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如何使用Swift进行API调用?_Swift_Xcode_Api - Fatal编程技术网

如何使用Swift进行API调用?

如何使用Swift进行API调用?,swift,xcode,api,Swift,Xcode,Api,所以我正在练习如何使用Swift进行API调用。代码如下: struct Example: Codable { let userID: String let ID: String let title: String let completed: String } func getJson(completion: @escaping (Example)-> ()) { let urlString = "https://jsonplaceh

所以我正在练习如何使用Swift进行API调用。代码如下:

struct Example: Codable {
    let userID: String
    let ID: String
    let title: String
    let completed: String
}


func getJson(completion: @escaping (Example)-> ()) {
    let urlString = "https://jsonplaceholder.typicode.com/todos/1"
    if let url = URL(string: urlString) {
        URLSession.shared.dataTask(with: url) {data, res, err in
            if let data = data {

                let decoder = JSONDecoder()
                if let json: Example = try? decoder.decode(Example.self, from: data) {
                    completion(json)
                }
            }
        }.resume()
    }
}

getJson() { (json) in
    print(json.ID)
}
但是,当调用getJson时,我无法打印任何内容。 找到了我使用的示例API。
找到了我用来帮助编写代码的教程。

完全按照API响应修改了变量名和数据类型

struct Example: Codable {
    let userId: Int
    let id: Int
    let title: String
    let completed: Bool
}

func getJson(completion: @escaping (Example)-> ()) {
    let urlString = "https://jsonplaceholder.typicode.com/todos/1"
    if let url = URL(string: urlString) {
        URLSession.shared.dataTask(with: url) {data, res, err in
            if let data = data {
                
                let decoder = JSONDecoder()
                do {
                    let json: Example = try! decoder.decode(Example.self, from: data)
                    completion(json)
                }catch let error {
                    print(error.localizedDescription)
                }
            }
        }.resume()
    }
}

getJson() { (json) in
    print(json.id)
}
您还可以使用CodingKey,并可以在初始化期间更改响应

struct Example: Codable {
    var userID: Int
    var ID: Int
    var title: String
    var completed: Bool
 
    enum CodingKeys: String, CodingKey {
        case userID = "userId"
        case ID = "id"
        case title = "title"
        case completed = "completed"
    }
    
    init(from decoder: Decoder) throws {
        let values = try decoder.container(keyedBy: CodingKeys.self)
        userID = try values.decode(Int.self, forKey: .userID)
        ID = try values.decode(Int.self, forKey: .ID)
        title = try values.decode(String.self, forKey: .title)
        completed = try values.decode(Bool.self, forKey: .completed)
        title = "Title: \(title)"
    }
}

func getJson(completion: @escaping (Example)-> ()) {
    let urlString = "https://jsonplaceholder.typicode.com/todos/1"
    if let url = URL(string: urlString) {
        URLSession.shared.dataTask(with: url) {data, res, err in
            if let data = data {
                do {
                    let json: Example = try JSONDecoder().decode(Example.self, from: data)
                    completion(json)
                }catch let error {
                    print(error.localizedDescription)
                }
            }
        }.resume()
    }
}

getJson() { (json) in
    print("ID: \(json.ID) \(json.title)")
}

我可以问一下,您将如何修改它以返回示例数组吗?答案不再有效。它找不到json。