XSLT1.0中xml节点的分组

输入：

输入XML

<Root>
    <Number>1</Number>
    <Reference>100</Reference>

    <Number>2</Number>
    <Reference>101</Reference>

    <Number>3</Number>
    <Reference>100</Reference>

    <Number>4</Number>
    <Reference>102</Reference>

    <Number>5</Number>
    <Reference>100</Reference>
</Root>

1.
100
2.
101
3.
100
4.
102
5.
100

预期产出：

<Root>
    <Number>1</Number>
    <Reference>100</Reference>
    <RefNumber>1</RefNumber>

    <Number>2</Number>
    <Reference>101</Reference>
    <RefNumber>1</RefNumber>

    <Number>3</Number>
    <Reference>100</Reference>
    <RefNumber>2</RefNumber>

    <Number>4</Number>
    <Reference>102</Reference>
    <RefNumber>1</RefNumber>

    <Number>5</Number>
    <Reference>100</Reference>
    <RefNumber>3</RefNumber>
</Root>

1.
100
1.
2.
101
1.
3.
100
2.
4.
102
1.
5.
100
3.

在XSLT1.0中，如何基于根/引用进行分组，并向输出中的RefNumber添加序号

---

提前感谢

一种方法是使用xsl:number。每当您匹配一个参考元素时，请复制该元素，并添加一个参考编号元素，该元素的参考元素数量具有相同的值：

<xsl:template match="Reference">
    <xsl:copy-of select="." />
    <xsl:variable name="Ref" select="." />
    <RefNumber><xsl:number count="Reference[. = $Ref]" /></RefNumber>
</xsl:template>

这是完整的XSLT

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="xml" indent="yes"/>

    <xsl:template match="Reference">
        <xsl:copy-of select="." />
        <xsl:variable name="Ref" select="." />
        <RefNumber><xsl:number count="Reference[. = $Ref]" /></RefNumber>
    </xsl:template>

    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
    </xsl:template>
</xsl:stylesheet>

应用于示例XML时，将输出以下内容：

<Root>
    <Number>1</Number>
    <Reference>100</Reference>
    <RefNumber>1</RefNumber>

    <Number>2</Number>
    <Reference>101</Reference>
    <RefNumber>1</RefNumber>

    <Number>3</Number>
    <Reference>100</Reference>
    <RefNumber>2</RefNumber>

    <Number>4</Number>
    <Reference>102</Reference>
    <RefNumber>1</RefNumber>

    <Number>5</Number>
    <Reference>100</Reference>
    <RefNumber>3</RefNumber>
</Root>

1.
100
1.
2.
101
1.
3.
100
2.
4.
102
1.
5.
100
3.

---

请注意使用标识转换模板复制其他现有节点。

一种方法是使用xsl:number。每当您匹配一个参考元素时，请复制该元素，并添加一个参考编号元素，该元素的参考元素数量具有相同的值：

<xsl:template match="Reference">
    <xsl:copy-of select="." />
    <xsl:variable name="Ref" select="." />
    <RefNumber><xsl:number count="Reference[. = $Ref]" /></RefNumber>
</xsl:template>

这是完整的XSLT

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="xml" indent="yes"/>

    <xsl:template match="Reference">
        <xsl:copy-of select="." />
        <xsl:variable name="Ref" select="." />
        <RefNumber><xsl:number count="Reference[. = $Ref]" /></RefNumber>
    </xsl:template>

    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
    </xsl:template>
</xsl:stylesheet>

应用于示例XML时，将输出以下内容：

<Root>
    <Number>1</Number>
    <Reference>100</Reference>
    <RefNumber>1</RefNumber>

    <Number>2</Number>
    <Reference>101</Reference>
    <RefNumber>1</RefNumber>

    <Number>3</Number>
    <Reference>100</Reference>
    <RefNumber>2</RefNumber>

    <Number>4</Number>
    <Reference>102</Reference>
    <RefNumber>1</RefNumber>

    <Number>5</Number>
    <Reference>100</Reference>
    <RefNumber>3</RefNumber>
</Root>

1.
100
1.
2.
101
1.
3.
100
2.
4.
102
1.
5.
100
3.

---

请注意使用标识转换模板复制其他现有节点。

Hi..这是用于分组的序列号..如参考=100它是1,2,3[即出现100的序列号]Hi..这是用于分组的序列号..如参考=100它是1,2,3[即出现100的序列号]