XSL将具有属性的xml行转换为无序列表树视图
以下XML来自SharePoint控件。我想使用XSLT转换以生成嵌套的ul>li列表。但是当我迭代每一行时,我遇到了问题,主文件夹会对每一行重复,而不是创建一个主文件夹节点并在该节点下添加Menu_Display_name的值来模拟树视图。。。 我的XML类似于:XSL将具有属性的xml行转换为无序列表树视图,xml,xslt,xslt-1.0,xslt-grouping,muenchian-grouping,Xml,Xslt,Xslt 1.0,Xslt Grouping,Muenchian Grouping,以下XML来自SharePoint控件。我想使用XSLT转换以生成嵌套的ul>li列表。但是当我迭代每一行时,我遇到了问题,主文件夹会对每一行重复,而不是创建一个主文件夹节点并在该节点下添加Menu_Display_name的值来模拟树视图。。。 我的XML类似于: <dsQueryResponse> <NewDataSet> <Row DOMAIN_USERNAME="someUser" PRIMARY_FOLDER="XYZ CORP H
<dsQueryResponse>
<NewDataSet>
<Row DOMAIN_USERNAME="someUser" PRIMARY_FOLDER="XYZ CORP HR TIME SELF SERVICE" SECONDARY_FOLDER="Time" MENU_DISPLAY_NAME="Create Timecard"></Row>
<Row DOMAIN_USERNAME="someUser" PRIMARY_FOLDER="XYZ CORP HR TIME SELF SERVICE" SECONDARY_FOLDER="Time" MENU_DISPLAY_NAME="Recent Timecards"></Row>
<Row DOMAIN_USERNAME="someUser" PRIMARY_FOLDER="XYZ CORP HR TIME SELF SERVICE" SECONDARY_FOLDER="Time" MENU_DISPLAY_NAME="Templates"></Row>
<Row DOMAIN_USERNAME="someUser" PRIMARY_FOLDER="XYZ CORP HR TIME SELF SERVICE" SECONDARY_FOLDER="Time" MENU_DISPLAY_NAME="Timecard Search"></Row>
<Row DOMAIN_USERNAME="someUser" PRIMARY_FOLDER="XYZ CORP EXP ENTRY" SECONDARY_FOLDER="" MENU_DISPLAY_NAME="Expenses Home"></Row>
<Row DOMAIN_USERNAME="someUser" PRIMARY_FOLDER="XYZ HR EMP SELF SERVICE" SECONDARY_FOLDER="" MENU_DISPLAY_NAME="Accommodation Request"></Row>
<Row DOMAIN_USERNAME="someUser" PRIMARY_FOLDER="XYZ HR EMP SELF SERVICE" SECONDARY_FOLDER="" MENU_DISPLAY_NAME="Additional Personal Information" ></Row>
<Row DOMAIN_USERNAME="someUser" PRIMARY_FOLDER="XYZ HR EMP SELF SERVICE" SECONDARY_FOLDER="" MENU_DISPLAY_NAME="All Actions Awaiting Your Attention"></Row>
<Row DOMAIN_USERNAME="someUser" PRIMARY_FOLDER="XYZ HR EMP SELF SERVICE" SECONDARY_FOLDER="" MENU_DISPLAY_NAME="Appraisals"></Row>
</NewDataSet>
</dsQueryResponse>
我对XSL的“穷人尝试”是这样的:
<xsl:template name="dvt_1.body">
<xsl:param name="Rows" />
<xsl:param name="FirstRow" />
<xsl:param name="LastRow" />
<ul>
<xsl:for-each select="$Rows">
<xsl:if test="position() >= $FirstRow and position() <= $LastRow">
<xsl:call-template name="dvt_1.rowview" />
</xsl:if>
</xsl:for-each>
</ul>
</xsl:template>
<xsl:template name="dvt_1.rowview">
<li class="isFolder isExpanded">
<xsl:value-of select="@PRIMARY_FOLDER" />
<xsl:choose>
<xsl:when test="@SECONDARY_FOLDER != ''">
<ul>
<li class="isFolder isExpanded">
<xsl:value-of select="@SECONDARY_FOLDER" />
<ul>
<li><xsl:value-of select="@MENU_DISPLAY_NAME" /></li>
</ul>
</li>
</ul>
</xsl:when>
<xsl:otherwise>
<ul>
<li><xsl:value-of select="@MENU_DISPLAY_NAME" /></li>
</ul>
</xsl:otherwise>
</xsl:choose>
</li>
</xsl:template>
<div id="navigator">
<ul>
<li class="isFolder isExpanded">
XYZ CORP HR TIME SELF SERVICE
<ul>
<li class="isFolder isExpanded">
Time
<ul>
<li><a href="#" target="_tab">Create Timecard</a></li>
<li><a href="#" target="_tab">Recent Timecards</a></li>
