Windows phone 8 检测何时发生web服务发布

我刚刚编写了一个简单的Windows8表单，可以发布到web服务api。它很好用。但我的挑战是能够确定手术后的成功与失败。我不知道如何返回值，因为aysnc任务不允许返回类型

//This class does the post to web service 
public class B2cMobileuserService : IB2cMobileuserService
    {
        private  string RegisterUserUrl = RestfulUrl.RegisterMobileUser;
        private readonly HttpClient _client = new HttpClient();


        public async Task RegisterMobileUser(B2cMobileuserView user)
        {
            var jsonString = Serialize(user);
            var content = new StringContent(jsonString, Encoding.UTF8, "application/json");
            var result = await _client.PostAsync(RegisterUserUrl, content);           
        }
}


//This class calls the one above

 public class WebserviceProcessor
    {
        //declaring all the service objects that would be used
        IB2cMobileuserService mobileuserService = null;

        public WebserviceProcessor() {
            mobileuserService = new B2cMobileuserService();
        }


        //This method is going to post values to the web serever
        public async void RegisterUser(B2cMobileuserView mobileuser) {
           mobileuserService.RegisterMobileUser(mobileuser);
        }


    }



//Then the code below is from my .xaml user interface that calls the class that sends to webservice

  private void Button_Click(object sender, RoutedEventArgs e)
        {
            B2cMobileuserView user = new B2cMobileuserView();
            user.Name = name.Text;
            user.Email = email.Text;
            user.PhoneType = "Windows Mobile";
            user.BrowserType = "None";
            user.CountryName = "Nigeria";
            user.UserPhoneID = phone.Text;

            Serviceprocessor.RegisterUser(user);

            progressBar.Visibility = Visibility.Visible;
        }


Please I dont know how to return a value cos when I try I get the error that says async method must be void. 
I need to set a way to know when the post was a success based on the return value from the web service.

---

要确保POST成功，请调用HttpResponseMessage.EnsureResessAccessStatusCode：

public async Task RegisterMobileUser(B2cMobileuserView user)
{
  var jsonString = Serialize(user);
  var content = new StringContent(jsonString, Encoding.UTF8, "application/json");
  var result = await _client.PostAsync(RegisterUserUrl, content);           
  result.EnsureSuccessStatusCode();
}

如果要返回值，请使用

任务

返回类型，而不是

任务

另一方面，要避免异步无效；使用

async Task

而不是

async void

，除非编译器强制您编写

async void

：

//This method is going to post values to the web serever
public Task RegisterUser(B2cMobileuserView mobileuser) {
  return mobileuserService.RegisterMobileUser(mobileuser);
}

另外，您应该将异步方法命名为

*Async

：

//This method is going to post values to the web serever
public Task RegisterUserAsync(B2cMobileuserView mobileuser) {
  return mobileuserService.RegisterMobileUserAsync(mobileuser);
}

---

您可能会发现我的帮助很大。

请在这里帮助我。我是这样返回任务的。或者你能给我一个示例方法吗。返回并测试您的响应。我真的很感激。只需要一个样品，你想要什么就给什么。我认为解析出服务器响应并返回比

HttpResponseMessage

更有意义的内容是最有意义的。我读了这篇文章。我现在的挑战是无法在按钮事件处理程序中调用该方法。它说等待运算符只能在asyc方法中使用。事件处理程序可以是

async void

。