Wpf 如何将DataGrid转换为dataTable
我想将所有datagrid记录复制到datatable中,而不使用任何循环。 例如: 但这不起作用,并发出错误消息Wpf 如何将DataGrid转换为dataTable,wpf,vb.net,wpfdatagrid,wpf-4.0,Wpf,Vb.net,Wpfdatagrid,Wpf 4.0,我想将所有datagrid记录复制到datatable中,而不使用任何循环。 例如: 但这不起作用,并发出错误消息 我的开发平台是Visual studio 2010,语言是WPF和vb.net 4.0,这取决于数据网格的填充方式。如果DataContext属性设置为DataTable,则只需检索该值并转换为DataTable即可 没有直接方法将其从DataGrid元素转换为DataTable 如果要手动执行此操作,则必须创建DataTable的实例,然后使用循环从DataGrid中的项创建行。
我的开发平台是Visual studio 2010,语言是WPF和vb.net 4.0,这取决于数据网格的填充方式。如果DataContext属性设置为DataTable,则只需检索该值并转换为DataTable即可 没有直接方法将其从DataGrid元素转换为DataTable
如果要手动执行此操作,则必须创建DataTable的实例,然后使用循环从DataGrid中的项创建行。必须在DataGrid上循环并将项添加到DataTable。下面的链接可能会有所帮助
我刚刚测试了这个,这个很有效
Dim dt as New DataTable
dt = ctype(Datagrid1.Datasource, DataTable)
这是在不使用循环的情况下将所有记录从DATAGRID传输到DATATABLE的方法 VB:
Dim dt As New DataTable
dt = CType(DataGrid1.ItemsSource, DataView).ToTable
DataTable dt = new DataTable();
dt = ((DataView)DataGrid1.ItemsSource).ToTable();
C#:
Dim dt As New DataTable
dt = CType(DataGrid1.ItemsSource, DataView).ToTable
DataTable dt = new DataTable();
dt = ((DataView)DataGrid1.ItemsSource).ToTable();
要将dataGrid转换为具有标题行的数据表,可以执行以下步骤: 1) 创建检索单元格的方法
static public DataGridCell GetCell(DataGrid dg, int row, int column)
{
DataGridRow rowContainer = GetRow(dg, row);
if (rowContainer != null)
{
DataGridCellsPresenter presenter = GetVisualChild<DataGridCellsPresenter>(rowContainer);
DataGridCell cell = (DataGridCell)presenter.ItemContainerGenerator.ContainerFromIndex(column);
if (cell == null)
{
dg.ScrollIntoView(rowContainer, dg.Columns[column]);
cell = (DataGridCell)presenter.ItemContainerGenerator.ContainerFromIndex(column);
}
return cell;
}
return null;
}
这里有一个helper类来使用它
/// <summary>
/// Class to help to retrive the Data Grid Contain
/// </summary>
public static class DataGridHelper
{
/// <summary>
/// Retrive the cell contains
/// </summary>
/// <param name="dg">DataGrid</param>
/// <param name="row">row</param>
/// <param name="column">column</param>
/// <returns>DataGrid Cell content</returns>
static public DataGridCell GetCell(DataGrid dg, int row, int column)
{
DataGridRow rowContainer = GetRow(dg, row);
if (rowContainer != null)
{
DataGridCellsPresenter presenter = GetVisualChild<DataGridCellsPresenter>(rowContainer);
// try to get the cell but it may possibly be virtualized
DataGridCell cell = (DataGridCell)presenter.ItemContainerGenerator.ContainerFromIndex(column);
if (cell == null)
{
// now try to bring into view and retreive the cell
dg.ScrollIntoView(rowContainer, dg.Columns[column]);
cell = (DataGridCell)presenter.ItemContainerGenerator.ContainerFromIndex(column);
}
return cell;
}
return null;
}
/// <summary>
/// Get row content
/// </summary>
/// <param name="dg">Datagrid</param>
/// <param name="index">Index</param>
/// <returns>DataGridRow</returns>
static public DataGridRow GetRow(DataGrid dg, int index)
{
DataGridRow row = (DataGridRow)dg.ItemContainerGenerator.ContainerFromIndex(index);
if (row == null)
{
// may be virtualized, bring into view and try again
dg.ScrollIntoView(dg.Items[index]);
row = (DataGridRow)dg.ItemContainerGenerator.ContainerFromIndex(index);
}
return row;
}
static T GetVisualChild<T>(Visual parent) where T : Visual
{
T child = default(T);
