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Swift 斯威夫特阿拉莫菲尔邮政公司“;call中的额外参数";_Swift_Alamofire - Fatal编程技术网

Swift 斯威夫特阿拉莫菲尔邮政公司“;call中的额外参数";

Swift 斯威夫特阿拉莫菲尔邮政公司“;call中的额外参数";,swift,alamofire,Swift,Alamofire,我想将一些xml发布到url。这是我的代码: func post(){ var data = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><Devices><Device><ID>EZR0114AF</ID><HEATAREA nr=\"4\"><T_TARGET>17.0</T_TARGET></HEATAREA></Device&

我想将一些xml发布到url。这是我的代码:

func post(){
    var data = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><Devices><Device><ID>EZR0114AF</ID><HEATAREA nr=\"4\"><T_TARGET>17.0</T_TARGET></HEATAREA></Device></Devices>"

    Alamofire.request(urlPost, .post, parameters: data, encoding: .utf8, headers: nil).response { (response) in
        print(response.data)
        print(response.error)
        print(response.response)
    }
}
func post(){
var data=“EZR0114AF17.0”
请求(urlPost,.post,参数:数据,编码:.utf8,头:nil)
打印(响应.数据)
打印(响应错误)
打印(response.response)
}
}

但是我得到了一个语法错误:
调用中的额外参数
。我不知道遗漏了什么,我尝试了很多,但都没有效果。有什么想法吗?

尝试将语法更改为

 let urlString = "XXXXXXXXX"

        Alamofire.request(urlString, method: .post, parameters: ["id": "1,2,3,4"] ,encoding: JSONEncoding.default, headers: nil).responseString {

            response in
            switch response.result {
            case .success(let responseString1):
                print("the response is: \(responseString1)")

                break
            case .failure(let error):

                print("The error is: \(error)")
            }
        }