Typescript索引签名返回缺少索引签名的数组结果

我有一个类似JSON的

"phone":{
"home":[{"label":"Phone1", "val":"123"},{"label":"Phone1", "val":"123"},{"label":"Phone1", "val":"123"}],
"work":[{"label":"Phone1", "val":"123"}, {"label":"Phone1", "val":"123"}, {"label":"Phone1", "val":"123"}],
"....":[{"label":"Phone1", "val":"123"}]}

因此可能会有更多的电话对象，如紧急电话等，但我知道的是，该值将是一个label/val对象数组

所以我创建了一个接口

export interface Person {
    phone:IHashOfPhones
}

export interface IHashOfPhones {
    [index:string]: Phone[]
}

export interface Phone {
    label: string;
    val:string; 
}

然而，在编译过程中，我遇到了如下错误

Index signature is missing in type { home : ...

如果我将

IHashOfPhones

设置为返回

any

一切正常，但我松开了类型安全

在代码中，我只循环它，没有赋值

有没有办法确保类型安全，或者我做了一些完全错误的事情？

使用可转位类型 从JSON字符串：

let jsonString: string = `{
  phone: {
    home: [{ label: "Phone1", val: "123" }, { label: "Phone1", val: "123" }, { label: "Phone1", val: "123" }],
    work: [{ label: "Phone1", val: "123" }, { label: "Phone1", val: "123" }, { label: "Phone1", val: "123" }],
    other: [{ label: "Phone1", val: "123" }]
  }
}`;
let data1: Person = JSON.parse(jsonString);

或者，从JS对象：

let data2: Person = <any>{
  phone: {
    home: [{ label: "Phone1", val: "123" }, { label: "Phone1", val: "123" }, { label: "Phone1", val: "123" }],
    work: [{ label: "Phone1", val: "123" }, { label: "Phone1", val: "123" }, { label: "Phone1", val: "123" }],
    other: [{ label: "Phone1", val: "123" }]
  }
};

---

我想我和你做的一样，但在我的例子中，返回数组是因为某种原因不起作用的，该死……不，对象不是字符串。只需使用“来自JS对象”的示例，并将其转换为

。

export interface IHashOfPhones { // Replace the other implementation by this one
  home?: Phone[]
  work?: Phone[]
  other?: Phone[]
}
let data3: Person = {
  phone: {
    home: [{ label: "Phone1", val: "123" }, { label: "Phone1", val: "123" }, { label: "Phone1", val: "123" }],
    work: [{ label: "Phone1", val: "123" }, { label: "Phone1", val: "123" }, { label: "Phone1", val: "123" }],
    other: [{ label: "Phone1", val: "123" }]
  }
};