _apiKey: String = ""
init(){
}
init(username: String, apiKey: String){
_username = username
_apiKey = apiKey
}
init(username: String, password: String){
_username = username
_password = password
}
func loginPassword() -> String{
var loginJSON = ["auth": ["passwordCredentials": ["username": _username, "password": _password]]];
var returnJSON: String
request(.POST, baseUrl, parameters: loginJSON, encoding: .JSON)
.responseJSON { (request, response, data, error) in
if let anError = error
{
// got an error in getting the data, need to handle it
println("error calling POST on /posts")
println(error)
}
else if let data: AnyObject = data
{
// handle the results as JSON, without a bunch of nested if loops
let post = JSON(data)
// to make sure it posted, print the results
println("JSON Returned")
}
}
}
}
var i = Identity(username: "secretName", password: "complicatedPassword")
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view, typically from a nib.
println("Before Call")
println("After Call")
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
}
基本上,我希望能够调用println(“调用前”),然后从loginPassword()方法接收响应,然后调用println(“调用后”)。我相信这是同步的,但我想不出一个办法让它工作,整个线程的事情一直困扰着我的头
我基本上想说:
if i.loginPassword(){ // do some login stuff }else{ // do some error stuff }
非常感谢您的帮助或指点。您需要设置一个回调函数,以便在
loginPassword()
函数中随时调用
这可能是实现这一目标的一种方式:
func loginPassword(callback: ((isOk: Bool)->Void)?) -> String{
var loginJSON = ["auth": ["passwordCredentials": ["username": _username, "password": _password]]];
var returnJSON: String
request(.POST, baseUrl, parameters: loginJSON, encoding: .JSON)
.responseJSON { (request, response, data, error) in
if let anError = error{
// got an error in getting the data, need to handle it
println("error calling POST on /posts")
println(error)
callback?(isOk: false)
}
else if let data: AnyObject = data{
// handle the results as JSON, without a bunch of nested if loops
let post = JSON(data)
// to make sure it posted, print the results
println("JSON Returned")
callback?(isOk: true)
}
}
}
然后
override func viewDidLoad() {
super.viewDidLoad()
var identity = Identity(username: "John Apleseed", apiKey: "213123123")
identity.loginPassword { (isOK) -> Void in
if (isOK) {
//do good stuff here
}else{
// do error handling here
}
}
}
更新
此外,您的调用函数可以如下所示:
override func viewDidLoad() {
super.viewDidLoad()
var identity = Identity(username: "John Apleseed", apiKey: "213123123")
identity.loginPassword(handlePasswordRequest)
}
您可以根据需要添加尽可能多的回调处理程序,而无需使用一堆嵌套闭包
private func handlePasswordRequest(isOK: Bool){
if (isOK) {
//do good stuff here
}else{
// do error handling here
}
}
更新2
如果需要深入调用层次结构调用回调,则需要将回调作为以前每个闭包的参数传递
更新3
我想尝试一下RxAlamofire和所有关于RxSwift的内容,非常感谢!有没有一种方法可以通过承诺把这些联系在一起,这样就不会让筑巢看起来那么糟糕了?在应用程序的另一半过程中,这可能会深入到4-5个级别?您知道Swift 2中的原始答案是什么样的吗?它在swift 1.2中对我有效,但现在似乎删除了错误参数。我的问题是关于this@HugoAlonso我希望看到回调示例的RxAlamofire嵌套。你能提供一个要点吗?谢谢