int numVisuals = VisualTreeHelper.GetChildrenCount(parent);
for (int i = 0; i < numVisuals; i++)
{
Visual v = (Visual)VisualTreeHelper.GetChild(parent, i);
child = v as T;
if (child == null)
{
child = GetVisualChild<T>(v);
}
if (child != null)
{
break;
}
}
return child;
}
}
//
///类以帮助检索包含的数据网格
///
公共静态类DataGridHelper
{
///
///检索单元格包含的内容
///
///数据网格
///划船
///纵队
///数据网格单元内容
静态公共DataGridCell GetCell(DataGrid dg,int行,int列)
{
DataGridRow rowContainer=GetRow(dg,row);
if(rowContainer!=null)
{
DataGridCellsPresenter=GetVisualChild(行容器);
//尝试获取该单元,但它可能已虚拟化
DataGridCell=(DataGridCell)presenter.ItemContainerGenerator.ContainerFromIndex(列);
if(单元格==null)
{
//现在试着把手机放在视野里,然后拿回手机
dg.ScrollIntoView(行容器,dg.Columns[列]);
单元格=(DataGridCell)presenter.ItemContainerGenerator.ContainerFromIndex(列);
}
返回单元;
}
返回null;
}
///
///获取行内容
///
///数据网格
///索引
///DataGridRow
静态公共DataGridRow GetRow(DataGrid dg,int索引)
{
DataGridRow行=(DataGridRow)dg.ItemContainerGenerator.ContainerFromIndex(索引);
if(行==null)
{
//可能已虚拟化,请查看并重试
总卷轴视图(总项目[索引]);
行=(DataGridRow)dg.ItemContainerGenerator.ContainerFromIndex(索引);
}
返回行;
}
静态T GetVisualChild(可视父级),其中T:Visual
{
T child=默认值(T);
int numVisuals=VisualTreeHelper.GetChildrenCount(父级);
对于(int i=0;i
我在C#DataGrid上找不到“ItemSource”,如何使用mvvmI可以很好地实现这一点,但我不得不添加自己的GetVisualChild和GetRow方法,因为它们没有发布在这里。很抱歉,忘记了,但正如您看到的,创建自己的方法来检索row和GetVisualChild很容易。让我知道如果你想我发布了这个方法,你可以添加这些方法,使答案完整吗?嗨,杰里米,我添加了助手类,我希望这能帮助你
/// <summary>
/// Class to help to retrive the Data Grid Contain
/// </summary>
public static class DataGridHelper
{
/// <summary>
/// Retrive the cell contains
/// </summary>
/// <param name="dg">DataGrid</param>
/// <param name="row">row</param>
/// <param name="column">column</param>
/// <returns>DataGrid Cell content</returns>
static public DataGridCell GetCell(DataGrid dg, int row, int column)
{
DataGridRow rowContainer = GetRow(dg, row);
if (rowContainer != null)
{
DataGridCellsPresenter presenter = GetVisualChild<DataGridCellsPresenter>(rowContainer);
// try to get the cell but it may possibly be virtualized
DataGridCell cell = (DataGridCell)presenter.ItemContainerGenerator.ContainerFromIndex(column);
if (cell == null)
{
// now try to bring into view and retreive the cell
dg.ScrollIntoView(rowContainer, dg.Columns[column]);
cell = (DataGridCell)presenter.ItemContainerGenerator.ContainerFromIndex(column);
}
return cell;
}
return null;
}
/// <summary>
/// Get row content
/// </summary>
/// <param name="dg">Datagrid</param>
/// <param name="index">Index</param>
/// <returns>DataGridRow</returns>
static public DataGridRow GetRow(DataGrid dg, int index)
{
DataGridRow row = (DataGridRow)dg.ItemContainerGenerator.ContainerFromIndex(index);
if (row == null)
{
// may be virtualized, bring into view and try again
dg.ScrollIntoView(dg.Items[index]);
row = (DataGridRow)dg.ItemContainerGenerator.ContainerFromIndex(index);
}
return row;
}
static T GetVisualChild<T>(Visual parent) where T : Visual
{
T child = default(T);
int numVisuals = VisualTreeHelper.GetChildrenCount(parent);
for (int i = 0; i < numVisuals; i++)
{
Visual v = (Visual)VisualTreeHelper.GetChild(parent, i);
child = v as T;
if (child == null)
{
child = GetVisualChild<T>(v);
}
if (child != null)
{
break;
}
}
return child;
}
}