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Swift NSLock.lock()在已持有锁的情况下执行?_Swift_Closures_Alamofire_Nslock - Fatal编程技术网

Swift NSLock.lock()在已持有锁的情况下执行?

Swift NSLock.lock()在已持有锁的情况下执行?,swift,closures,alamofire,nslock,Swift,Closures,Alamofire,Nslock,我正在查看一些Alamofire检索器代码: func should(_ manager: SessionManager, retry request: Request, with error: Error, completion: @escaping RequestRetryCompletion) { lock.lock() ; defer { lock.unlock() } if let response = request.task.response

我正在查看一些Alamofire检索器代码:

   func should(_ manager: SessionManager, retry request: Request, with error: Error, completion: @escaping RequestRetryCompletion) {
        lock.lock() ; defer { lock.unlock() }

        if let response = request.task.response as? HTTPURLResponse, response.statusCode == 401 {
            requestsToRetry.append(completion)

            if !isRefreshing {
                refreshTokens { [weak self] succeeded, accessToken, refreshToken in
                    guard let strongSelf = self else { return }

                    strongSelf.lock.lock() ; defer { strongSelf.lock.unlock() }

                    ...
                }
            }
        } else {
            completion(false, 0.0)
        }
    }
我不明白如何在函数的第一行上有
lock.lock()
,然后在传递给
refreshTokens
的闭包中也有同一行
strongSelf.lock.lock()


如果在执行
延迟
解锁时,直到
should
方法结束才释放第一个锁,那么第二个
strongSelf.lock.lock()
如何在第一个锁被持有时成功执行?

刷新令牌的后续关闭,其中第二次调用
锁()
/
unlock()
被调用,异步运行。这是因为闭包是
@escaping
,并且是从
reshTokens
例程中的
responseJSON
中调用的。因此,
should
方法将在实际调用
refreshttokens
关闭时执行其延迟的
unlock

话虽如此,这并不是我见过的最优雅的代码,锁的实用性还不清楚,死锁的风险很大程度上取决于其他例程的实现细节。这里看起来没问题,但我不怪你对它皱眉