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Typescript 从基类推断泛型参数_Typescript - Fatal编程技术网

Typescript 从基类推断泛型参数

Typescript 从基类推断泛型参数,typescript,Typescript,我如何从基类推断出abcabc class BaseClass<T> {} class A extends BaseClass<'abc'> { constructor() { super() } } // NotAbc is 'unknown' type NotAbc = A extends BaseClass<infer I> ? I : never 类基类{} 类扩展了基类{ 构造函数(){ 超级() } } //NotAbc是“未

我如何从基类推断出abc
abc

class BaseClass<T> {}

class A extends BaseClass<'abc'> {
  constructor() {
    super()
  }
}

// NotAbc is 'unknown'
type NotAbc = A extends BaseClass<infer I> ? I : never
类基类{}
类扩展了基类{
构造函数(){
超级()
}
}
//NotAbc是“未知的”
类型NotAbc=A扩展基类?I:从来没有

它不起作用,因为未使用泛型参数:

class BaseClass<T> {
    t!: T
}

class A extends BaseClass<'abc'> {
    constructor() {
        super()
    }
}

// Abc is 'abc'
type Abc = A extends BaseClass<infer I> ? I : never
类基类{
t!:t
}
类扩展了基类{
构造函数(){
超级()
}
}
//Abc是“Abc”
类型Abc=扩展基类?I:从来没有
现在,它的工作如预期