Tsql 中值函数在Sql Server中的工作原理
在甲骨文中,它运行良好 oracle的查询如下所示Tsql 中值函数在Sql Server中的工作原理,tsql,aggregate-functions,Tsql,Aggregate Functions,在甲骨文中,它运行良好 oracle的查询如下所示 Select COMPONENT_ID, COMPONENT_NAME, POSITION_ID, POSITION_NAME, CHANNEL_ID, CHANNEL_NAME, Max(METRIC) as METRIC, Max(TTD_ATTN) as TTD_ATTN_Max,
Select COMPONENT_ID,
COMPONENT_NAME,
POSITION_ID,
POSITION_NAME,
CHANNEL_ID,
CHANNEL_NAME,
Max(METRIC) as METRIC,
Max(TTD_ATTN) as TTD_ATTN_Max,
Min(TTD_ATTN) as TTD_ATTN_Min,
Avg(TTD_ATTN) as TTD_ATTN_Avg,
Median(TTD_ATTN) as TTD_ATTN_Med,
StdDev(TTD_ATTN) as TTD_ATTN_StdDev,
Max(COMPONENT_NO) as COMPONENT_NO,
DATAMONTH,
CHANNEL_ID||'_'||POSITION_ID as CHANNEL_POSITION,
CHANNEL_NAME||'_'||POSITION_NAME as CHANNEL_POSITION_NAME
from SCNCAAF0461A1894981868ABA.PB36E6D13A82C4609B9488950
Group By COMPONENT_ID,
COMPONENT_NAME,
POSITION_ID,
POSITION_NAME,
CHANNEL_ID,
CHANNEL_NAME,
DATAMONTH
但对于SQL Server,获取错误
Select COMPONENT_ID,
COMPONENT_NAME,
POSITION_ID,
POSITION_NAME,
CHANNEL_ID,
CHANNEL_NAME,
max(METRIC) AS METRIC,
max(TTD_ATTN) AS TTD_ATTN_Max,
min(TTD_ATTN) AS TTD_ATTN_Min,
avg(TTD_ATTN) AS TTD_ATTN_Avg,
Median(TTD_ATTN) AS TTD_ATTN_Med,
stdev(TTD_ATTN) AS TTD_ATTN_StdDev,
max(COMPONENT_NO) AS COMPONENT_NO,
DATAMONTH,
ISNULL(CHANNEL_ID, '') + '_' + ISNULL(POSITION_ID, '') AS CHANNEL_POSITION,
ISNULL(CHANNEL_NAME, '') + '_' + ISNULL(POSITION_NAME, '') AS CHANNEL_POSITION_NAME
from SCNCAAF0461A1894981868ABA.PB36E6D13A82C4609B9488950
Group By COMPONENT_ID,
COMPONENT_NAME,
POSITION_ID,
POSITION_NAME,
CHANNEL_ID,
CHANNEL_NAME,
DATAMONTH
错误:无法正确分析Select语句。无法生成输出表
我认为他们的问题是中值函数。有人能帮忙吗?中间值在SQL Server中不存在-甚至在SQL Server 2012中也不存在,但仍需RTM'ed
如何使用SQL Server计算中值的问题是。据我所知,SQL Server不支持中值,至少不直接作为函数。当然,您可以使用SQL以某种方式计算中值。的可能重复项