Tsql 根据问题显示不同的总计（&A）；日期

我的查询有以下结果：

上述样本数据：

declare @tbl table (DateOfService date, IssueID int, IssueName varchar(100), AssignedConsultant varchar(30), Activity varchar(100), TimeSpent float, TimeInvoiced float)

insert into @tbl (DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values ('2019-12-19',10295,'Bin Issue','Doug','Activity Detail 1…',10.25,8)
insert into @tbl (DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values ('2019-12-19',10295,'Bin Issue','Doug','Activity Detail 2…',10.25,8)
insert into @tbl (DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values ('2020-01-24',10295,'Bin Issue','Doug','Activity Detail 3…',5.5,4)
insert into @tbl (DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values ('2020-01-24',10295,'Bin Issue','Doug','Activity Detail 4…',5.5,4)

select
*
from    @tbl

但是，出于保密原因，我无法分享我的疑问

如何改变这些结果，使其看起来像这样：

从我的预期结果可以看出，我只需要计算每个日期花费和开具发票的总时间

我遇到的问题是，这个结果被用于Excel中的pivot，导致出现双值

---

请帮忙？

我认为这不管用，但看起来对这些结果是管用的

下面是我的想法（不确定技术上是否正确），但它对我很有用：

declare @tbl table (DateOfService date, IssueID int, IssueName varchar(100), AssignedConsultant varchar(30), Activity varchar(100), TimeSpent float, TimeInvoiced float)

insert into @tbl (DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values ('2019-12-19',10295,'Bin Issue','Doug','Activity Detail 1…',10.25,8)
insert into @tbl (DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values ('2019-12-19',10295,'Bin Issue','Doug','Activity Detail 2…',10.25,8)
insert into @tbl (DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values ('2020-01-24',10295,'Bin Issue','Doug','Activity Detail 3…',5.5,4)
insert into @tbl (DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values ('2020-01-24',10295,'Bin Issue','Doug','Activity Detail 4…',5.5,4)

select
    DateOfService
,   IssueID
,   IssueName
,   AssignedConsultant
,   Activity
,   case when lag(TimeSpent) over (order by IssueName) = TimeSpent then 0 else TimeSpent end            TimeSpent
,   case when lag(TimeInvoiced) over (order by IssueName) = TimeInvoiced then 0 else TimeInvoiced end   TimeInvoiced
from    @tbl

---

请参见

中的结果，我假设您有某种方法来标识每一行，因此我在表变量中添加了and ID列。我还将第二行的值保留为NULL，因为您不清楚在那里需要什么值。无论如何，这应该适用于表示的数据集：

declare @tbl table (ID int,DateOfService date, IssueID int, IssueName varchar(100), AssignedConsultant varchar(30), Activity varchar(100), TimeSpent float, TimeInvoiced float)

insert into @tbl (ID,DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values (1,'2019-12-19',10295,'Bin Issue','Doug','Activity Detail 1…',10.25,8)
insert into @tbl (ID,DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values (2,'2019-12-19',10295,'Bin Issue','Doug','Activity Detail 2…',10.25,8)
insert into @tbl (ID,DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values (3,'2020-01-24',10295,'Bin Issue','Doug','Activity Detail 3…',5.5,4)
insert into @tbl (ID,DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values (4,'2020-01-24',10295,'Bin Issue','Doug','Activity Detail 4…',5.5,4)


;WITH CTE AS (
SELECT MIN(ID) ID, DateOfService
FROM @tbl
GROUP BY DateOfService
)
SELECT T1.DateOfService,
        IssueID,
        IssueName,
        AssignedConsultant,
        Activity, 
        CASE WHEN T2.ID IS NULL THEN NULL ELSE T1.TimeSpent END TimeSpent,
        CASE WHEN T2.ID IS NULL THEN NULL ELSE T1.TimeInvoiced END TimeInvoiced
FROM @tbl T1
LEFT JOIN CTE T2 on T1.ID = T2.ID