SwiftUI-正确使用导航视图和图纸

SwiftUI-正确使用导航视图和图纸,swiftui,navigationbar,navigationlink,Swiftui,Navigationbar,Navigationlink,导航视图和工作表有问题。我有以下流程: -ContentView:具有打开ContentView2工作表的按钮 -ContentView2:具有指向ContentView3的标题的NavigationLink -ContentView3:具有NavigationLink,无标题,可将用户定向到ContentView2 但是,当我设置上述流时,当用户在ContentView2和ContentView3之间来回移动时,我最终会得到堆叠的标题。当用户在两个视图之间来回移动时,如何防止出现这种情况,并且

导航视图和工作表有问题。我有以下流程: -ContentView:具有打开ContentView2工作表的按钮 -ContentView2:具有指向ContentView3的标题的NavigationLink -ContentView3:具有NavigationLink,无标题,可将用户定向到ContentView2

但是,当我设置上述流时,当用户在ContentView2和ContentView3之间来回移动时,我最终会得到堆叠的标题。当用户在两个视图之间来回移动时,如何防止出现这种情况,并且只有一个标题?谢谢

struct ContentView: View {
    @State var showSheet = false

    var body: some View {
        Button("Click"){
            self.showSheet.toggle()
        }
        .sheet(isPresented: $showSheet) {
            ContentView2()
        }
    }
}


struct ContentView2: View {
    var body: some View {
        NavigationView {
            NavigationLink(destination: ContentView3()){
                Text("Click Here")
            }
            .navigationBarTitle("Bar Title", displayMode: .inline)
        }
    }
}

struct ContentView3: View {
    var body: some View {
        NavigationLink(destination: ContentView2()){
            Text("Click Here")
        }
    }
}

在根目录中只需要一个
导航视图
,下面是更正的组件

struct ContentView: View {
    @State var showSheet = false

    var body: some View {
        Button("Click"){
            self.showSheet.toggle()
        }
        .sheet(isPresented: $showSheet) {
           NavigationView {    // only here !!
            ContentView2()
           }
        }
    }
}


struct ContentView2: View {
    var body: some View {
         NavigationLink(destination: ContentView3()){
             Text("Click Here")
         }
         .navigationBarTitle("Bar Title", displayMode: .inline)
    }
}