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Swift 将图像从一个视图控制器传递到另一个控制器会给出零_Swift_Uiviewcontroller_Segue - Fatal编程技术网

Swift 将图像从一个视图控制器传递到另一个控制器会给出零

Swift 将图像从一个视图控制器传递到另一个控制器会给出零,swift,uiviewcontroller,segue,Swift,Uiviewcontroller,Segue,我正在尝试向预览控制器发送图像,如下所示。我的问题是,预览控制器中的newImage是nil 代码如下: FirstViewController override func prepare(for segue: UIStoryboardSegue, sender: Any?) { print("In here") if segue.identifier == "showImage" { let secondViewController = self.storyb

我正在尝试向预览控制器发送图像,如下所示。我的问题是,预览控制器中的
newImage
nil

代码如下:

FirstViewController

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    print("In here")
    if segue.identifier == "showImage" {

        let secondViewController = self.storyboard!.instantiateViewController(withIdentifier: "showImage") as! showImageController

        secondViewController.newImage =  UIImage(named: imageArray[0])

    }
}
@IBOutlet weak var imageHolder: UIImageView!
var newImage: UIImage!

override func viewDidLoad() {
    super.viewDidLoad()
    imageHolder.image = newImage
    // Do any additional setup after loading the view.
}
预览控制器

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    print("In here")
    if segue.identifier == "showImage" {

        let secondViewController = self.storyboard!.instantiateViewController(withIdentifier: "showImage") as! showImageController

        secondViewController.newImage =  UIImage(named: imageArray[0])

    }
}
@IBOutlet weak var imageHolder: UIImageView!
var newImage: UIImage!

override func viewDidLoad() {
    super.viewDidLoad()
    imageHolder.image = newImage
    // Do any additional setup after loading the view.
}

InstanceEviewController调用viewDidLoad(),这样在调用映像时就不会设置映像。将代码移动到viewWillExample(),它就会工作

您应该使用
segue.destination
而不是像这样创建一个新的

 override func prepare(for segue: UIStoryboardSegue, sender: Any?) {

   print("In here")

   if segue.identifier == "showImage" {

        let next = segue.destination as! showImageController

        next.newImage =  UIImage(named: imageArray[0])

    }

 }