Windows phone 8 从本地存储器读取

在jumpstart视频中（为Windows Phone 8 jumpstart构建应用程序） 他们展示了给我错误信息的示例代码： 异步方法的返回类型必须为void、Task或T的Task

这是示例代码：

//open
private async string loadStringAsync()
{
   string theData = string.Empty;

   //Get a reference to the local folder
   StorageFolder localFolder = ApplicationData.Current.LocalFolder;
   StorageFile storageFile = await localFolder.GetFileAsync("MyFile.store");

   //Open it and read it
   Stream readStream = await storageFile.OpenStreamForReadAsync();
   using (StreamReader reader = new StreamReader(readStream))
   {
     theData = await reader.ReadToEndAsync();
   }
   return theData;
}

我想它需要一个简单的修复程序，但由于我对编程还不熟悉，并且该视频上的注释被禁用，我不知道如何…

var a=loadStringAsync（）；
var a = loadStringAsync();

private async Task<string> loadStringAsync()
{
    string theData = string.Empty;

    //Get a reference to the local folder
    StorageFolder localFolder = ApplicationData.Current.LocalFolder;
    StorageFile storageFile = await localFolder.GetFileAsync("MyFile.store");

    //Open it and read it
    Stream readStream = await storageFile.OpenStreamForReadAsync();
    using (StreamReader reader = new StreamReader(readStream))
    {
       theData = await reader.ReadToEndAsync();
    }
    return theData;
}

专用异步任务loadStringAsync（）
{
string theData=string.Empty；
//获取对本地文件夹的引用
StorageFolder localFolder=ApplicationData.Current.localFolder；
StorageFile StorageFile=await localFolder.GetFileAsync（“MyFile.store”）；
//打开并阅读它
Stream readStream=wait storageFile.OpenStreamForReadAsync（）；
使用（StreamReader=新StreamReader（readStream））
{
theData=wait reader.ReadToEndAsync（）；
}
返回数据；
}

你读到错误了吗？谢谢你的链接，我想最好先读一下异步编程：）