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VBA MSSOAP.SoapClient30错误:为SOAP请求提供的参数数量不正确HRESULT=0x80070057_Vba_Soap - Fatal编程技术网

VBA MSSOAP.SoapClient30错误:为SOAP请求提供的参数数量不正确HRESULT=0x80070057

VBA MSSOAP.SoapClient30错误:为SOAP请求提供的参数数量不正确HRESULT=0x80070057,vba,soap,Vba,Soap,更新:所以我想我需要以某种方式在方法参数处提交一个复杂类型-如何使用VBA实现这一点 这是我第一次编写VBA代码,我将非常感谢任何关于如何解决问题的建议。基本上,我已经编写了一个小的soap服务,它工作得很好-我用SoapUI测试它-所以我想其他应用程序应该能够使用它 。也许,对于VBScript SOAPClient来说,它并不太友好——在这个方向上的任何点都会有很大帮助 我试图把一些实际使用它的代码放在一起(下面是VBScript)——我在谷歌搜索时发现的一个示例的基础上构建了它。它会生成以

更新:所以我想我需要以某种方式在方法参数处提交一个复杂类型-如何使用VBA实现这一点

这是我第一次编写VBA代码,我将非常感谢任何关于如何解决问题的建议。基本上,我已经编写了一个小的soap服务,它工作得很好-我用SoapUI测试它-所以我想其他应用程序应该能够使用它

。也许,对于VBScript SOAPClient来说,它并不太友好——在这个方向上的任何点都会有很大帮助

我试图把一些实际使用它的代码放在一起(下面是VBScript)——我在谷歌搜索时发现的一个示例的基础上构建了它。它会生成以下错误:

Incorrect number of parameters supplied for SOAP request HRESULT=0x80070057

Module Module1

    Dim WSDLFileName As String
    Dim base64attachment As String
    Dim attachment_filename As String
    Dim summary As String
    Dim SoapClient
    Dim res

    Sub Main()
        WSDLFileName = "http://localhost:7777/?wsdl"
        base64attachment = "UG9ydG1hbiBpcyBwb3J0Zm9saW8gbWFuYWdlbWVudCBzb2Z0d2FyZSB0byBoZWxwIFBNTyBrZWV"
        attachment_filename = "test_file.txt"
        summary = "test issue with summary"
        SoapClient = CreateObject("MSSOAP.SoapClient30")
        SoapClient.MSSoapInit(WSDLFileName)
        res = SoapClient.CreateJiraIssueWithBase64Attachment(summary, base64attachment, attachment_filename)
        Console.Out.WriteLine(res)
    End Sub

End Module
任何指示都会有帮助,我在这里迷路了

我希望它会产生如下响应:

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:open="open.JiraAdapter">
   <soapenv:Header/>
   <soapenv:Body>
      <open:CreateJiraIssueWithBase64Attachment>
         <open:summary>some summary</open:summary>
         <open:base64attachment>BASE64CODEDFILE</open:base64attachment>
         <open:attachment_filename>NAME of the file attached</open:attachment_filename>
      </open:CreateJiraIssueWithBase64Attachment>
   </soapenv:Body>
</soapenv:Envelope>

一些总结
BASE64CODEDFILE
所附文件的名称

您的服务响应包含复杂类型的对象

<xs:element name="CreateJiraIssueWithBase64AttachmentResult" type="s0:Status" minOccurs="0" nillable="true"/>
希望这对你有帮助

Connector = CreateObject("MSSOAP.HttpConnector30") 
Connector.Property("EndPointURL") = "url"
Connector.Property("UseSSL") = True
Connector.Connect
Connector.Property("SoapAction") = "CreateJiraIssueWithBase64Attachment"
Connector.BeginMessage

Serializer = CreateObject("MSSOAP.SoapSerializer30")
Serializer.Init(Connector.InputStream)
Serializer.StartEnvelope
Serializer.StartBody
Serializer.StartElement("CreateJiraIssueWithBase64Attachment";"open.jiraAdapter.test")
Serializer.StartElement("summary";"open.jiraAdapter.test")
Serializer.WriteString("another test issue for JUR")
Serializer.EndElement
Serializer.StartElement("base64attachment";"open.jiraAdapter.test")
Serializer.WriteString("Y29kZTogaHR0cDovL3Bhc3RlYmluLmNvbS9EbUx3N0oycQ0KeG1sOiBodHRwOi8vcGFzdGViaW4uY29tLzE3Q2MxVjJM")
Serializer.EndElement 
Serializer.StartElement("attachment_filename";"open.jiraAdapter.test")
Serializer.WriteString("readme.txt")
Serializer.EndElement   
Serializer.EndElement   
Serializer.EndBody
Serializer.EndEnvelope    
Connector.EndMessage

Reader = CreateObject("MSSOAP.SoapReader30")
Reader.Load(Connector.OutputStream)  
/// Reader.Body.xml - response