Typescript-特定父级的扩展类数组

我有一个抽象类叫做Action：

我有几个扩展动作的类：

如何声明一个扩展了Action但不应该接受Action本身的类数组

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使用返回抽象类而不是抽象类的构造函数签名。抽象类在类型系统中没有构造函数，因此它将无效，但继承抽象类的任何派生类都将有效

abstract class Action { ... }

class Vote extends Action { ... }
class Upload extends Action { ... }

const actions: (new () => Action)[] = [
  Vote,    // OK (passes)
  Upload,  // OK (passes)
  File,    // OK (fails)
  Action   // Ok now (fails)
]

---

使用返回抽象类而不是抽象类的构造函数签名。抽象类在类型系统中没有构造函数，因此它将无效，但继承抽象类的任何派生类都将有效

abstract class Action { ... }

class Vote extends Action { ... }
class Upload extends Action { ... }

const actions: (new () => Action)[] = [
  Vote,    // OK (passes)
  Upload,  // OK (passes)
  File,    // OK (fails)
  Action   // Ok now (fails)
]

const actions: (typeof Action)[] = [
  Vote,    // OK (passes)
  Upload,  // OK (passes)
  File,    // OK (fails)
  Action   // BAD (passes)
]

abstract class Action { ... }

class Vote extends Action { ... }
class Upload extends Action { ... }

const actions: (new () => Action)[] = [
  Vote,    // OK (passes)
  Upload,  // OK (passes)
  File,    // OK (fails)
  Action   // Ok now (fails)
]