Wpf 如何使用集合在ContextMenu中创建根级菜单项？

我们有一组DesignerLocation对象存储在ViewModel的属性中。我们希望为每个项目创建上下文菜单，以便用户可以轻松访问它们

目前，我们正在将该集合绑定到特定“打开…”上下文菜单的Items属性，这意味着用户必须弹出该菜单，即使只有一个设计器位置

e、 这是一个过于简化的上下文菜单，有三个设计师的位置

Open in... (<-- This menu's Items property is bound to DesignerLocations)
    Open DesignerLocation1
    Open DesignerLocation2
    Open DesignerLocation3
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这是我们真正想要的

…如果只有一个

Open DesignerLocation1
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也就是说，如何在不必求助于复合集合或手动响应ContextMenuOpening的情况下实现以下内容

<MenuCollectionPlaceholder>  <-- This would be bound to DesignerLocations and would generate MenuItems as needed without requiring the flyout
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最后，我看到人们直接在上下文菜单中放置ItemsControl，但我觉得这是错误的，因为ItemsControl本身不是MenuItem。错了吗？那会给我们我们想要的

<ItemsControl>  <-- This would be bound to DesignerLocations and would generate MenuItems as needed without requiring the flyout
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<MenuCollectionPlaceholder>  <-- This would be bound to DesignerLocations and would generate MenuItems as needed without requiring the flyout
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<ItemsControl>  <-- This would be bound to DesignerLocations and would generate MenuItems as needed without requiring the flyout
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