View 注销更改视图sencha touch
嗨,我需要在我的sencha touch应用程序中实现保持登录 请参阅下面我的代码: Login.js-一旦用户单击Login,它将在本地存储中存储“sessionToken”。然后它将转到主页View 注销更改视图sencha touch,view,login,sencha-touch-2,logout,View,Login,Sencha Touch 2,Logout,嗨,我需要在我的sencha touch应用程序中实现保持登录 请参阅下面我的代码: Login.js-一旦用户单击Login,它将在本地存储中存储“sessionToken”。然后它将转到主页 onBtnLoginClick: function(){ var loginviewGetValue = Ext.getCmp('loginview').getValues(); var bbid = Ext.getCmp('bbID').ge
onBtnLoginClick: function(){
var loginviewGetValue = Ext.getCmp('loginview').getValues();
var bbid = Ext.getCmp('bbID').getValue();
var bbpassword = Ext.getCmp('bbPassword').getValue();
var LoginLS = Ext.getStore('LoginLS');
LoginLS.add({
sessionId: 'sadsadsadasd'
,deviceId:'1'
,bb_id :bbid
});
LoginLS.sync();
var mainForm= Ext.create('bluebutton.view.Main');
Ext.Viewport.setActiveItem(mainForm);
launch: function() {
// Destroy the #appLoadingIndicator element
Ext.fly('appLoadingIndicator').destroy();
// Initialize the main view
var LoginLS = Ext.getStore('LoginLS');
LoginLS.load();
var record = LoginLS.getAt(0);
if(record != undefined){
var sessionId = record.get('sessionId');
if (sessionId !=undefined){
Ext.Viewport.add(Ext.create('bluebutton.view.Main'));
}
else
Ext.Viewport.add(Ext.create('bluebutton.view.Login'));
}
else{
Ext.Viewport.add(Ext.create('bluebutton.view.Login'));
}
// Ext.create('bluebutton.view.TopMenuList');
},
App.js~每次启动函数都会检查localStorage中的sessionToken。如果Localstorage为空,则它将转到登录页。否则它将转到主页
onBtnLoginClick: function(){
var loginviewGetValue = Ext.getCmp('loginview').getValues();
var bbid = Ext.getCmp('bbID').getValue();
var bbpassword = Ext.getCmp('bbPassword').getValue();
var LoginLS = Ext.getStore('LoginLS');
LoginLS.add({
sessionId: 'sadsadsadasd'
,deviceId:'1'
,bb_id :bbid
});
LoginLS.sync();
var mainForm= Ext.create('bluebutton.view.Main');
Ext.Viewport.setActiveItem(mainForm);
launch: function() {
// Destroy the #appLoadingIndicator element
Ext.fly('appLoadingIndicator').destroy();
// Initialize the main view
var LoginLS = Ext.getStore('LoginLS');
LoginLS.load();
var record = LoginLS.getAt(0);
if(record != undefined){
var sessionId = record.get('sessionId');
if (sessionId !=undefined){
Ext.Viewport.add(Ext.create('bluebutton.view.Main'));
}
else
Ext.Viewport.add(Ext.create('bluebutton.view.Login'));
}
else{
Ext.Viewport.add(Ext.create('bluebutton.view.Login'));
}
// Ext.create('bluebutton.view.TopMenuList');
},
Logout.js~注销将清除sessionToken并再次进入登录页面
onLogoutClick: function scan() {
var LoginLS = Ext.getStore('LoginLS');
Ext.Viewport.setMasked({
xtype: 'loadmask',
message: 'Loading...'
});
LoginLS.load();
var record = LoginLS.getAt(0);
LoginLS.removeAll();
LoginLS.sync();
//Load a new view
// Ext.getCmp('tabpanel').destroy();
var loginForm = Ext.create('bluebutton.view.Login');
Ext.Viewport.setActiveItem(loginForm);
Ext.Viewport.setMasked(false); // hide the load screen
但我现在有个问题。我无法返回登录页面。它转到空白页。请给我一些解决办法。谢谢
这是我得到的错误
[WARN][Ext.data.Batch#runOperation] Your identifier generation strategy for the model does not ensure unique id's. Please use the UUID strategy, or implement your own identifier strategy with the flag isUnique. Console.js:35
[WARN][Ext.Component#constructor] Registering a component with a id (`loginview`) which has already been used. Please ensure the existing component has been destroyed (`Ext.Component#destroy()`. Console.js:35
[WARN][Ext.Component#constructor] Registering a component with a id (`bbID`) which has already been used. Please ensure the existing component has been destroyed (`Ext.Component#destroy()`. Console.js:35
[WARN][Ext.Component#constructor] Registering a component with a id (`bbPassword`) which has already been used. Please ensure the existing component has been destroyed (`Ext.Component#destroy()`. Console.js:35
[WARN][Ext.Component#constructor] Registering a component with a id (`btnLogin`) which has already been used. Please ensure the existing component has been destroyed (`Ext.Component#destroy()`. Console.js:35
[DEPRECATE][bluebutton.view.Login#show] Call show() on a component that doesn't currently belong to any container. Please add it to the the Viewport first, i.e: Ext.Viewport.add(component);
对组件使用
itemId
,而不是id
,并在Controller
中相应地引用它们。检查此问题:查看错误消息,很明显您正在尝试再次创建登录面板,而不销毁现有组件。出现错误是因为不允许您在应用程序中多次使用相同的id
为了避免这种情况,您不应该多次创建同一个视图,您应该重用视图,这对性能也有好处。还有一件事,您应该给n元素id
,当且仅当您不能没有它时
假设无法避免id
属性,则应执行以下两项操作之一:
var loginView = Ext.getCmp("loginview");
if(!loginView){
loginView = Ext.create('bluebutton.view.Login');
}
var loginView = Ext.getCmp("loginview");
loginView.destroy();
你得到的错误是什么>嗨,我更新了我的问题。你是什么意思?我不明白。很抱歉,我是新来的sencha touchCool Floyd,第二个对我来说更有价值!