<li><a href="#" target="_tab">Templates</a></li>
<li><a href="#" target="_tab">Timecard Search</a></li>
</ul>
</li>
</ul>
</li>
<li class="isFolder isExpanded">
XYZ CORP EXP ENTRY
<ul>
<li><a href="#" target="_tab">Expense Home</a></li>
</ul>
</li>
<li class="isFolder isExpanded">
XYZ HR EMP SELF SERVICE
<ul>
<li><a href="#" target="_tab">Accommodation Request</a></li>
<li><a href="#" target="_tab">Additional Personal Information</a></li>
<li><a href="#" target="_tab">All Actions Awaiting Your Attention</a></li>
<li><a href="#" target="_tab">Appraisals</a></li>
</ul>
</li>
</ul>
</div>
<xsl:key name="primary" match="Row" use="@PRIMARY_FOLDER" />
-
我想要的xsl输出如下:
<xsl:template name="dvt_1.body">
<xsl:param name="Rows" />
<xsl:param name="FirstRow" />
<xsl:param name="LastRow" />
<ul>
<xsl:for-each select="$Rows">
<xsl:if test="position() >= $FirstRow and position() <= $LastRow">
<xsl:call-template name="dvt_1.rowview" />
</xsl:if>
</xsl:for-each>
</ul>
</xsl:template>
<xsl:template name="dvt_1.rowview">
<li class="isFolder isExpanded">
<xsl:value-of select="@PRIMARY_FOLDER" />
<xsl:choose>
<xsl:when test="@SECONDARY_FOLDER != ''">
<ul>
<li class="isFolder isExpanded">
<xsl:value-of select="@SECONDARY_FOLDER" />
<ul>
<li><xsl:value-of select="@MENU_DISPLAY_NAME" /></li>
</ul>
</li>
</ul>
</xsl:when>
<xsl:otherwise>
<ul>
<li><xsl:value-of select="@MENU_DISPLAY_NAME" /></li>
</ul>
</xsl:otherwise>
</xsl:choose>
</li>
</xsl:template>
<div id="navigator">
<ul>
<li class="isFolder isExpanded">
XYZ CORP HR TIME SELF SERVICE
<ul>
<li class="isFolder isExpanded">
Time
<ul>
<li><a href="#" target="_tab">Create Timecard</a></li>
<li><a href="#" target="_tab">Recent Timecards</a></li>
<li><a href="#" target="_tab">Templates</a></li>
<li><a href="#" target="_tab">Timecard Search</a></li>
</ul>
</li>
</ul>
</li>
<li class="isFolder isExpanded">
XYZ CORP EXP ENTRY
<ul>
<li><a href="#" target="_tab">Expense Home</a></li>
</ul>
</li>
<li class="isFolder isExpanded">
XYZ HR EMP SELF SERVICE
<ul>
<li><a href="#" target="_tab">Accommodation Request</a></li>
<li><a href="#" target="_tab">Additional Personal Information</a></li>
<li><a href="#" target="_tab">All Actions Awaiting Your Attention</a></li>
<li><a href="#" target="_tab">Appraisals</a></li>
</ul>
</li>
</ul>
</div>
<xsl:key name="primary" match="Row" use="@PRIMARY_FOLDER" />
-
XYZ公司人力资源时间自助服务
-
时间
-
XYZ公司出口报关单
-
XYZ HR EMP自助服务
有人能帮助我使用xslt实现这一点吗?确实是xslt 1.0中需要了解的内容(我相信Sharepoint就是这么使用的)。首先,通过PRIMARY\u VALUE
属性进行分组,这样就有了如下键:
<xsl:template name="dvt_1.body">
<xsl:param name="Rows" />
<xsl:param name="FirstRow" />
<xsl:param name="LastRow" />
<ul>
<xsl:for-each select="$Rows">
<xsl:if test="position() >= $FirstRow and position() <= $LastRow">
<xsl:call-template name="dvt_1.rowview" />
</xsl:if>
</xsl:for-each>
</ul>
</xsl:template>
<xsl:template name="dvt_1.rowview">
<li class="isFolder isExpanded">
<xsl:value-of select="@PRIMARY_FOLDER" />
