Excel VBA关于用户定义类型的错误处理
这是一个以编程方式安装API类型库的示例。为什么错误处理例程失败?我试图遵循Python中我熟悉的Excel VBA关于用户定义类型的错误处理,vba,excel,Vba,Excel,这是一个以编程方式安装API类型库的示例。为什么错误处理例程失败?我试图遵循Python中我熟悉的try…除了…最后策略 Sub CopyViewLayout(): 'TRY: On Error GoTo addReference Dim App As femap.model 'COMPILE ERROR: USER TYPE NOT DEFINED ResumeSub: Dim App As femap.model Set App = GetObject(,
try…除了…最后
策略
Sub CopyViewLayout():
'TRY:
On Error GoTo addReference
Dim App As femap.model
'COMPILE ERROR: USER TYPE NOT DEFINED
ResumeSub:
Dim App As femap.model
Set App = GetObject(, "femap.model")
Dim rc As Variant
Dim feView As femap.View
Set feView = App.feView
rc = feView.Get(0)
Exit Sub
'EXCEPT:
addReference:
Dim vbaEditor As VBIDE.VBE
Dim vbProj As VBIDE.VBProject
Dim checkRef As VBIDE.Reference
Dim filepath As String
Set vbaEditor = Application.VBE
Set vbProj = ActiveWorkbook.VBProject
filepath = "C:\apps\FEMAPv11\"
On Error GoTo Failure
vbProj.References.AddFromFile (filepath & "femap.tlb")
Set vbProj = Nothing
Set vbaEditor = Nothing
GoTo ResumeSub
'FINALLY
Failure:
MsgBox ("couldn't find type library, exiting sub")
End Sub
编辑
我从main中打断了这个部分,因为在VBA中错误处理是非常可笑的。。。对我来说,更好的方法是使用布尔实现有限状态机
回答
Sub refcheck()
Dim i As Long
Dim FEMAP_GUID As String
FEMAP_GUID = "{08F336B3-E668-11D4-9441-001083FFF11C}"
With ActiveWorkbook.VBProject.references
For i = 1 To .Count
If .Item(i).GUID = FEMAP_GUID Then
Exit For
Else
'note: filepath is determined using Dir() elsewhere...
.AddFromFile (filepath & "femap.tlb")
Exit For
End If
Next
End With
End Sub
错误处理只处理运行时错误;不是编译时错误。使用
Dim App as Object
并确保在代码中只使用一次Dim App
通过将
用作对象
,可以将任何对象延迟绑定到它。当你编码思想时,你会失去智能感知。就像迪克提到的那样,使用后期绑定,但光靠它是不够的。您必须在正确处理错误的情况下使用它
比如说
Dim App As Object
On Error Resume Next
Set App = GetObject(, "femap.model")
On Error GoTo 0
If App Is Nothing Then
MsgBox "Please check if femap is installed"
Exit Sub
End If
'
'~~> Rest of the code
'
如果您确定它已安装,那么您将收到错误,因为未引用相关库。为此,我建议您看看
但是,我仍然建议您采用后期绑定路线。VBA中的错误处理与
try…catch
一样无效-尝试模仿它只会导致痛苦和痛苦。对我来说,错误处理可能是最困难的挑战。为了解决这个问题,我绘制了一个依赖项和子项的流程图/路线图,并创建了一组模块范围布尔函数,作为“门”中的“键”,其中门是主要的键依赖调用。编辑问题的答案可以克服堆栈溢出的Q&a性质。。你也许应该贴一个答案。@Mat'smugh,好吧,我会的。谢谢