typescript管理REST调用和回调

typescript管理REST调用和回调,typescript,firebase,code-organization,Typescript,Firebase,Code Organization,我正在使用带有typescript的googlefirebase函数。我有一个关于更好的代码管理的基本问题。当前我的代码如下所示: export const on_command_ping = functions.database.ref("commands/ping/{id}").onWrite(async (change, context) => { if(instr == '/my-sr'){ const reoptions = { u

我正在使用带有typescript的googlefirebase函数。我有一个关于更好的代码管理的基本问题。当前我的代码如下所示:

export const on_command_ping = functions.database.ref("commands/ping/{id}").onWrite(async (change, context) => {
    if(instr == '/my-sr'){
        const reoptions = {
            uri: baseUrl + '/serviceRequests',
            headers: {
                'Authorization': "Basic " + btoa(username + ":" + password)
            },
            json:true
        };

        const result = await rp.get(reoptions)
            .then(function(resp){
                console.log("got the response dude:" + JSON.stringify(resp))


                const options = {
                    uri: respUrl, 
                    method: "POST",
                    json: true,
                    body: { "attachments": [{
                                    "fallback": "Sorry failed to get response"}]
                          }
                 }
                 return rp(options);
               }));
     }else  if(instr == '/my-oher-stuff'){
        //another REST call
      }

正如您在上面所看到的,这将很难在单个函数中管理所有内容。那么,如何组织这段代码,使每个rest调用都是基于if-else从上面调用的单独函数呢

您可以将代码放入函数的IF块中

例:


在你的代码
instr
中从来没有定义过。对不起,为了简短起见,我吃了一些与我的问题不相关的东西。
export const on_command_ping = functions.database.ref("commands/ping/{id}").onWrite(async (change, context) => {
    if (instr == '/my-sr') {
        return function1(change, context)
    }
    else if (instr == '/my-oher-stuff') {
        return function2(change, context)
    } 
    else {
        return function3(change, context)
    }

});

function function1(change, context) {
    const reoptions = {
        uri: baseUrl + '/serviceRequests',
        headers: {
            'Authorization': "Basic " + btoa(username + ":" + password)
        },
        json: true
    };

    const result = await
    rp.get(reoptions)
        .then(function (resp) {
            console.log("got the response dude:" + JSON.stringify(resp))


            const options = {
                uri: respUrl,
                method: "POST",
                json: true,
                body: {
                    "attachments": [{
                        "fallback": "Sorry failed to get response"
                    }]
                }
            }
            return rp(options);
        }));
}

function function2(change, context) {
    //Some code here
}

function function3(change, context) {
    //Some code here
}