<xsl:choose>
<xsl:when test="@SECONDARY_FOLDER != ''">
<ul>
<li class="isFolder isExpanded">
<xsl:value-of select="@SECONDARY_FOLDER" />
<ul>
<li><xsl:value-of select="@MENU_DISPLAY_NAME" /></li>
</ul>
</li>
</ul>
</xsl:when>
<xsl:otherwise>
<ul>
<li><xsl:value-of select="@MENU_DISPLAY_NAME" /></li>
</ul>
</xsl:otherwise>
</xsl:choose>
</li>
</xsl:template>
<div id="navigator">
<ul>
<li class="isFolder isExpanded">
XYZ CORP HR TIME SELF SERVICE
<ul>
<li class="isFolder isExpanded">
Time
<ul>
<li><a href="#" target="_tab">Create Timecard</a></li>
<li><a href="#" target="_tab">Recent Timecards</a></li>
<li><a href="#" target="_tab">Templates</a></li>
<li><a href="#" target="_tab">Timecard Search</a></li>
</ul>
</li>
</ul>
</li>
<li class="isFolder isExpanded">
XYZ CORP EXP ENTRY
<ul>
<li><a href="#" target="_tab">Expense Home</a></li>
</ul>
</li>
<li class="isFolder isExpanded">
XYZ HR EMP SELF SERVICE
<ul>
<li><a href="#" target="_tab">Accommodation Request</a></li>
<li><a href="#" target="_tab">Additional Personal Information</a></li>
<li><a href="#" target="_tab">All Actions Awaiting Your Attention</a></li>
<li><a href="#" target="_tab">Appraisals</a></li>
</ul>
</li>
</ul>
</div>
<xsl:key name="primary" match="Row" use="@PRIMARY_FOLDER" />
首先,选择每个PRIMARY\u文件夹第一次出现的行
<xsl:for-each select="$rows[generate-id() = generate-id(key('primary', @PRIMARY_FOLDER)[1])]">
唯一的额外工作是,根据是否填充了SECONDARY\u文件夹
,您的行为略有不同。不过,您可以使用两个单独的模板来实现这一点
尝试以下XSLT:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="html" indent="yes" />
<xsl:key name="primary" match="Row" use="@PRIMARY_FOLDER" />
<xsl:key name="secondary" match="Row" use="concat(@PRIMARY_FOLDER, '|', @SECONDARY_FOLDER)" />
<xsl:variable name="rows" select="//Row" />
<xsl:template match="/">
<ul>
<xsl:for-each select="$rows[generate-id() = generate-id(key('primary', @PRIMARY_FOLDER)[1])]">
<li class="isFolder isExpanded">
<xsl:value-of select="@PRIMARY_FOLDER" />
<xsl:apply-templates select="key('primary', @PRIMARY_FOLDER)[generate-id() = generate-id(key('secondary', concat(@PRIMARY_FOLDER, '|', @SECONDARY_FOLDER))[1])]" mode="secondary" />
</li>
</xsl:for-each>
</ul>
</xsl:template>
<xsl:template match="Row[@SECONDARY_FOLDER != '']" mode="secondary">
<li class="isFolder isExpanded">
<xsl:value-of select="@SECONDARY_FOLDER" />
<ul>
<xsl:apply-templates select="key('secondary', concat(@PRIMARY_FOLDER, '|', @SECONDARY_FOLDER))" />
</ul>
</li>
</xsl:template>
<xsl:template match="Row" mode="secondary">
<xsl:apply-templates select="key('primary', @PRIMARY_FOLDER)" />
</xsl:template>
<xsl:template match="Row">
<li>
<a href="#" target="_tab">
<xsl:value-of select="@MENU_DISPLAY_NAME" />
</a>
</li>
</xsl:template>
</xsl:stylesheet>
-
请在中查看此操作
注意,如果您的实际XML具有名称空间,则需要修改XSLT以将其考虑在内。您可以向我们展示您的XSLT代码吗?@JEY-Sure已更新。Muenchian分组是我应该看到的吗?有人能帮我吗?确实这是你最好的机会,或者如果您使用xslt2,您可以为每个groupSharePoint使用.NET集成XSLT实现,因此它仅限于XSLT1.0。