Swift 快速动态UIPickerView

我觉得我很接近了，因为下面的代码适用于静态UIPickerView，但我正在尝试根据第一个选择动态设置我的pickerview，尽管查看了教程并进行了搜索，我还是无法完全理解这一点。例如，如果您在myPickerData中选择“Brown”，则myPickerData中仅显示“本科生”，或者如果您选择“Dartmouth”，则您应仅获得“本科生”和“MBA”，最后，如果您选择“Columbia”或“Harvard”，则您将获得“本科生”、“法学博士”、“MBA”

var myPickerData = ["Select Your Dream College", “Brown", "Columbia", “Dartmouth”,  "Harvard" ]

var myPickerData2 = ["Undergraduate", "JD", "MBA"]

func numberOfComponents(in pickerView: UIPickerView) -> Int {
    return 2
}

func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {

    if component == 0 {
        return myPickerData.count
    }

    return myPickerData2.count
}

func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {

    if component == 0 {
        return myPickerData[row] as String
    }
    return myPickerData2[row] as String
}

func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {

    uniSelected = myPickerData[pickerView.selectedRow(inComponent: 0)]

    collegeSelected = myPickerData2[pickerView.selectedRow(inComponent: 1)]
}

你可以试试

func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {

     if component == 0 {

         let str = myPickerData[row]

         if str == "Brown" {

            myPickerData2 = ["Undergraduate"]
         }
         else if str == "Dartmouth" {

            myPickerData2 = ["Undergraduate", "MBA"]
         }
         else {

            myPickerData2 = ["Undergraduate", "JD", "MBA"]

         }

         pickerView.reloadComponent(1)

      }
      else {

         uniSelected = myPickerData[pickerView.selectedRow(inComponent: 0)]

         collegeSelected = myPickerData2[pickerView.selectedRow(inComponent: 1)]
      }

}

//

这可能包含重复项，但您可以尝试

let mainDic:[String:[String]] = ["Select Your Dream College":[],
                 "Brown":["Undergraduate"],
                 "Dartmouth":["Undergraduate", "MBA"],
                 "Columbia":  ["Undergraduate", "JD", "MBA"],
                 "Harvard",["Undergraduate", "JD", "MBA"]]

然后

并在组件0中使用它

myPickerData = Array(mainDic.keys)

将您的数据源设置为

mainDic

，并将键处理为

myPickerData

，当前选择的键值处理为

myPickerData 2

编辑：在

viewDidLoad

myPickerData = Array(mainDic.keys)
myPickerData2 = mainDic["Select Your Dream College"]! // it's default or simply []

---

这是非常有帮助的，而且我认为这将是一个解决问题的方法。但是，是否有一种更干净/可扩展的方法来做到这一点？我只为每个数据源数组列出了3个，并设想一个更大的数组将成为一个巨大的if语句。也就是说，如果我在myPickerData1中加载15个可能的选择，那么if-else语句将变得非常混乱。好的，dict数组是有意义的，但是我原来的func方法有什么变化？尝试可视化我的原始代码将如何更改。又来了！mainDic的init myPickerData和myPickerData 2，，，参见edit试图用字典实现您的建议，遇到了很多问题，所以只使用原始if语句haaa

myPickerData = Array(mainDic.keys)
myPickerData2 = mainDic["Select Your Dream College"]! // it's default or simply []